Determine the period of revolution of an artificial satellite in a circular orbit of altitude 350 km.

A)
1.266 hrs
B)
1.395 hrs
C)
1.525 hrs
D)
1.738 hrs

Correct Answer :   1.525 hrs


Explanation : T=2π(R0+h)3/2/√μ
= 2×3.14x(6728000)3/2/(3.986×1014)
= 1.525 hrs.