Correct Answer : Weathering → transportation → deposition → upheaval
Correct Answer : All of the above
Explanation : * Illites do not swell when wet* Illite bond is weaker than Kaolinite bond* Illite bond is stronger than montmorillonite bond* Illites are composed of two silica tetrahedralsheets with a central octahedral sheet
Correct Answer : Black cotton soil
Correct Answer : solids, water and air
Explanation : Solids and water, solids and air are two-phase systems. Sand, gravel and air are not the phases. Solids, water and air are considered to be a three-phase system of the soil mass.
Correct Answer : 20.4 kN/m³
Explanation : Dry unit weight γd = 17 kN/m³Water content w = 20% = 0.2Bulk unit weight γ = γd *(1+w)γ = 17*(1+0.2)γ = 20.4 kN/m³.
Correct Answer : are of spongy nature
Correct Answer : True
Explanation : The density index is used to express the relative compactness or degree of compaction of a natural cohesion-less soil deposit. It is also known as relative density or degree of density.
Correct Answer : 1.0 to 3.0
Correct Answer : 18.535 kN/m³
Explanation : Porosity n=30%=0.3Specific gravity G=2.7Voids ratio e = n / (1-n)e=0.3/(1-0.3)=0.429Dry unit weight γd = Gγw/(1-e)γd=(2.7*9.81)/(11+0.429)γd=18.535 kN/m³
Correct Answer : homogenous soils
Correct Answer : rectangular
Explanation : When the sphere centres form a rectangular space lattice, then they form a packing known as cubic packing, wherein each sphere is in contact with six surrounding neighbouring spheres.
Correct Answer : 20%
Explanation : * Illites* Kaolinites .* Montomorillonite* Vermiculite
Correct Answer : sky scrapper buildings
Correct Answer : the volume of air and volume of water
Explanation : The voids in soil mass are occupied by air and water. Hence, the volume of voids equals to the volume of air and volume of water.
Correct Answer : block diagram
Explanation : It is always convenient to show the constituents occupying separate spaces as blocks. In the phase diagram, the soil occupies the bottom position. Water and air occupy the middle and top positions.
Correct Answer : left side
Explanation : Volumes are represented on the left side whereas weights are represented on the right side of the block diagram.
Correct Answer : 80°C
Correct Answer : under-consolidated
Correct Answer : 1
Correct Answer : 0.861
Correct Answer : 0.75
Correct Answer : alluvial
Correct Answer : 15-35
Explanation :
Correct Answer : 5° to 20°
Correct Answer : 0.247
Explanation : Degree of saturation S=1Specific gravity G=2.7Voids ratio e = (W*G)/S = Wsat*GWsat = e/GWsat = 0.667/2.7Wsat = 0.247.
Correct Answer : angular-grained dense sand
Correct Answer : 47.64%
Explanation : Consider a unit cube of soil having spherical particles of diameter d.Volume of each spherical particle = (π/6)d³Total volume of container = 1*1*1=1No. of solids in the container = (1/d)*(1/d)*(1/d)=(1/d³)Volume of the solids Vs = (π/6)*d³*(1/d³)=(π/6)Volume of the voids Vv = 1-(π/6)Voids ratio e = (1-(π/6))/(π/6)Porosity n = e/(1+e) = 0.9099/(+0.9099) = 0.4764In percentage, n = 47.64%.
Correct Answer : 160 years
Correct Answer : net ultimate bearing capacity
Correct Answer : Wd
Explanation : The weights of Water, air and total weight are represented as Ww, Wa and W. The weight of solids is represented as Wd or Ws in the phase diagram.
Correct Answer : Ww+Wd
Explanation : The sum of the weight of voids Wv and weight of solid is the total weight. The weight of total voids is equal to the weight of Water and weight of air. Since the weight of air is considered to be negligible, the weight of total voids is equal to the weight of Water. Therefore, the total weight of the moist sample is the sum of Ww+Wd.
Wv
Ww+Wd
Correct Answer : natural water content minus its plastic limit to its plasticity index
Correct Answer : In pipette analysis, weight Wd per ml of suspension is found directly
Correct Answer : parabolic
Correct Answer : confining pressure
Correct Answer : sodium-hexametaphosphate 33 g, sodium carbonate 7 g and distilled water one litre
Correct Answer : plastic and also compressible
Explanation : Porosity n = 40% = 0.4Air content ac = 50% = 0.5Percentage air voids na= n*acna = 0..4*0.5na = 20%.
Correct Answer : 19.5 kN/m³
Explanation : Voids ratio e = 0.6Specific gravity G = 2.65Saturated unit weight γsat = (G+e) γw/ (1+e)γsat = (2.65+0.6)*9.81/(1+0.6)γsat= 19.927 N/m3.
Correct Answer : 2
Correct Answer : 90°
Explanation : The soil will have maximum possible voids when the soil grains are arranged in a cubical array of spheres. In a cubical array, the angle of orientation α = 90°.
Correct Answer : n = 1-[π/(6*(1-cosα)*(√(1-2cosα))]
Explanation : The formula was given by Slichter. In an intermediate packing, the centres of any 8 spheres, originally arranged in a cubic packing form the corners of the rhombohedron, with an acute face angle α.
Correct Answer : π/6
Explanation : Consider a unit cell,Volume of each spherical particle = (π/6)*d³Total volume of container=1*1*1=1No. of solids in the container=(1/d)*(1/d)*(1/d)=(1/d³)Volume of the solids Vs=(π/6)*d³*(1/d³)=(π/6).
Correct Answer : consolidation
Correct Answer : textural classification
Correct Answer : 3 m to 4 m
Correct Answer : 40 kN
Explanation : Weight of soil sample W=190kNWeight after oven drying Wd=150kNWeight of Water Ww=W-WdWw=190-150Ww=40kN.
Correct Answer : 0.286
Explanation : Volume of Water Va= (1/7) total volume VVolume of Water VW= (1/8) total volume VVolume of voids Vv= Va + VwVv=(1/7)V+(1/8)VVv=(15/56)V=0.268V.
Correct Answer : 1.00
Correct Answer : H/3 above the base parallel to base
Correct Answer : positive hydrostatic pressure
Correct Answer : wind
Correct Answer : greater than total shearing strength
Correct Answer : A soil having pH value less than 7 is an acidic soil
Correct Answer : sand
Correct Answer : 3
Correct Answer : Karl Terzaghi
Explanation : If civil engineering were a game, Karl Terzaghi had a right to lay down the rules—he had invented and established much of the groundwork. Terzhaghi (1883-1963) is one of the leading civil engineers of the 20th century and is widely known as the father of soil mechanics.
Correct Answer : air
Correct Answer : 10.423
Explanation : Voids ratio e=0.6Specific gravity G=2.7Submerged unit weight Y’ = (G -1) Yw/ (1+e)Y’ = (2.7-1)*9.81/(1+0.6)Y’ = 10.423 kN/m³.
Explanation : * size of the particles* shape of the particles* cohesive properties of particles* internal frictional resistance of particles
Correct Answer : As the test progresses the area under shear, gradually changes
Correct Answer : 12
Explanation : In the densest state of packing, sphere centres form a rhombohedral array with face angle α=60°. Thus, each sphere is in contact with 12 neighbouring spheres.
Correct Answer : 0.7071
Explanation : The total volume of rhombohedron is given by,V = (1-cosα)*(√(1+2cosα))V = (1-cos60°)*(√(1+2 cos60°))V = 0.7071.
Correct Answer : 0.35
Explanation : Consider a unit cube of soil having spherical particles of diameter d.Volume of the solids Vs= (π/6)=0.5236The total volume V=(1-cosα)*(√(1+2cosα))Minimum void ratio is possible in densest state with α=60°∴ V=(1-cos60°)*(√(1+2cos60°))V=0.7071Volume of the voids Vv=V-Vs=0.7071-0.5236Vv=0.1835Voids ratio e= Vv/ Vs=0.1835/0.5236∴ e=0.35.
Correct Answer : 0.3895
Explanation : α=75°The total volume V=(1-cosα)*(√(1+2cosα))∴ V=(1-cos75°)*(√(1+2cos75°))V=0.9131Volume of the solids Vs=(π/6)=0.5236Volume of the voids Vv=V-Vs=0.9131-0.5236Vv=0.3895.
Correct Answer : 3.0
Correct Answer : shrinkage limit
Correct Answer : 1.47
Correct Answer : 2.6
Correct Answer : pipette
Explanation : The pipette method is the standard sedimentation method used in laboratory for wet mechanical or sedimentation analysis.
Correct Answer : 24
Explanation : For complete drying, sandy soil takes about 4 hours and fat clays take about 14 to 16 hours. To assure complete drying of sample, it is kept for about 24 hours.
Correct Answer : 10 cm
Explanation : The sampling depth (h) in hydrometer method is taken as 10 cm.
Correct Answer : RH
Explanation : The reducing reading is designated as RH, which is used for calibration of hydrometer.
Correct Answer : specific gravity
Correct Answer : Both (B) and (C)
Correct Answer : Plasticity
Explanation : Plasticity is the property of a soil which allows it to be deformed rapidly, without rupture, without elastic rebound and without volume change.
Correct Answer : Consistency index
Explanation : consistency index or relative consistency is defined as the ratio of liquid limit, minus the natural water content to the plasticity index of the soil.
Correct Answer : Loose bulky grains hold together by capillary stresses
Explanation : A common feature of collapsible soil is the loose bulky grain held together by capillary stresses.
Correct Answer : Holtz and Gibbs
Explanation : In 1967, Holtz and Gibbs provide guidance for identifying the potential collapsible soil in arid and semi-arid regions.
Correct Answer : No problem
Explanation : The severity of the problem will be zero, if the CP value lies between 0-1 percent.
Correct Answer : 27°C
Correct Answer : clay
Correct Answer : 45° + half of the angle of shearing resistance
Correct Answer : 25.0 m
Correct Answer : Total surface area in a unit mass
Explanation : Specific surface is usually defined as the total surface area of the soil particle in a unit mass.
Correct Answer : Decreases
Explanation : The subdivision of a mass yields greater surface area than the same mass itself. The specific surface of a mass increases as the grain size decreases.
Correct Answer : Grain shape
Explanation : Specific surface varies for different shapes of particle having the same mass. Hence grain shape is important factor for determining specific surface.
Correct Answer : Textural classification
Explanation : Soil classification of composite soils exclusively based on the particle size distribution is known as textural classification.
Correct Answer : Triangular classification of U.S. public road administration
Explanation : Triangular classification of U.S. public road administration is a commonly used system for textural classification.
Correct Answer : down at the centre
Correct Answer : head loss to the length of the seepage
Correct Answer : Casagrande
Explanation : In 1940, casagrande originally developed the unified soil classification system (USCS).
Correct Answer : Air field construction
Explanation : In the earlier stages of World War 2, the USCS system was used for air field construction.
Explanation : According to USCS the fine grained soils, whose behavior is controlled by plasticity, are classified on the basis of their plasticity.
Correct Answer : drained test
Correct Answer : 95.7%
Correct Answer : 1959
Explanation : The Indian standard classification system (ISCS) was first developed in 1959 and revised in 1970.
Explanation : Fine grained soil are subdivided into 3 types : * Inorganic silts and very fine sands* Inorganic clays* Organic silts and clay and organic matter.
Correct Answer : 18 groups
Explanation : The ISCS classifies the soil into 18 groups as against 15 groups of USCS.
Explanation : * seepage* exit gradient* hydrostatic pressure* seepage pressure
Correct Answer : stess taken up by the pore water
Correct Answer : 75%
Correct Answer : 80%
Correct Answer : 1.25
Explaination : Coeff.compressibility = Coeff.volume change/(1 + e).(1 + e) = Coeff.volume change/Coeff.compressibility.e = (Coeff.volume change/Coeff.compressibility) - 1.e = ((6.75 x 10⁻²)/(3 x 10⁻²)) - 1.e = 2.25 - 1.e = 1.25.
Correct Answer : tan² (45° + φ)
Correct Answer : Elasticity of soils
Correct Answer : 60°
Explanation : For organic soils like peat, a lower temperature of about 60° is preferable to prevent the oxidation of the organic matter.
Correct Answer : Calcium carbide
Explanation : Calcium carbide method is very quick as the result can be obtained in 5 – 10 minutes. The field kit contains the moisture tester, a small single – pan weighing balance, a bottle containing calcium carbide and a brush.
Correct Answer : acetylene
Explanation : The acetylene gas is produced by the reaction of moisture of soil and the calcium carbide. The gas exerts pressure on a sensitive diaphragm attached to a dial gauge which reads the water content.
Correct Answer : Negative
Explanation : The addition of dispersing agent in water increases its water level, therefore the dispersing correction is always negative.
Correct Answer : Taking the observation
Explanation : In sedimentation analysis the hydrometer method differs from the pipette method in the method of taking the observation.
Correct Answer : Always positive
Explanation : The actual reading to be taken at water level will be more; hence the meniscus correction will be always positive.
Correct Answer : R = Rh’ + Cm ± CL – Cd
Explanation : According to the derived equation of hydrometer the equation isR = Rh’ + Cm ± CL – Cd.
Correct Answer : R=Rh’ + C
Explanation : The three corrections Cm, CL, Cd can be combined into one corrections Cm and the equation can be written as R = Rh’ + Cm.
Correct Answer : 2.0 g/cm³
Correct Answer : shape, size and weight of grain
Correct Answer : clay soils
Correct Answer : strain to stress
Correct Answer : IC = WL-W/IP
Explanation : The consistency or relative density is defined as ratio of liquid limit, minus the natural water content to the plasticity index of the soil IC = WL-W/IP.
Correct Answer : WS
Explanation : Shrinkage limit is represented as WS.
Correct Answer : Atterberg
Explanation : In 1911, Atterberg who was a Swedish Agriculturist divided the entire range of liquid to solid state in to four stages.
Correct Answer : Semi-arid regions and Arid regions
Explanation : Since collapsible soil exhibit loose, weakly cemented sands they are usually present in arid and semi- arid regions.
Correct Answer : Coulomb
Correct Answer : pycnometer
Correct Answer : 64%
Correct Answer : Directly proportional to electric force
Explanation : The electrical force responsible for inter-particle effect is proportional to the specific surface.
Correct Answer : kozney’s method
Explanation : The harmonic diameter DH can be found by using kozney’s method using the formula : F=6/ρs×1/Dn.
Correct Answer : Coarse grained soil
Explanation : Since the textural classification is based on the percentages of sand, silt, and clay size making up the soil. Such a classification is more suitable for describing coarse-grained soil.
Correct Answer : Parallel to the three sides of the triangle
Explanation : To use the textural classification chart, for a given percentage of three constituents forming a soil, lines are drawn parallel to three sides of the equilateral triangle.
Correct Answer : safe bearing capacity
Correct Answer : unified soil classification system
Correct Answer : a semi-ellipse
Correct Answer : moves away from the backfill
Correct Answer : 50% of the soil
Explanation : If more than 50 % of the soil is retained on a NO.200 US sieve (0.075), it is designated as coarse grained soil.
Correct Answer : GW-GM and SP-SM
Explanation : If the percentage of fines lies between 5 to 12 %, coarse grained soils are designated by dual symbols GW-GM or SP-SM.
Correct Answer : Silt and clay
Correct Answer : a circular arc
Correct Answer : Df > 1
Correct Answer : 20
Correct Answer : IP=0.73(WL-20)
Explanation : The A-line, dividing the inorganic clay from silt and organic soil has the equation: IP=0.73(WL-20).
Correct Answer : Clayey gravel
Explanation : As per Indian standards of group symbols and typical names, G-refers to gravel and C-refers to clay.
Explanation : For a soil component to be a boulder, size range must be of average diameter more than 30cm and shape of round to angular and bulky hard.
Correct Answer : 33331
Correct Answer : 6 t/m²
Correct Answer : decrease their shear strength
Correct Answer : gravitational force
Correct Answer : 0.95
Correct Answer : 0.01
Correct Answer : load at which soil fails
Correct Answer : 84%
Correct Answer : major principal plane
Correct Answer : 0.002 mm
Correct Answer : radiation
Explanation : The radiation method consists of 2 steel casings. A device containing some radio–active isotope is lowered in one caning and a detector in another. The neutrons emitted by the device are detected by the detector and the loss of energy of neutrons is equated to the water content.
Correct Answer : Opaque
Explanation : Since the density of the soil suspension is high, the visibility will be opaque.
Correct Answer : 1000
Explanation : The quantity of dry soil and dispersing agent is taken as double of pipette which is 500 ml.
Correct Answer : Grams
Explanation : since the soil is weighed in terms of mass, the volume is taken in terms of grams.
Correct Answer : toe failure
Correct Answer : weight of water to weight of solids of given mass of soil
Correct Answer : oven-drying method
Correct Answer : Solid limit
Explanation : Liquid limit, plastic limit, shrinkage limit are useful for engineering purpose.
Correct Answer : Electro-magnetic charges
Correct Answer : Kerosene
Explanation : According to Goldschmidt theory, the clay does not become plastic when mixed with liquids of non-polarizing agents like kerosene.
Correct Answer : Capillary stress
Explanation : As the common Feature exhibited by collapsible soil is capillary stress, the loose bulky grains in the soil are held together by it.
Correct Answer : Degree of saturation
Explanation : Collapsible potential varies with degree of saturation, at an overburden pressure of Po.
Correct Answer : hydroscopic water
Correct Answer : 0.2275 cm/sec
Correct Answer : increases with an increase in the liquid limit
Correct Answer : Physical properties of the soil
Explanation : As specific surface is associated with surface characteristics of a particle, therefore it is related with physical properties.
Correct Answer : Larger specific surface
Explanation : As the specific surface increases as the size of the grain decreases. Therefore Microscopic particles have a large specific surface.
Correct Answer : Surface area of the particle per unit volume
Explanation : From the expression, specific surface = surface area of particle/volume of the particle, it can be seen that specific surface is the surface area of a particle.
Correct Answer : Equilateral triangle
Explanation : A triangle, having equal length of sides (i.e. Equilateral triangle) is used in textural classification chart.
Correct Answer : Particle-size composition and Plasticity characteristics
Explanation : HRB classification system, also known as public road administration (PRA) is based on both the particle-size composition and plasticity characteristics.
Correct Answer : Public road administration (PRA) system
Explanation : Highway research board classification system is also known as public road administration (PRA) system.
Correct Answer : 25 mm
Correct Answer : Shrinkage limit
Correct Answer : Both (A) and (B)
Correct Answer : 2.0
Correct Answer : 0.60
Correct Answer : flow lines and equipotential lines cross each other at right angles
Correct Answer : degree of saturation
Correct Answer : Liquid limit and Plasticity index
Explanation : Based on the liquid limit and plasticity index, fine grained soil is subdivided.
Correct Answer : Gravel and sand
Explanation : Based on the soil size, coarse grained soil is divided in to gravel and sand.
Correct Answer : Relative suitability
Explanation : In Casagrande’s plasticity chart, the numbers denote relative suitability with No.1 as the best and No.10 as the worst.
Correct Answer : it can be performed under all three driange conditions with complete control
Correct Answer : temperature, meniscus and dispersing agent corrections
Correct Answer : depends upon the force responsible
Explanation : * back fill is dry, cohesionless, homogeneous and isotropic* slip surface is the plane which passes through the heel of the wall* position and direction of the resultant earth pressure, are known* sliding wedge itself acts as a rigid body and the value of earth pressure is obtained by considering the limiting equilibrium of the wedge
Correct Answer : 0.375
Correct Answer : equal to a fill of height Z equal to q/r, where r is the density of the backfill
Correct Answer : 27°c
Explanation : The hydrometer are generally calibrated at 27°c if the temperature is more than 27°c, temperature correction will be taken negative. If less than 27°c then the temperature correction will be positive.
Correct Answer : down and outwards on a slip surface
Correct Answer : D₁₀
Correct Answer : Illite group
Correct Answer : void ratio
Correct Answer : 92%
Correct Answer : Per cent water content
Correct Answer : Gaseous state
Correct Answer : 4.44
Explanation : Sensitivity,St = QU(undistributed)/QU(distributed)=240/54=4.44.
Correct Answer : First saturation
Explanation : As there is a sudden compression of the soil under pressure, the structural collapse occurs upon first saturation.
Correct Answer : 24 x 10⁻⁵ m³/sec
Explanation : * stress distribution on the failure plane, is uniform* it can be performed under all three drainage conditions* precise measurement of the pore pressure and volume change during the test is possible* state of stress within the specimen during any stage of the test as well as at failure, is completely determined
Correct Answer : 105° to 110°C
Correct Answer : degree of consolidation
Correct Answer : stratified soils
Correct Answer : 18.2%
Correct Answer : Specific surface of the soil particle
Explanation : Permeability of soil greatly depends on the specific surface of the soil because of the viscous effects associated with surface characteristics of the grains.
Correct Answer : Surface area
Explanation : The chemical activity of the clay mineral depends upon the surface area, because of the electrical charge of clay minerals is high per unit mass.
Correct Answer : 7 primary groups
Explanation : Based on HRB system, the soil is divided into 7 primary groups, designated as A-1, A-2…A-7.
Correct Answer : Group index
Explanation : As group index is a mean of rating the value of soil as a sub-grade material. It can be used for finding the performance and quality of the soil.
Correct Answer : GI=0.2a+0.005ac+0.001bd
Explanation : Group index (GI) is given by the following equation :GI = 0.2a+0.005ac+0.01bd.
Correct Answer : 0.0002 mm
Correct Answer : directional angles
Correct Answer : minor principal stress is vertical
Correct Answer : major principal stress is vertical
Correct Answer : 2.65
Correct Answer : more than 1
Correct Answer : bored piles
Correct Answer : proportional to the internal friction of the soil
Correct Answer : is more in well compacted clays
Correct Answer : consolidated undrained test
Correct Answer : liquid limit
Correct Answer : possess high coefficient of internal coefficient
Correct Answer : 2.50
Correct Answer : glaciated water
Correct Answer : liquid limit minus the natural water content to the plasticity index of the soil
Correct Answer : cohesion
Correct Answer : H²
Correct Answer : 1.08
Correct Answer : unconfined compression test
Correct Answer : 0.188
Correct Answer : 2.72
Correct Answer : it is on the verge of failure
Correct Answer : 0.862
Correct Answer : 65%
Correct Answer : 10 tonnes
Correct Answer : 45°
Correct Answer : tan² (45° - φ/2)
Correct Answer : minus unit weight of water
Correct Answer : three phase soil
Explanation : * is proportional to the cohesion of the soil* is generally known as the strength of the soil* increases with an increase in the normal stress* is proportional to the tangent of the angle of internal friction
Correct Answer : permeability
Correct Answer : water content
Correct Answer : perpendicular to equipotential lines
Correct Answer : plasticity