Correct Answer : High lift device
Explanation : High lift devices are not part of aircraft propulsion system. High lift device is used to increase lift produced. Flaps are an example of high lift device which are used at takeoff and landing.
Correct Answer : Longerons
Explanation : Longerons are structural elements of an aircraft. Longerons are heavy structural members that run straight and used to prevent bending.
Correct Answer : Cheap and low fuel consumption
Explanation : Piston prop engine are widely used during early era. Piston prop engine provides cheap and low fuel consumption. Piston prop engine suffers from speed limits.
Correct Answer : Centrifugal compressor
Explanation : Centrifugal Compressor is type of compressor. Centrifugal compressor uses centrifugal force to fling the air. Flow does not coincide with axis of rotation. Flap is secondary control surface of an aircraft.
Correct Answer : Generate work to drive shaft
Explanation : Turbine is an essential component of gas turbine engine. Turbine is used to decrease temperature and pressure of the gas. Combustion products pressure is reduced by turbine. Turbine generates work to drive the shaft.
Correct Answer : piston prop
Explaination : Piston prop engine is shown in above diagram. A typical piston prop engine relies piston and propeller blades to generate useful work and thrust. They are heavy and produces more noise.
Correct Answer : turbojet engine with centrifugal compressor
Explaination : A typical Turbojet with centrifugal compressor is shown in above schematic diagram. Centrifugal force is used as working principle to drive this type of compressor. As shown in figure, it consists of combustion chamber and turbine stage as well.
Correct Answer : typical turbo jet
Explaination : As shown in figure, a typical Turbojet engine is shown. Here, turbojet engine is operated by axial flow Compressor as shown in the above schematic diagram. As air passes through Compressor, pressure will increase and then it will be directed to combustion and preceding stages.
Correct Answer : turboprop
Explaination : A turboprop is different from traditional piston prop engine. Here, propeller is connected to turbine engine via gear box. Rocket is type of aircraft and spacecraft propulsion system.
Correct Answer : turbofan
Explaination : A typical turbofan engine is shown in the above diagram. Turbofan operates with same principle as other has turbine engine. However, it has a fan mounted at inlet as shown. Fuel Efficiency of such engine is more than typical Turbojet.
Correct Answer : ratio of thrust required by rubber engine to the actual thrust from selected existing engine
Explanation : For a typical rubber engine, scale factor is defined as ratio of thrust required by rubber engine to the actual thrust from selected existing engine. Scale factor can vary based on our requirements. Lift to drag ratio is primarily concern of aerodynamics of aircraft.
Correct Answer : 2.28 unit
Explaination : Given, actual length Lactual = 2.5unit, S.F. = 0.8Approximate length is given by,Length L = Lactual*(SF) 0.4Length L = 2.5*(0.8) 0.4 = 2.28 unit.
Correct Answer : 112.35 in
Explanation : Given, diameter d = 94 inch, S.F. = 0.7Now, actual diameter is given by,Actual diameter D = d / (SF)0.5 = 94 / (2.7)0.5 = 112.35in.
Correct Answer : Clean airflow
Explanation : The nose inlet offers clean air flow. It was used in some fighters such as Mig 21. This type of inlet requires long internal duct which is one of the disadvantages of nose inlet. They are typically located at the nose section of an aircraft.
Correct Answer : foreign object ingestion problem
Explanation : Chin inlet is good at operating higher AOA. They offers advantages similar to nose but required duct length is shorter. One of the disadvantage of this type is foreign object ingestion. This good affect the performance of engine as well.
Correct Answer : shock separated flow outside of the inlet
Explanation : Engine performance is influenced by cowl lip radius. A large cowl lip radius will produce shock separated flow on the outside of an inlet. Large cowl lip will reduce distortions. This is very helpful at higher AOA.
Correct Answer : inlet applicability
Explaination : Typical inlet application limits based on Mach number is shown in the diagram. Above diagram is illustrating the selection criteria. This criteria is presented for different types of inlets based upon designed Mach values.
Correct Answer : 0.556
Explanation : Given, BPR =1.5Maximum thrust SFC = 0.67*e(-0.12*BPR) = 0.67* e(-0.12*1.5) = 0.556.
Correct Answer : 0.8164
Explanation : Given, ratio of rubber engine weight (w) and actual engine weight (W) = 0.8Now, weight of the rubber engine is given by, w = W * SF1.1Hence, SF1.1 = w/W = 0.81.1*ln (SF) = ln0.8 = -0.223Hence, ln (SF) = -0.223/1.1 = -0.2028Hence, SF = e-0.2028 = 0.8164.
Correct Answer : Slow down the incoming air
Explanation : One of the primary function of emulate is to reduce velocity of incoming air. Lift produced by wings can be increased with the help of high lift device such as flaps. Lift curve slope can be altered by using different angle of attacks.
Correct Answer : total pressure deliver to the engine divided by freestream total pressure
Explanation : Inlet pressure recovery is nothing but the total pressure which is deliver to the engine divided by the free stream total pressure. Dynamic pressure is exerted due to velocity of the fluid. Lift drag ratio is more important for the aerodynamics of the aircraft.
Correct Answer : NACA flush inlet
Explanation : Inlet has primary function to reduce flow velocity of the incoming air. NACA flush inlet is one of the example of typical inlet profile. Flap and slat are secondary control surfaces. Gisele is main body of an aircraft.
Explaination : A typical NACA flush inlet is shown in the above diagram. NACA flush inlet was used by several early jets but in modern days it is rarely used. NACA flush inlet can be used to reduce wetted area.
Correct Answer : Pitot inlet
Explaination : The typical schematic diagram of pitot inlet is shown in above figure. A Pitot inlet is nothing but a simple forward facing hole. This inlet works well at typical low supersonic speed regimes.
Correct Answer : 2D ramp inlet
Explaination : A typical schematic diagram of 2d ramp is shown in above figure. 2d ramp inlet is used for supersonic speed regimes. It uses flow over wedge concept. Conical Inlet is also termed as round inlet. NACA flush inlet was used by early jets.
Correct Answer : Mixed isentropic compression inlet
Explaination : As shown in figure a mixed isentropic compression inlet is shown. As shown in the diagram, it uses both internal and external compressions. This can lead to higher efficiency. Expansion is the reverse or opposite process of compression.
Correct Answer : 114.67 unit
Explanation : Given, Thrust T = 150000 unit, BPR = 0.7.Now, Diameter D is given by, D = 0.288*T0.5*e 0.04*BPR = 0.288*1500000.5*e0.04*0.7Hence, D = 0.288*387.3*1.028 = 114.67 unit.
Correct Answer : Side inlet location of buried engine
Explanation : Here, typical side inlet location of buried engine is shown. Tail root engine is located at root section of the tail. Lofting is mathematical modelling of aircraft components. It is an important step in aircraft design. Chin buried is similar to that of the nose inlet section. Chin inlet suffers from various drawbacks such as ingestion of foreign objects etc.
Correct Answer : Boundary layer suction
Explanation : Boundary layer suction is one of the type of the boundary layer diverter. Here, the boundary layer air is removed with the help of suction. It doesn’t benefit from the ram impact. Power loading is related to propulsion system performance.
Correct Answer : Boundary layer bypass duct
Explanation : A boundary layer bypass duct or simply a separate inlet duct is one of example of boundary layer diverter. Fuselage fineness ratio is defined as ratio of fuselage length to the maximum diameter. Thrust loading is ratio of Thrust to weight. Power loading ratio of weight and power.
Correct Answer : Step diverter
Explanation : Boundary layer diverter is used to divert the boundary layer formed typically on the body. Step diverter, BL bypass duct and BL suction are some of the techniques used for this purpose. Flap is an example of high lift device.
Correct Answer : 1.045
Explanation : Given, Mach number M = 0.7Now, for Mach number 0.7 area ratio is 1.094.Now, diameter ratio is given by,Diameter ratio = (area ratio)0.5 = 1.0940.5 = 1.045.
Correct Answer : chin inlet
Explaination : A typical chin inlet arrangement is shown in the diagram. When inlet is located at tip of the wing then, it is termed as wing tip inlet. Chin inlet are similar to that of the nose inlets.
Correct Answer : armpit inlet
Explaination : The above diagram is representing the typical armpit inlet location. This type of inlet is risky. This can be used to have short internal duct. Lift curve is curve representing lift variations.
Correct Answer : wing root inlet
Explaination : A typical wing root inlet can be seen in the above diagram. Nose inlet is located at nose section of the aircraft which can offer clearer airflow. Chin is similar to nose inlet with some fundamental modification. Armpit inlet location is considered to be risky.
Correct Answer : typical Podded engine
Explaination : A typical Podded engine configuration is shown in the above diagram. Buried engines are located inside aircraft body itself. Nose buried engine and side buried engine are typical example of buried engine arrangements.
Correct Answer : tail podded engine
Explaination : As shown in figure, typical tail podded engine is shown. As the name suggests this engine is located at empennage section of the aircraft. Wingtip is located at the tips of wing.
Correct Answer : To expand exhaust flow
Explanation : Function of nozzle is to expand flow. Nozzle is used to increase flow velocity by decreasing pressure and temperature of the flow. Lift is generated by wings primarily. Pressure can be increased by using compressor.
Correct Answer : fixed convergent nozzle
Explaination : A typical convergent nozzle is shown in the above figure. The illustrated fixed convergent nozzle Increases velocity of the flow for subsonic condition. For supersonic expansion divergent section is required.
Correct Answer : increases
Explanation : Given, Mach number = 0.5. The flow is in subsonic speed region.For subsonic speed, as area decreases the flow velocity will increase for convergent nozzle.
Correct Answer : preliminary sizing of capture area
Explaination : Preliminary sizing of capture area is shown in the above diagram. It provides typical guidelines and values to get preliminary sizing of capture area. Drag polar is used to provide relationship between lift and drag.
Correct Answer : 0.68
Explanation : Given, area ratio A/A* = 1.110Now, as we know, A/A* = (1/M)*(1+0.2M2)3*0.5787For given problem, we will substitute different values of Mach number from the options.Let’s consider M = 0.68Hence, for assumed value of Mach number,A/A* = (1/0.68)*(1+0.2*0.682)3*0.5787A/A* = 0.8510*1.092483 = 1.110.The evaluated area ratio is equal to the given area ratio.Hence, correct value of Mach number is 0.68.
Correct Answer : Channel diverter
Explanation : Channel diverter is considered as most common type of boundary layer diverter used for supersonic applications. It offers high performance among the other types. Empennage is tail section of the aircraft.
Correct Answer : over expanded
Explaination : Given, temperature t 200k, density d 1.01 kg/m3Now, exit pressure p = d*R*T = 200*287*1.01 = 57974 = 0.57 bar < 1 barSince exit pressure p < back pressure, the nozzle is over expanded.
Correct Answer : Keep it as long as possible
Explanation : ‘Keep it as long as possible’ is old thumb rule for propeller. However, the length of the propeller is limited by the tip speed. Propeller tip speed should be below sonic speed.
Correct Answer : 1570.8 unit
Explanation : Given, diameter d = 25 unit, n = 1200rpm.Now, static tip speed V = ?*n*d/60 = ?*1200*25/60 = 1570.8 unit.
Correct Answer : 9.167
Explanation : Given, Static tip speed V = 600 ft. per second, n = 1250rpm.Now, diameter d = V*60/π*n = 600*60/π*1250 = 9.167 ft.
Correct Answer : updraft cooling
Explaination : Downdraft and updraft cooling are typical cooling system used in aircraft. Above diagram is representing typical updraft cooling system. Here, in this method cooling air flows in upward direction. It creates more efficient cooling flow than the downdraft cooling.
Correct Answer : 12.60
Explanation : Given, bhp = 3000.Now, ratio of weight to length is given by,W/L = 0.403*(bhp)0.43 = 0.403*30000.43 = 12.60.
Correct Answer : 893.84 lb.
Explanation : Given, bhp = 2500Now, approximate value of weight is given by, W = 1.67*bhp0.803 = 1.67*25000.803 = 893.84 lb.
Correct Answer : Downdraft cooling
Explanation : Downdraft cooling is a typical example of a cooling system which can be used in aircraft. Air flows in downward direction in the downdraft cooling configuration. Lofting is mathematical modelling of skin and aircraft. Circulation is related to vorticity in the flow.
Correct Answer : 82.73 unit
Explanation : Given, power = 200Hp, number of blades = 2Now, diameter d = 22*(Hp)0.25 = 22*(200)0.25 = 82.73 unit.
Correct Answer : fuel tanks, fuel lines, fuel pump, etc
Explanation : Fuel system includes fuel tanks, fuel lines, supply lines, pump, etc. Elevator and rudder are known as primary control surface. Elevator is used for pitch up and pitch down. Rudder provides yaw motion. High lift device is used to increase the amount of lift.
Correct Answer : Flap
Explanation : There are mainly 3 types of fuel tank: discrete, bladder and integral. Flap is not type of fuel tank. Flap is a high lift device. Flap is used to increase lift produced by wings during takeoff and landing.
Correct Answer : typical central fuel tank location
Explaination : Typical fuel tank is shown in the diagram. As shown in the diagram Fuel tank is located at the centre and hence it is a typical central fuel tank. Tip tank will be located at the tip of wing typically.
Correct Answer : Loss of available fuel volume
Explanation : A typical bladder tank is formed by stuffing a shaped rubber bag into a cavity in the aircraft structure. However, the thick rubber bag results in the kids of available fuel volume. Self-sealing property is one of the advantages of the bladder tank. Thrust loading is the ratio of thrust to weight.
Correct Answer : cavities within the aircraft’s airframe itself
Explanation : As name suggests a typical integral tank is an integral part of the aircraft itself. Integral tanks are cavities within the structure of airframe. These cavities are then sealed in order to form a fuel tank. Integral tanks are not external tanks
Correct Answer : inboard section of the wing
Explanation : Typically, main fuel tank is located near to the inboard section of the wing. At tip, tip tanks are placed. Due to safety parameters, one soul avoid placing fuel tanks at the passenger cabin or at the cockpit.