Correct Answer : higher maximum speed
Explanation : Thrust loading is nothing but a ratio. It is the ratio of aircraft thrust to the weight of the aircraft. Higher thrust loading means higher thrust for given weight. This will improve maximum speed of an aircraft.
Correct Answer : Yes
Explanation : Thrust loading and wing loading are one of the crucial parameter of an aircraft design. A designer can find both of them either by estimating thrust loading and then evaluating the wing loading or vice-versa.
Correct Answer : 1.5
Explanation : Given, lift coefficient CL = 2.5, thrust loading T/W = 0.6.Now, thrust loading at cruise is given by,T/W = CD / CL0.6 = CD / 2.5CD = 0.6*2.5 = 1.5.
Correct Answer : 12
Explanation : Given, weight at cruise W = 2275kg, power = 190hp.Hence, power loading = W/hp = 2275/190 = 11.97 = 12.
Correct Answer : 846.15/V
Explanation : Given, prop aircraft, thrust loading T.L. = 0.65Since propeller is idle, propeller efficiency ?=1. Here, velocity is not mentioned so we will substitute it as V.Now, thrust loading is given as,T.L. = T/W = (550*η / V)*(hp/W)Hence, power loading W/hp = PL = 550*η / (T.L.*V) = 550/(V*0.65) = 846.15/V.
Correct Answer : T/W = (550*? / V) * (hp/W)
Explanation : Power is defined as thrust into velocity. Propeller will be operating with some finite value of propeller efficiency ?. 550 we multiply as to make units similar both the side.In general, for prop aircraft thrust loading and power loading is given as,T/W = (550*η / V)*(hp/W)
Correct Answer : greater or equal to one
Explanation : Power loading for propeller driven aircraft is an important parameter representing the relation between power and weight. Power loading will always be greater than one and in much idle case it will be one. It cannot be zero. Lift and drag are forces.
Correct Answer : weight of aircraft to the horsepower by prop engine
Explanation : Power loading will be defined as the ratio of weight of the aircraft to the power; typically horsepower produced by prop engine. It will impact on acceleration, climb, maximum speed etc. In general, it varies from 10-20.
Correct Answer : static sea-level conditions, take-off requirement etc
Explanation : When designer speaks for a thrust loading it generally refers to the value which has been calculated for standard day conditions, static sea-level conditions, take-off performance etc. Different phases incorporate different values of thrust loading. Hence, a designer typically converts them to take-off conditions.
Correct Answer : ratio of thrust produced by an engine to the weight of the aircraft
Explanation : Thrust loading is nothing but the thrust to weight ratio. It is defined as the ratio of thrust produced by the engine to the weight of the aircraft. Thrust loading will vary from aircraft to aircraft. It can be between 0.2-0.6 typically.
Correct Answer : Comparison of the engine’s available thrust at cruise to the estimated drag of aircraft
Explanation : Thrust matching is nothing but the comparison of an engine’s available thrust at cruise to the estimated drag of aircraft. It is used for better initial estimation of the thrust to weight ratio.
Correct Answer : drag to lift ratio at cruise
Explanation : At idle cruise condition, lift = weight and thrust = drag. Hence, thrust loading T/W = D/L = Drag to lift ratio at the cruise. Aerodynamic efficiency is the ratio of lift to drag. Thrust loading at cruise is inverse of aerodynamic efficiency.
Correct Answer : 1.11
Explanation : Given, thrust loading at cruise T.L. = 0.9, prop aircraft.For prop aircraft maximum L/D = Cruise L/DHence, T.L. = D/L.Hence, cruise L/D = 1/(T/W) = 1/0.9 = 1.11.
Correct Answer : 48.225 mph
Explanation : Given, Power loading P.L. = 12.P.L. is given by,W/hp = 1 / (a*Vmaxc), for twin turbo prop a=0.012, c=0.5.Hence, maximum velocity Vmax is given by,12 = 1 / (0.012*Vmax0.5)0.012*Vmax0.5 = 1/12.Vmax0.5 = 1 / (0.012*12) = 6.944Takin log at both sides,0.5*ln (Vmax) = ln (6.944) = 1.937Now, taking anti-log,Vmax = e(1.937/0.5) = e3.875 = 48.225mph
Correct Answer : decrease
Explanation : Thrust loading of the aircraft is defined as the ratio of the thrust of the aircraft to the weight of that aircraft. Hence, thrust loading is inversely proportional to the aircraft weight. Hence, if weight is increased then the corresponding value of thrust loading will decrease.
Correct Answer : 26.97 pound of force
Explanation : Thrust in pound of force = Thrust in newton*0.225 = 120*0.225 = 26.97 lb of force.
Correct Answer : 0.096
Explanation : Given, maximum lift to drag = 12.Thrust loading at cruise T/W = 1 / (L/D at cruise)For, jet aircraft cruise lift to drag = 86.6% of maximum lift to drag = 86.6% of 12 = 0.866*12 = 10.392Now, thrust loading at cruise,Thrust loading at cruise T/W = 1 / (L/D at cruise)= 1/10.392 = 0.096.
Correct Answer : 2
Explanation : Given, Thrust loading at cruise T/WThrust loading at cruise T/W = 1 / (L/D)Hence, Aerodynamic efficiency (L/D) at cruise is,L/D = 1 / (T/W) = 1/0.5 = 2.
Correct Answer : 0.1
Explanation : Given, Aerodynamic efficiency L/D = 10Thrust loading at cruise T/W = 1 / (L/D) = 1/10 = 0.1.
Correct Answer : weight of the aircraft and the reference area of wing
Explanation : Wing loading is defined as the ratio of the weight of an aircraft to the reference area of wing. Similar to thrust loading, wing loading has major effects on the aircraft performance. Lift to drag ratio is defined as aerodynamic efficiency.
Correct Answer : stall speed, climbing, ground roll etc
Explanation : Ratio of the weight of an aircraft to the reference area of wing is termed as wing loading. Wing loading will show the relation between surface area and the weight of an aircraft as a whole. Wing loading will have impact on stall speed, climbing, ground roll, take-off etc.
Correct Answer : more space for fuel storage in wing
Explanation : Wing loading will affect the size of the wing, weight of aircraft etc. Wing loading is given by, Weight off aircraft divided by reference area. If wing loading is low then, the reference area is more. This shows that large wings are used which can store more fuel.
Correct Answer : 21.5
Explanation :
Correct Answer : take-off distance estimation
Explaination : Above diagram is representing variation of take-off parameter with take-off distance. It is used for takeoff distance estimation. Take-off parameter will vary with the wing loading and thrust loading. Power loading is ratio of power to weight for jet.
Correct Answer : 9071.07
Explanation : Given, a civil aircraft.Lift off speed V1 = 80m/s, maximum lift coefficient CL=2.8.Wing loading is given by,W/S = 0.5*ρ*V2*CLWhere, V = V1/1.1 = 80/1.1=72.72m/sHence, wing loading is given by,W/S = 0.5*ρ*V2*CLW/S = 0.5*1.225*72.722*2.8 = 9071.07.
Correct Answer : 5.832m/s
Correct Answer : increase wing loading
Explanation : Wing loading is directly related to the weight of the aircraft. High wing loading refers to the small wings and vice-versa. Hence, to decrease the empty weight, we can increase the wing loading by reducing reference area.
Correct Answer : weight and cost of aircraft
Explanation : Low wing loading shows larger wings are used. Larger wing will increase weight and as wing is large material requirement will increase as well. This will affect the cost parameter.
Correct Answer : Lowest among all three
Explanation : In general, we chose the lowest among all the values. This is done if and only if the lowest value can satisfy almost every mission phase requirement; from take-off to land. If it does not satisfy then, we should estimate another value.
Correct Answer : 3.5
Explanation : Given, W/S = 12, lift co-efficient CL = 2.1 and q=20PaNow load factor n is given by, n = q*CL / (W/S) = 20*2.1/12 = 3.5.
Correct Answer : 0.48
Explanation : Given, load factor n=1.2, lift to drag L/D = 2.5Now, n at cruise is given by, n = (T/W)*(L/D).Hence, T/w is given as,T/W = n / (L/D) = 1.2/2.5 = 0.48.
Correct Answer : 1.80m/s
Correct Answer : 7.54
Explaination :