Rocket Propulsion - Definitions and Fundamentals Quiz(MCQ)

A)
Rocket
B)
Turbojet
C)
Turbofan
D)
Scramjet

Correct Answer :   Rocket


Explanation : Unlike turbojet, turbofan, scramjet, ramjet or turboprop engines, rockets are not air-breathing engines. It carries both fuel and oxidizer along with it, while the other engines suck in air to undergo combustion with the stored fuel.

A)
Solar
B)
Nuclear
C)
Chemical
D)
Geothermal

Correct Answer :   Geothermal


Explanation : Chemical, solar, nuclear, electric are all different types of rocket engines based on their energy sources. But geothermal energy source is limited locally on earth and can’t be harnessed for the whole course of the rocket’s journey.

3 .
Consider two rocket engines A and B with A having a specific impulse of 242s and B having a specific impulse of 150s. What can be said about their efficiency?
A)
B is more efficient than A
B)
A is more efficient than B
C)
Both A and B are equally efficient
D)
Efficiency doesn’t depend on specific impulse

Correct Answer :   A is more efficient than B


Explaination : Higher specific impulse will result in better efficiency. Rocket A has a higher specific impulse than rocket B. Hence it is more efficient.

4 .
Given that the total impulse is 25000 Ns and specific impulse is 300s, find out the effective propellant mass for a burn duration of 8s.
A)
 8.5 kg
B)
17 kg
C)
34 kg
D)
68 kg

Correct Answer :    8.5 kg


Explaination : Given Isp = 300s and It = 25000 Ns.
Using Isp = It/mpgo, with go = 9.8 m/s2.
mp = 25000 / (9.8 x 300) = 8.5 kg.

5 .
For a rocket, the specific impulse was found to be 250s. Given that the thrust force is constant and assuming gravity-free and drag-free conditions, what will the thrust force be for a mass flow rate of the form (4t2-3t) kg/s and a burn duration of 3s?
A)
12426 N
B)
15595 N
C)
18375 N
D)
25234 N

Correct Answer :   18375 N


Explaination : Specific impulse Isp = ∫Fdt/(go∫mdt) where m is mass flow rate, go is standard acceleration due to gravity at sea level.
Then Isp = Ftb/go(4tb3/3 – 3tb2/2).
Using tb = 3s, Isp = 250s, go = 9.8 m/s2,
F = 250 x 9.8 x 22.5/3 = 18375 N.

6 .
What is the range of temperature of reaction product gases in a rocket engine?
A)
500 to 1700 °C
B)
1700 to 2500 °C
C)
2500 to 4100 °C
D)
4100 to 6900 °C

Correct Answer :   2500 to 4100 °C


Explaination : The temperature at which product gases of the chemical reaction taking place within the combustion chamber is too high. It is even higher than the melting point of some of the more commonly used materials in aircraft industry like aluminum (660 °C). Appropriate cooling mechanisms are set up to ensure that this high temperature doesn’t transfer over to the rocket components and that it doesn’t lead to the development of thermal stresses.

A)
Pump-fed system
B)
No feed system is used
C)
Gravity assisted feed system
D)
The Gas pressure feed system

Correct Answer :   The Gas pressure feed system


Explanation : For attitude control of such vehicles, the thrust, as well as the total energy of the propulsion system should be low. Gas pressure feed system is suitable in such circumstances.

A)
Pump-fed system
B)
Gravity assisted feed system
C)
The Gas pressure feed system
D)
No feed system is used

Correct Answer :   Pump-fed system


Explanation : In vehicles used for space launch, the thrust required and the overall energy of propulsion required is too high. In such cases, the rate of supply of propellants to the combustion chamber will be high. A pump fed system is capable of generating a large mass flow rate of the propellants. Hence it is used here.

A)
0 Ns
B)
9000 Ns
C)
18000 Ns
D)
36000 Ns

Correct Answer :   18000 Ns


Explanation : Here we assume that the start and stop transients are negligible during the operation of the system. Then, for a constant thrust (F), and for the total burning time of t seconds, the total impulse It = Ft.
It = 6000 x 3 = 18000 Ns

10 .
Suppose the thrust force of a rocket varies with time t as F = 250(3t2 + 2t). Then find out the total impulse for a burn duration of 4s.
A)
10000 Ns
B)
20000 Ns
C)
40000 Ns
D)
80000 Ns

Correct Answer :   20000 Ns


Explaination : The total impulse can be obtained by integrating the force F with respect to time t from 0 to 3. The total impulse for a varying force F is obtained by It = ∫Fdt.
It = 250 x (tb3 + tb2) = 250 x (64 + 16) = 20,000 Ns.

11 .
If the exit pressure is thrice the atmospheric pressure for a rocket A and if it is twice for rocket B, what will be the ratio of pressure thrust of rocket A to that of B?
A)
1
B)
2
C)
3
D)
4

Correct Answer :   2


Explaination : Pressure thrust is the difference between nozzle exit pressure and ambient pressure multiplied by nozzle exit area.
Pe = 3Pa for rocket A
Pe = 2Pa for rocket B
Pressure thrust Tp = (Pe-Pa)Ae
So TpA/TpB = 2Pa/Pa

A)
The cross-sectional area of the throat
B)
The cross-sectional area of the nozzle exit
C)
The total surface area of the rocket casing
D)
The total surface area of the combustion chamber

Correct Answer :   The cross-sectional area of the nozzle exit


Explanation : Area (A) represents the nozzle exit cross-sectional area. The expression for pressure thrust is (Pe-Pa)A, where Pe is the exit pressure and Pa is the ambient pressure.

A)
Thrust decreases, specific impulse increases
B)
Thrust increases, specific impulse increases
C)
Thrust increases, specific impulse decreases
D)
Thrust decreases, specific impulse decreases

Correct Answer :   Thrust increases, specific impulse increases


Explanation : Atmospheric pressure decreases with increasing altitude. So the pressure thrust part of the total thrust increases and hence the total thrust increases. Specific impulse is impulse per unit weight of the propellant and proportional to thrust, so it too will increase.

A)
equal to
B)
less than
C)
greater than
D)
equal to or slightly higher than

Correct Answer :   equal to or slightly higher than


Explanation : Exhaust pressure should be such that it is equal to or slightly greater than the atmospheric pressure. Else the pressure thrust will be negative and lead to low overall thrust.

A)
Keeps on increasing
B)
Keeps on decreasing
C)
First increases, then decrease
D)
First decreases, then increase

Correct Answer :   First increases, then decrease


Explanation : Initially as the nozzle is extended, thrust keeps increasing. This is because of the rate of increase in exhaust velocity being high compared to the decrease in exit pressure. This increase happens until the point where exit pressure equalizes atmospheric pressure. Afterward, the decrease in pressure thrust is more significant and as a result of this, the total thrust also decreases.

A)
A
B)
B
C)
A doesn’t have a specific impulse
D)
B doesn’t have a specific impulse

Correct Answer :   B


Explanation : B will have much higher specific impulse because it uses large amounts of outside air for combustion. Since specific impulse is impulse per unit amount of propellant and the stored propellant in jet engines is only the fuel (and not both fuel and oxidizer like in rocket engines), it will have a higher specific impulse.

17 .
If exhaust pressure is Pe and surrounding fluid pressure is Pa, what is the condition for the optimum expansion ratio of a rocket nozzle?
A)
Pe=Pa
B)
Pe<Pa
C)
Pe>Pa
D)
Pe=0.5*Pa

Correct Answer :   Pe=Pa


Explaination : For the optimum expansion of the nozzle, exhaust pressure should be equal to the ambient pressure. When that happens, the size of the rocket exhaust plume matches the size of the nozzle and losses are minimum.

A)
625 m/s
B)
1250 m/s
C)
2500 m/s
D)
5000 m/s

Correct Answer :   1250 m/s


Explanation : Total Thrust = mass flow rate x effective exhaust velocity. Here we assume that the mass flow rate is constant, flow is axially directed and frictional effects are neglected.
So, 20,000 = 16 x ueff
ueff = 20,000/16 = 1250 m/s.

19 .
What is the nozzle throat diameter of a rocket having chamber pressure (Pc) of 3 MPa, mass flow rate (m) of 20 kg/s and characteristic velocity (c*) of 1500 m/s?
A)
10 cm
B)
11.3 cm
C)
12.8 cm
D)
25 cm

Correct Answer :   11.3 cm


Explaination : From the expression c* = Pc At / m, throat area At can be determined.
At = 1500 x 20/(3 x 106) = 0.01 m2
At = πd2/4

A)
Throat section
B)
Divergent section
C)
Convergent section
D)
Staggering section

Correct Answer :   Staggering section


Explanation : Main elements of a nozzle include convergent, divergent and throat sections. Staggered nozzle sections are uncommon and unfavorable for the smooth flow of exhaust gases.

A)
Propellants
B)
Surrounding air
C)
combustion products of the propellants
D)
A mixture of combustion products and surrounding air

Correct Answer :   combustion products of the propellants


Explanation : The exhaust gas at the nozzle exit of a chemical rocket engine consists of combustion products of the propellants. If the combustion were inefficient, it would also contain unburnt propellants. Downstream of the nozzle exit, the exhaust jet entrains the surrounding air and becomes a mixture of both.

A)
C
B)
Isp
C)
Both of them are equal
D)
Both of them are equivalent

Correct Answer :   Both of them are equivalent


Explanation : Isp = C/go, where go is the standard acceleration due to gravity at sea level. Since Isp and c differ only by a constant factor, they are equivalent.

A)
Rocket velocity
B)
Exit area
C)
Mass flow rate
D)
Exhaust velocity

Correct Answer :   Rocket velocity


Explanation : In the formulation of effective exhaust velocity, mass flow rate, exhaust velocity, exit area, nozzle exit pressure, ambient pressure are all relevant variables. But the rocket velocity doesn’t come into picture in the final expression.

A)
combustion chamber
B)
casing
C)
nozzle
D)
injector

Correct Answer :   combustion chamber


Explanation : Characteristic velocity can be used to compare the performance of combustion chambers in chemical rocket engines. It can also be used to compare different propellants and propulsion systems.

A)
The kinetic energy of ejected matter
B)
The electrical energy of the rocket control system
C)
The chemical energy of combustion of propellants
D)
The potential energy of the rocket at some altitude

Correct Answer :   The kinetic energy of ejected matter


Explanation : At the nozzle exit, the exhaust gases are ejected with some kinetic energy. This is the most useful form of energy crucial to propulsion. Chemical energy produced from the combustion of propellants is of no use unless it can be harnessed for propelling the rocket forward by some means.

A)
7.78 MW
B)
15.55 MW
C)
31.10 MW
D)
62.21 MW

Correct Answer :   15.55 MW


Explanation : Power of the jet is 1/2mv2. It is the time rate of expenditure of ejected jet’s kinetic energy.
Pjet = 1/2 x 15 x 14402
= 15.55 MW.

27 .
For a rocket having 95% combustion efficiency, total chemical power of 17MW, a mass flow rate of propellants of 15 kg/s, and effective jet exhaust velocity of 1443 m/s, find the internal efficiency of rocket propulsion.
A)
91%
B)
93%
C)
95%
D)
97%

Correct Answer :   97%


Explaination : Internal efficiency of rocket propulsion is the ratio of kinetic power in the jet to the available chemical power. It is an indicator of how much the system is capable of converting input energy into useful kinetic energy.
Pav chem = ηcomb x Ptot chem
= 0.95 x 17 x 106 W
ηint = Pkinetic / Pav chem
= 1/2μe2 / Pchem
= 0.5 x 15 x 14432 / (0.95 x 17 x 106)
≅ 0.966.

A)
Poor mixing
B)
Incomplete burning
C)
Heat loss to the walls
D)
Radial combustion propagation

Correct Answer :   Radial combustion propagation


Explanation : Axial and radial combustion propagation are two different kinds of burning propagation. Poor mixing and incomplete burning constitute combustion losses.

A)
10 MW
B)
15 MW
C)
75 MW
D)
225 MW

Correct Answer :   15 MW


Explanation : Power transmitted to the vehicle is the product of vehicle velocity and the thrust produced by the propulsion system. It is not the same as exhaust jet power.
Ptrans = T v
= 5 x 103 x 3000
= 15 MW.

30 .
For a propulsive device, if power available is denoted by P1, power input by P2, combustion efficiency by e, then which of the following expression is correct?
A)
P1=P2*e
B)
P1=P2/e
C)
P1=P2/e2
D)
P1=P2*e2

Correct Answer :   P1=P2*e


Explaination : P1=P2*e is the correct expression. Input power will be reduced by a factor of combustion efficiency to become power available.

A)
enthalpy of fusion
B)
enthalpy of atomization
C)
heat of combustion
D)
enthalpy of vaporization

Correct Answer :   heat of combustion


Explanation : The heat of combustion is the maximum energy per unit mass that can be extracted from chemical propellants. It can be of two types – higher or lower heating value. Higher heating value is determined by taking all the propellants to their pre-combustion temperature and letting all the vapor produced in the reaction to condense.

A)
Expulsion of propellants
B)
Ionization of propellants
C)
Combustion of propellants
D)
Atomization of propellants

Correct Answer :   Combustion of propellants


Explanation : Propellants are mixed together and combusted to create energy for propulsion. Expulsion of propellants after combustion converts this energy into a more useful form (kinetic energy).

A)
8.91 kW/kg
B)
17.14 kW/kg
C)
25.43 kW/kg
D)
34.28 kW/kg

Correct Answer :   17.14 kW/kg


Explanation : Specific power is jet power divided by the total mass of that the propulsion system prior to its launch. It is lower for electric propulsion system when compared to chemical rockets. This is because of the heavier and relatively inefficient power source that it has to carry.
Pspec = Pjet / mtotal
mtotal = minert + mprop
= 50 + 1000 = 1050 kg
∴ Pspec = 18 x 106 / 1050
= 17.14 kW/kg.

A)
Very low specific power
B)
Relatively light machinery
C)
Very high thrust capability
D)
Relatively low values of specific impulse

Correct Answer :   Very low specific power


Explanation : Chemical rockets have very high thrust capability. Because of this, chemical rockets have high specific power and high acceleration.

A)
Solid propulsion system
B)
Liquid propulsion system
C)
Hybrid propulsion system
D)
Electrical propulsion unit

Correct Answer :   Electrical propulsion unit


Explanation : Electrical propulsion units have low thrust values. This means that it is a less viable option during take-offs and landing. Because of its very low acceleration potential, it takes a long period of time to accelerate and hence is suited for missions that are time intensive.

A)
300 s
B)
600 s
C)
800 s
D)
2000 s

Correct Answer :   800 s


Explanation : Chemical rocket engines have relatively lower values of specific impulse. Ion-electrostatic type of rocket engines have very high specific impulses, but they lag in their acceleration potential. Nuclear fission type rocket engines have typical values of the specific impulse around 600 s, while the arc-electro thermal ones have it around 800 s.

37 .
A rocket engine moving at 500 m/s produces a total thrust of 9563 N, consuming propellants at the rate of 4.55 kg/s. The energy content of the propellants is 5.35 MJ/kg. Find the effective exhaust velocity.
A)
1400 m/s
B)
1555 m/s
C)
2100 m/s
D)
3936 m/s

Correct Answer :   2100 m/s


Explaination : Rocket thrust is the product of mass flow rate and effective exhaust velocity. Using this,
ue = T/m
= 9563/4.55
≈ 2100 m/s.

A)
Hall effect
B)
Resistojets
C)
Nuclear fission
D)
Electro thermal

Correct Answer :   Hall effect


Explanation : Hall effect type of rocket engines uses Xe as a typical working fluid. Resistojet rockets typically use H2 or N2H4 as working fluid, while nuclear fission uses H2 and electro thermal one uses NH3, N2H4 or H2.

A)
0.01
B)
0.1
C)
1
D)
10

Correct Answer :   0.01


Explanation : Typical value of the mass flow rate for a chemical rocket engine is about 0.03. Nuclear fission and arc-electro thermal types of engines have it around the same order of magnitude.

A)
Hall effect
B)
Ion-electrostatic
C)
Solar heating
D)
Nuclear fission

Correct Answer :   Ion-electrostatic


Explanation : Ion-electrostatic engine has a specific impulse of 1200-5000 s. Nuclear fission type engines have Isp of 500-860 s, while solar heating engines have it around 400-700 s.

A)
Few weeks
B)
Few days
C)
Few minutes
D)
Few seconds

Correct Answer :   Few days


Explanation : Resistojets have a propulsion duration spanning a few days. The chemical rocket engines have a propulsion duration lasting a few seconds to a few minutes, while for ion-electrostatic engines, it lasts for months.

A)
Nuclear
B)
Chemical
C)
Arc heating
D)
Solar heating

Correct Answer :   Arc heating


Explanation : Arc heating can lead to temperatures of about 20,000 deg C. Chemical propulsion systems have a maximum temperature ranging from 2500-4100 deg C, while nuclear fission leads to temperatures of about 2700 deg C.