Correct Answer : combustion chamber
Explanation : Propellants burn in the combustion chamber for both solid and liquid rocket engines. This burning can produce temperatures higher than melting points of many of the chamber wall materials. So, an effective cooling system is used to mitigate this issue.
Correct Answer : Mixing, evaporation and complete combustion of the propellants
Explanation : All the three factors – mixing, complete combustion and evaporation of the propellants are considered for the choice of the volume of combustion chamber. It is chosen such that the mixing is good, evaporation is less and the complete combustion is ensured at all times.
Correct Answer : Average time spent by each molecule or atom within the combustion chamber volume
Explanation : Stay time is the average time that each molecule or atom of the propellant stays within the volume of the combustion chamber.It is defined by ts = Vc/mVi, where Vc is the chamber volume, m is the mass flow rate, and Vi is the average specific volume.
Correct Answer : 0.8 and 3 m
Explanation : L* typically has a range of 0.8 to 3 m. This is the case for bipropellants. For monopropellants, it may lie even higher.
Correct Answer : Length of the thrust chamber as if it were a straight tube with no converging section
Explanation : Characteristic length is the length of the thrust chamber assuming that it was a straight tube with no converging section.L* = Vc/At, where Vc is the chamber volume and At is the throat area.
Correct Answer : decreases; decreases
Explaination : The combustion chamber length will decrease because the combustion chamber volume decreases with the chamber pressure for the same thrust. It will also lead to a decrease in the nozzle throat area.
Correct Answer : Lower wall temperature
Explanation : Heat transfer to the chamber wall will be less if the diameter and volume of the chamber is large. This is due to the large area exposed to heat and due to thicker walls of the chamber.
Correct Answer : payload mass
Explanation : The combustion chamber mass is not a function of payload mass. But it will depend upon the method of cooling, area ratio of the nozzle and the chamber pressure.
Correct Answer : Possibility for complete combustion
Explanation : If there are means of achieving complete combustion, then the size of the combustion chamber may be reduced. Other than that, using highly reactive propellants (with adequate safety measures), having high chamber pressure and using injectors with good mixing will also act as factors for the selection of a smaller combustion chamber.
Correct Answer : injector
Explanation : Injector in rocket engine and carburetor in an internal combustion engine functions in a similar manner. Injector meters, injects and atomizes the liquid propellants into the combustion chamber.
Correct Answer : Sheet injector
Explanation : Sheet injector requires large chamber volume for good combustion. It is a spray-type injector that can give cylindrical, conical and many other kinds of spray sheets.
Correct Answer : showerhead
Explanation : A showerhead injector is also called as a non-impinging injector. The propellant usually comes out normal to the face cross-section of the injector.
Correct Answer : Dribbling flow
Explanation : Dribbling flow can cause afterburning. The dribble flow may lead to an excess in fuel and this might end up in secondary reactions after passing the combustion chamber and result in afterburning.
Correct Answer : atomization
Explanation : Atomization is the process through which the liquid is broken into tiny droplets. One of the functions of injector is atomization.
Correct Answer : Injector hole pattern
Explanation : By varying the injector hole pattern, it is possible to get different types of propellant distribution from the injector inlet. It is related to feed passages and internal manifolds within the injector.
Correct Answer : low flow velocities; good distribution of flow over the chamber cross-section
Explanation : For larger manifolds, the injector flow will be lesser and the distribution of flow over the chamber cross-section will be uniform. This can be seen by considering two passages of varying cross-sections and constant mass flow rate of propellants through it.
Correct Answer : less dribble; lighter injector
Explanation : Dribble flow is remaining flow after the valve closes. For a smaller manifold volume of an injector, the amount of dribble flow will be lesser. Since the injector is small, only a small mass of material is used for injector manufacturing and hence it leads to a lighter injector.
Correct Answer : pop valve
Explanation : Pop valve is used for that purpose. It sharply opens to allow full flow. This type of valve opens only when a certain pressure has been attained.
Correct Answer : dribble flow
Explanation : Dribble or dripping flow is the flow after the main valves are shut. This uneven flow is undesirable and needs to minimize.
Correct Answer : Q/A = -k dT/dL
Explaination : Q/A = -k dT/dL is the expression for heat transferred per unit area. This is called as Fourier’s law of heat transfer. By negative symbol in the equation, we can see that the direction of heat transfer is in the direction of negative gradient (larger temperature to smaller temperature) of temperature along the length of the material.
Correct Answer : Prandtl number
Explaination : μCp/k is the Prandtl number. It is the ratio of momentum diffusivity to thermal diffusivity.
Correct Answer : Nusselt number
Explaination : hgD/k is called as the Nusselt number. This is a parameter which comes into picture while dealing with heat transfer problems between a solid body and a moving fluid.
Correct Answer : Uniform velocity profile
Explanation : Film coefficient calculation might be simplified for a uniform velocity profile. In reality, the determination of this coefficient is very difficult because of the presence of combustion oscillations, complex geometry, non-uniform velocity profile and presence of boundary layers.
Correct Answer : Gas film coefficient; liquid film coefficient
Explanation : Gas film coefficient largely helps in the determination of numerical value of heat transfer rate. Liquid film coefficient largely helps in determining the value of wall temperatures.
Correct Answer : series type with strong temperature gradient
Explanation : The heat transfer through the liquid-cooled rocket chamber can be considered as a steady state series type process with strong temperature gradients. This involves a large temperature gradient across the thin gaseous film touching the wall, a temperature drop across the wall and a third temperature drop in the presence of the moving cooling fluid.
Correct Answer : conduction; convection
Explaination : Heat transfer through the chamber walls includes both the conduction through the chamber wall as well as convection through the flowing fluids. This problem is basically one that is associated with the heat and mass transport associated with through a wall.
Correct Answer : q = h (Tg – Tl)
Explaination : q = h(Tg – Tl) is the correct expression for heat transferred per unit area. This relation assumes that the heat flow is radial in direction.
Correct Answer : E = fεσAT4
Explaination : E = fεσAT4 is the correct expression for energy radiated by a body. Here σ is the Stefan-Boltzmann constant and it has a value of 5.67 x 10-8 W/m2K4.
Correct Answer : Ammonia
Explanation : Gases with symmetrical molecules like hydrogen, oxygen and nitrogen typically doesn’t show a strong band in the region of radiant heat transfer. Heteropolar gases, on the other hand, shows strong activity in that band.
Correct Answer : Pyrotechnic ignition
Explaination : In pyrotechnic ignition, a squib or grain of solid propellant of few seconds of burning duration is used for the sake of ignition. This is one of the common ways of ignition in a solid propellant rocket engine.
Correct Answer : 15.62 kg/s
Explaination : Propellant flow rate m? = F/c, where F is the total thrust and c is the specific fuel consumption.Then m? = 50,000/3200 = 15.62 kg/s.
Correct Answer : 4.17 kg/s
Explaination : Fuel flow rate m?f = m?/(r+1), where m? is the total propellant mass flow rate and r is the mixture ratio.So m?f = 10/2.4 = 4.17 kg/s.
Correct Answer : 12.95 kg/s
Explaination : m?o = m?r/(r+1)So m?o = 17*3.2/4.2 = 12.95 kg/s.
Correct Answer : 15 and 25%
Explaination : The pressure drop across the injector is set between 15 and 25% of the chamber pressure. This is done partly for obtaining high velocities of propellant injection. High velocities will help in easy atomization and droplet breakup which in turn helps in complete combustion.
Correct Answer : 10.12 cm2
Explaination : Nozzle throat area At = F/P1CF, where P1 is the chamber pressure, CF is the thrust coefficient and F is the total thrust provided by the rocket engine.Then At = 10000/(5.2 x 106 x 1.9)= 10.12 cm2.