Capgemini Interview Preparation and Recruitment Process


About Capgemini


Capgemini is a global leader in consulting, technology services, and digital transformation. Headquartered in Paris, France, the company was founded in 1967 by Serge Kampf as Sogeti, initially focusing on enterprise management and data processing. Over the decades, it evolved through strategic acquisitions and rebranding—becoming CAP Gemini Sogeti in 1975 after acquiring CAP and Gemini Computer Systems, and later simplifying to Capgemini in 1996. Today, it operates in over 50 countries with more than 338,000 employees, including around 194,400 in India as of 2024.

Capgemini Interview Questions

The company provides a wide range of services, including IT consulting, digital transformation, cloud solutions, artificial intelligence, cybersecurity, and engineering services. It serves diverse industries such as banking, manufacturing, aerospace, healthcare, and retail, helping clients innovate and manage their businesses through technology. Capgemini’s purpose is to "unleash human energy through technology for an inclusive and sustainable future," a mission reflected in its work on projects like digital healthcare accelerators and sustainable tech solutions.

Capgemini has grown significantly through acquisitions, notably the 2019 purchase of Altran for €3.6 billion, which boosted its engineering and R&D capabilities and increased its workforce beyond 250,000. It also launched Capgemini Invent in 2018, a design and consulting brand that includes the well-known design firm frog. In 2022, the company reported global revenues of €22 billion, showcasing its financial strength and market presence.

Led by CEO Aiman Ezzat since May 2020, with Paul Hermelin as Chairman, Capgemini emphasizes ethical innovation and inclusivity. It has been recognized as one of the World’s Most Ethical Companies by the Ethisphere Institute for 12 consecutive years and supports 11 UN Sustainable Development Goals. With a 55-year heritage, Capgemini continues to adapt to the fast-evolving tech landscape, blending deep industry expertise with cutting-edge solutions to shape the future of business and society.

You work together to transform the world's most successful companies while sharing information and challenging ourselves to be better. It's how we cultivate exceptional careers and give innovation the personal touch it requires.

If you have the desire, talent, and aptitude to work with cutting-edge technology, Capgemini is the place for you. Please see the eligibility requirements listed below.

Eligibility Criteria :

The candidates must meet all of the following required criteria :

* Candidates must have a 60% or higher in Diploma, Graduation, and MCA/ ME / MTech.
* For SSC and HSC scores, there are no percentage criteria.
* The interview process is open for all branches for both BE and BTech.
* ME / MTech students must be only from Information Technology, Information Science, and Computer Science.
* Candidates should not have any outstanding backlogs when they come for the process.
* Only those candidates who have been shortlisted for the further rounds will be eligible for further rounds.



Capgemini Recruitment Process


1. Interview Process :


The Capgemini Recruitment Process generally consists of three rounds of selection:

* Online assessment test
* Technical interview round
* HR interview round

2. Interview Rounds :


Online Assessment Test :

The online-based assessment test is the first step in the recruitment process. The candidates who clear this round are called for the technical interview rounds. The test is divided into 4 parts.

 The detailed online test pattern for the Capgemini recruitment process is mentioned below :

* Pseudocoding : This is an MCQ round. Capgemini's Pseudo Code section assesses candidates' ability to answer questions that include: Understanding of programming logic (tested through Pseudocode Questions), C, C++, Java, Data Structures and Object-Oriented Programming (OOPS).

* English Communication Test : This exam will put your grammatical and vocabulary skills to the test. This is also an MCQ round. The areas to study for the English Communication test are Reading Comprehension, Para-Jumbles, Direct and Indirect Speech, Active and Passive Voice, Sentence Correction, and completion.

* Game-Based Aptitude : The Capgemini Gamified Quantitative Aptitude Test is the most interesting new stage in the Capgemini Recruitment Process. It is expected to be a series of four games to be completed. The various types of games that occur in the test are related to Deductive Logical Thinking, Inductive Logical Thinking, Grid Challenge, and Motion Challenge.

* Behavioral Competency : This round (also known as the Adaptive Employee Personality Test or ADEPT-15) is a personality psychometric designed to assess work-related behavior. The evaluation is made up of pairs of assertions. You must choose the one you agree with the most.
Only those candidates who have passed all three steps of the test evaluation will be invited to the interview. This round can be skipped by HR  for experienced professionals having adequate work experience and knowledge based on the company's requirements.
The Behavioral Profiling Module is for understanding the candidate's profile, and students who complete the module will receive a work-style report.

Technical Interview Round :


The candidates who clear the online test are called for the face-to-face technical interview round.

Technical interview evaluates your technical abilities, which are usually related to the technical knowledge required for the position and the company you want to work for. The questions are designed to test your problem-solving and numerical reasoning skills.

Thus, the interviewer will evaluate you in the Technical Round based on your :

* Technical Expertise and problem-solving skills.
* IQ Quotient
* Projects  and your past work experiences

The technical face-to-face interview is the most important part of the entire procedure. You should know the principles of computer science, such as OOPS, DBMS, CN, and OS, etc, and be able to properly describe them to the interviewer. Knowledge of a programming language is essential. Make sure you know how to program in at least one language. You do not need to be fluent in all programming languages, but you should have enough familiarity with at least one, such as C++, Java, or Python. The interviewer will also assess your problem-solving abilities. You'll be questioned about your previous projects and professional experiences, including what you did, what technology you used, what you developed, and how successful you were. Questions about the CV and the company may be asked as well.

The number of technical interviews to be conducted will be based on your profile, performance in the previous rounds, and company requirements.

HR Interview Round :


Students who have cleared the Technical interview will be called for the HR round. HR interviews are conducted to assess a candidate's personality in order to determine whether or not they are qualified for the position and how well a candidate will fit into the company's work culture. In addition to the normal HR questions regarding strengths and weaknesses, reasons for applying to the company, why you should be hired, and so on, expect questions about work experience, educational qualification, interests, and family background. They can also ask questions related to Capgemini, such as when it was founded, its objectives, beliefs, goals and organizational structure, among other things.

The hiring process comes to a close at this point. Adaptability is demanded of candidates, although this stage allows for negotiation. The most often asked questions are :

* Please tell me about yourself. (If you're a beginner, start with your academics, projects, achievements, other curriculum activities, and strengths. Also, include information about your interests, background, and so on. Start with your current position, achievements, past work history, and academic and personal details if you're an experienced professional.)

* Why do you think Capgemini is good for you?

* What are your Strengths and Weaknesses?

* Question from Resume

* Questions form Internship/prior projects

* How do you see yourself five years from now?

*
What is your expectation with respect to this role?

* Why are you interested in working for Capgemini?

* Are you open to relocating to various parts of India?

* Why are you looking for a job change? (If you're an experienced professional seeking a change, this is a common question. The easiest method to respond to this question is to state that you are leaving your current work in order to advance your career. Make sure you don't criticize or speak poorly about the company where you now work.)

* What is your expected salary? (This is a difficult question to answer. It is generally asked from experienced employees. You may inquire about the company's standard raise for employees.)

* Do you have a question for us about the company?

Capgemini Interview Questions :

1 .
Why is it suggested to utilise a database management system (DBMS)? List some of its primary advantages to explain.
Following are some advantages of using DBMS :

* Minimizing Data Redundancy : DBMS supports a system to eliminate data redundancy within the database by integrating all data into a single database, and because data is stored in only one location, there is no duplication of data.

* Data Sharing : In a DBMS, data can be shared among several users at the same time because the same database is shared across all users and by various applications.

* Data Integrity : This refers to the database's data being consistent and accurate at all times. It is critical because a database management system (DBMS) contains numerous databases, each of which contains data that is visible to multiple users. As a result, it's critical to guarantee that data is accurate and consistent across all databases and for all users.

* Data Security : Only approved users should be allowed access to the database, and their identities should be authenticated using a legitimate login and password. Under no circumstances should unauthorized users be allowed to access the database, as this would break the integrity limitations.
2 .
Why is normalization needed in a database?
The term "normalization" refers to the process of analyzing relation schemas based on their functional dependencies. Normalization is the technique of splitting up data into numerous tables to reduce redundancy.

The advantages of normalization are :

* Standardization eliminates the copy information, allowing a smaller database to be maintained. As a result, the size of the database is reduced in general.

* Better execution is assured, which is related to the previous point. As the size of information bases shrinks, the time it takes to process it becomes shorter and more constrained, enhancing reaction time and speed.
Narrower tables may be possible as standardized tables are altered and feature fewer segments, allowing for more data items per page.

* With fewer files per table, support assignments are completed faster (file modifies).
3 .
Distinguish between UNION and UNION ALL.
To aggregate the results of two or more SQL SELECT queries, we use the SQL UNION method. In the union operation, the number of data types and columns in both tables on which the UNION action is performed must be the same. Duplicate rows are removed from the result set by the UNION operation. Union ALL operation is the same as a Union operation. It returns the set without sorting the data or deleting duplicates.
4 .
What is Java String Pool?
The developers of Java were well aware that programmers would rely heavily on the String data type. As a result, they sought optimization from the beginning. They came up with the idea of storing String literals in the String pool (storage space in the Java heap).

As a result, whenever a new object is created, the String pool first checks to see if the object has previously been generated in the pool, and if it has, the same reference is returned to the variable. Otherwise, a new object in the String pool will be created and the reference will be returned.

They wanted to use sharing to reduce the size of the temporary String object. To make sharing easier, an immutable class is required. It is not possible to share mutable structures with two unknown parties. As a result, immutable Java Strings aid in the implementation of the String Pool concept.
5 .
Explain shallow copy vs deep copy in the context of Java.
The method of copying an object that is used by default in cloning is a shallow copy. The fields of an old object X are copied to a new object Y in this procedure. The reference is duplicated to Y while copying the object type field, i.e. object Y will point to the same location as X. If the field value is a primitive type, the primitive type's value is copied. As a result, any changes made in object X or Y's linked objects will be reflected in other objects.
// Java
// An object reference of this class is
// contained by IBS
class IB {
    int a, b;
}
 
// Contains a reference of IB and
// implements clone with shallow copy.
class IBS implements Cloneable {
    int x;
    int y;
    IB z = new IB();
    public Object clone() throws CloneNotSupportedException
    {
        return super.clone();
    }
}

// Driver class
public class Main {
    public static void main(String args[])
        throws CloneNotSupportedException
    {
        IBS t1 = new IBS();
        t1.x = 1;
        t1.y = 2;
        t1.z.a = 3;
        t1.z.b = 4;
 
        IBS t2 = (IBS)t1.clone();
 
        // a copy of object t1 is created
        // and is passed to t2
        t2.x = 10;
 
        // any modification in the primitive type of t2
        // does not get reflected in the t1 field
        t2.z.a = 30;
 
        // any modification in object type field
        // gets reflected in both t2 and t1(shallow copy)
        System.out.println(t1.x + " " + t1.y + " " + t1.z.a
                           + " " + t1.z.b);
        System.out.println(t2.x + " " + t2.y + " " + t2.z.a
                           + " " + t2.z.b);
    }
}

Output :

1 2 30 4
10 2 30 4

In the above program, t1.clone returns a shallow copy of the object t1. After receiving the copy, specific modifications to the clone technique must be applied in order to acquire a deep copy of the object.

A deep copy duplicates all fields as well as the dynamically allocated memory that the fields point to. When an item is copied together with the objects to which it refers, it is called a deep copy.

// Java
// An object reference of this
// class is contained by IBS
class IB {
    int a, b;
}
 
// Contains a reference of IB and
// implements clone with deep copy.
class IBS implements Cloneable {
    int x, y;
 
    IB z = new IB();
 
    public Object clone() throws CloneNotSupportedException
    {
        // Assigning the shallow copy to
        // the new reference variable t
        IBS t = (IBS)super.clone();
 
        // Creating a deep copy for c
        t.z = new IB();
        t.z.a = z.a;
        t.z.b = z.b;
 
        // Creating a new object for the field c
        // and assigning it to the obtained shallow copy
        // in order to make it a deep copy
        return t;
    }
}

public class Main {
    public static void main(String args[])
        throws CloneNotSupportedException
    {
        IBS t1 = new IBS();
        t1.x = 1;
        t1.y = 2;
        t1.z.a = 3;
        t1.z.b = 4;
 
        IBS t3 = (IBS)t1.clone();
        t3.x = 10;
 
        // any modification in the primitive type of t2
        // does not get reflected in the t1 field
        t3.z.a = 30;
 
        // any modification in object type field of t2
        // does not get reflected in t1(deep copy)
        System.out.println(t1.x + " " + t1.y + " " + t1.z.a
                           + " " + t1.z.b);
        System.out.println(t3.x + " " + t3.y + " " + t3.z.a
                           + " " + t3.z.b);
    }
}

Output :
1 2 3 4
10 2 30 4

We can see how a new object for the IB class has been designated to replicate an object that will be delivered to the clone method in the preceding example. As a result, t3 will acquire a deep copy of t1's object. As a result, any changes made by t3 to the ‘z' object properties will not be reflected in t1.
6 .
Distinguish between range and xrange in Python.
xrange and range are nearly identical in terms of functionality. They both allow you to generate a list of integers that you may use whatever you want. The only difference between range and xrange is that xrange produces an xrange object while range provides a Python list object.

This implies that, unlike range, xrange does not create a static list during execution. It generates the values as needed using a technique known as yielding. Generators, which are a type of object, are employed with this technique. That is, if you have a large range and want to construct a list for a billion people, you should use xrange.

This is particularly the case if you're working with a system that demands a lot of memory, such as a cell phone, because range will utilise as much RAM as it can to build your array of numbers, causing a memory problem and crashing your app.
7 .
What are the advantages of NumPy arrays over Python lists?
The following are some advantages of NumPy arrays over Python lists :

* NumPy arrays store data in a sequential manner, unlike Python lists, making data processing simpler.

* NumPy is not just more efficient, but it's also easier to use. We get a lot of vector and matrix operations for free, allowing us to avoid doing unnecessary work. They're also put to good use.

* NumPy arrays are faster, and NumPy has a lot of useful features like FFTs, convolutions, quick searching, simple statistics, linear algebra, histograms, and so forth.
8 .
Illustrate public static void main(String args[]) in Java.
The entry point for any Java code is called main() and is always written as a public static void main (String[] args).

* public : The term "public" refers to an access modifier. It's used to specify who has access to use this method. This method is public, which implies that it can be accessed by any class.

* static : This is a keyword that indicates that it is a class-based system. In Java, main() is made static so that it can be accessed without having to create a class instance; however if main is not made static, the compiler will throw an error because main() is called by the JVM before any objects are created, and only static methods can be directly invoked via the class.

* void : The return type of a method is void, and it defines a method that does not return any value.

* main : It's the name of the method that JVM looks for when it's searching for a starting point for an application with a specific signature, and it's the method where the main execution happens.

* String args[] : The parameter passed to the main method is String args[]. args[] is an array of arguments with each element as a string.
9 .
What do you know about #pragma directive?
#pragma is a preprocessor directive for turning on or off specific functionalities. #pragma startup, #pragma exit, and #pragma warn are its three types.

We can use #pragma startup to provide functions that are called when the script starts working.
#pragma exit allows us to specify functions that are executed when the code terminates.
#pragma warn tells the computer whether or not to suppress any warnings.
10 .
To connect the C program and the operating system, what structure is used?
The file structure is used to connect the operating system and an application. The header file “stdio.h” (standard input/output header file) defines the file. It contains information on the currently open file, its current size, and its memory location. It has a character pointer that indicates which character is currently being opened. When you open a file, you're telling the software and the operating system which file you want to open.
11 .
What is the drawback of scanf() and how can it be avoided (if any)?
With a string of characters, scanf() will fail. A multi-word string cannot be entered into a single variable using scanf(). The gets( ) function is used to avoid this. When the enter key is pushed, it gets a string from the keyboard and ends it. As part of the input string, spaces and tabs are permitted.
12 .
What is the difference between getch() and getche()?
Both these C functions read characters from the keyboard, the only difference being:

* getch() is a function that reads characters from the keyboard without using any buffers. As a result, no data is presented on the screen.

* getche() uses a buffer to read characters from the keyboard. As a result, information is displayed on the screen.
Here is an example to demonstrate the difference between the two functions:
#include
#include
int main()
{
    char c;
    printf("Enter a character here: ");
    c = getch();
    printf("nYou entered the character: %c",c);
    printf("nEnter another character: ");
    c = getche();
    printf("nYour new entered character is: %c",c);
    return 0;
}

Output :
Enter a character here:
You entered the character: c
Enter another character: b
Your new entered character is: b

getch() immediately returns the character without waiting for the enter key to be pressed and the character is not displayed on the screen. getche() displays the character on the screen without waiting for the enter key to be pressed.
13 .
What is the difference between Dataset.clone() and Dataset.copy()?
DataSet. Clone() copies only the DataSet object's schema and returns a DataSet object with the same structure as the existing dataset object, including all the relations, constraints, and schemas. The data from the old one will not be copied to the new one.

DataSet.Copy() copies the entire code and structure of an existing DataSet object.
14 .
What are the disadvantages of using an array to implement Queue?
The cons of using an array to implement a queue are :

* Even if the queue is empty, if it has a significant number of enqueue and dequeue operations, we may not be able to insert entries at some time (as in the case of linear increment of front and rear indices) (this problem is solved by using circular queue).

* When using an array to construct a queue, there may be occasions where we need to extend the queue to insert additional elements. Because it is nearly impossible to extend the array size when using an array to implement a queue, determining the suitable array size is always an issue.
15 .
Is there a good reason to choose BSTs over AVLs in the first place?
If you wish to compare the two: an AVL tree to a simple binary search tree (BST) without balancing it, then AVL :

* will require additional memory (each node must keep track of its balance factor) and
* Each operation has the potential to be slower (because you need to maintain the balance factor and sometimes perform rotations).

The worst-case for BST without balancing is quite terrible (linear). However, if you are confident that this worst-case scenario will not occur, or if you don't mind if the process is slow in rare circumstances, BST without balancing may be preferable to AVL.
16 .
List the advantages of using Tries over Binary Search Trees (BSTs).
The advantages of Tries over binary search trees (BSTs) are as follows :

* It's quicker to lookup keys. In the worst-case scenario, looking up a key of length m takes O(m) time. Because lockups are dependent on the depth of the tree, which is logarithmic in the number of keys if the tree is balanced, a BST does O(log n) key comparisons, where n is the number of items in the tree. As a result, a BST takes O(m log n) time in the worst scenario. Furthermore, log(n) will approach m in the worst-case scenario. Also, on real processors, the simple actions Tries utilize during lookup, such as array indexing with a character, are quick.

* Because nodes are shared between keys with common starting sub-sequences, tries with a large number of short keys are more space-efficient.

* Tries facilitate longest-prefix matching, assisting in the discovery of the key with the longest possible prefix of characters, all of which are unique.

* The length of the key is equal to the number of internal nodes from root to leaf. As a result, balancing the tree isn't an issue.
17 .
What is a DNS (Domain Name System) forwarder?
A DNS forwarder is a DNS server that forwards DNS queries for external DNS names to DNS servers outside the network. A forwarder is used with a DNS server when it receives DNS queries that cannot be resolved quickly. Therefore, it forwards these requests to external DNS servers for resolution.

A DNS server that is configured as a forwarder behaves differently than a DNS server that is not configured as a forwarder.

The DNS server behaves as follows when configured as a forwarder:

* When the query is received by the DNS server, it resolves it using a cache.

* If the DNS server is not able to resolve the request, it forwards it to another DNS server.

* If the forwarder is not available, it tries to resolve the query using a root hint.
18 .
How does the dynamic host configuration protocol help with network management?
The network administrator uses the dynamic host configuration protocol to create a pool of IP addresses instead of going to each client computer to configure a static IP address. This group is known as an area that can be dynamically assigned to clients.
19 .
What do you know about anonymous FTP (File Transfer Protocol)?
Users can access public data through anonymous FTP. The server does not need the user to identify himself, and the login is anonymous. As a result, while utilizing anonymous FTP, you must substitute 'anonymous' for the user id. Anonymous FTPs allow you to send large files to a large number of individuals without having to give out a large number of password and username combinations.
20 .
What distinguishes a structure from a class in C++?
There are a few distinctions between a class in C++ and a structure.

These are the following :

* When creating a structure from a class or another structure, the base class or structure's default access specifier is public. When deriving a class, on the other hand, the default access specifier is private.

* The members of a structure are always public, but the members of a class are always private.

* The variables of a structure are stored in the stack memory while those of the class are stored in the heap memory.

* Class supports inheritance whereas structures do not.

* The type of class is reference type whereas the type of structure is a value type.

Capgemini MCQ :

1 .
A 30% Loss on Cost Price is what percentage loss on Selling Price?
A)
25%
B)
30%
C)
40%
D)
None of the above

Correct Answer :   None of the above


Explanation : Let CP=100, SP=70
Loss= 30/70*100=42.85%

2 .
A, B and C Can hire a taxi for Rs. 2400 for one day. A, B and C utilized the auto for 6 hours, 8 hours and 10 hours separately. What amount did C pay?
A)
600
B)
800
C)
1000
D)
1200

Correct Answer :   1000


Explanation : Let total fair rs.2400
C share=10/24*2400=1000

3 .
A is twice as fast as B is thrice as fast as C. The journey covered by C in 42 minutes, what will be covered by A is
A)
14 MIN
B)
22 MIN
C)
40 MIN
D)
54 MIN

Correct Answer :   14 MIN


Explanation : B is thrice as fast as C
C covered in 42 minutes
B covered in 42/3=14 min

4 .
What percent is 2 minutes 24second of an hour?
A)
2%
B)
4%
C)
6%
D)
8%

Correct Answer :   4%


Explanation : %=144/60*60=4%

5 .
A man purchases a book for Rs.29.50 and offers it for Rs. 31.10. Discover his gain percent.
A)
2.4%
B)
5.4%
C)
8.1%
D)
9.6%

Correct Answer :   5.4%


Explanation : So we have C.P. = 29.50
S.P. = 31.10
Gain = 31.10 - 29.50 = Rs. 1.6
Gain %=( Gain/Cost*100)%
= (1.6/29.50?100)%=5.4%

6 .
A train 125 meter long is running at 50 km/hr. In what time will it pass a man running at 5 km/hr in a similar bearing in which the train is going?
A)
10 sec
B)
15 sec
C)
55 sec
D)
60 sec

Correct Answer :   10 sec


Explanation : Distance=125 meter speed=50-5=45km/hr=>45*5/18=12.5 m/s
Time=125/12.5=10sec

7 .
A man pushes downstream 30 km and upstream 18 km, taking 5 hours each time. What is the speed of the stream (current)?
A)
1.2 KM/HR
B)
1.7 KM/HR
C)
2.8 KM/HR
D)
4.8 KM/HR

Correct Answer :   1.2 KM/HR


Explanation : Let x=speed of boat and y=speed of current
=30/ (x + y) =18/(x-y) =5 by solving y=1.2 km/hr

8 .
Look at the series: A4, __, C16, D32, E64. What number should fill the blank?
A)
B16
B)
B10
C)
B8
D)
D4

Correct Answer :   B8


Explanation : The letters Increase by 1; the numbers are duplicated by2.

9 .
The ratio of investment of A: B is 8:7 and the ratio of year-end profits is 20:21. If B invested for 12 months, then find the period of investment of A.
A)
3 MONTHS
B)
6 MONTHS
C)
8 MONTHS
D)
10 MONTHS

Correct Answer :   10 MONTHS


Explanation : Let A invest for x month A=8x
B=7*12=84 months
8x/84=20/21
X=10

10 .
A sum of money doubles itself at C.I. in 15 years.
A)
30 years.
B)
35 years.
C)
30 years.
D)
45 years

Correct Answer :   45 years

11 .
The total ages of 5 youngsters conceived at the interval of 3 years each is 50 years. What is the age of the youngest child?
A)
4 years
B)
8 years
C)
10 years
D)
None of the above

Correct Answer :   4 years


Explanation : Give the times of youngsters a chance to be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
At that point, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
5x = 20
x = 4.

12 .
What was the day of the week on 28th May 2006?
A)
Friday
B)
Monday
C)
Sunday
D)
Thursday

Correct Answer :   Sunday


Explanation : 28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 conventional years + 1 jump year) = (4 x 1 + 1 x 2) 6 odd days
Jan. Feb. March April May
(31 + 28 + 31 + 30 + 28) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Add up to number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.

13 .
What was be the day of the week on fifteenth August 2010?
A)
Sunday
B)
Monday
C)
Tuesday
D)
Friday

Correct Answer :   Sunday


Explanation : Fifteenth August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0
Odd days in 400 years = 0
9 years = (2 jump years + 7 customary years) = (2 x 2 + 7 x 1) = 11 odd days 4 odd days.
Jan. Feb. March April May June July Aug.
(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days
227 days = (32 weeks + 3 days) 3 odd days.
Add up to number of odd days = (0 + 0 + 4 + 3) = 7 0 odd days.
Given day is Sunday.

14 .
A boat can go at a speed of 13 km/hr in still water. In the event that the speed of the stream is 4 km/hr, discover the time taken by the boat to go 68 km downstream.
A)
2 hours
B)
3 hours
C)
4 hours
D)
5 hours

Correct Answer :   4 hours


Explanation : Time taken to movement 68 km downstream = 68 hrs = 4 hrs.

15 .
A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is:
A)
12.5 km/hr
B)
10 km/hr
C)
9 km/hr
D)
8.5 km/hr

Correct Answer :   10 km/hr

16 .
A can complete a specific work in a similar time in which B and C together can do it. In the event that A and B together could do it in 10 days and C alone in 50 days, at that point B alone could do it in.
A)
14 DAYS
B)
15 DAYS
C)
20 DAYS
D)
25 DAYS

Correct Answer :   25 DAYS

17 .
A, B and C mutually thought of connecting with themselves in a business wander. It concurred that A would contribute Rs. 6500 for a half year, B, Rs. 8400 for 5 months and C, Rs. 10,000 for 3 months. A needs to be the working part for which, he was to get 5% of the benefits. The benefit earned was Rs. 7400. Calculate the share of B in the profit.
A)
Rs. 1900
B)
Rs. 2660
C)
Rs. 2800
D)
Rs. 2840

Correct Answer :   Rs. 2660


Explanation : For dealing with, A got = 5% of Rs. 7400 = Rs. 370.
Equalization = Rs. (7400 - 370) = Rs. 7030.
Proportion of their investment = (6500 x 6): (8400 x 5): (10000 x 3)
= 39000: 42000: 30000
= 13: 14: 10
B's offer = Rs. 7030 x14/37= Rs. 2660.

18 .
If 20 men can construct a divider 112 meters in length in 6 days, what length of a comparable divider can be worked by 25 men in 3 days?
A)
58 meters.
B)
69 meters.
C)
70 meters.
D)
76 meters.

Correct Answer :   70 meters.


Explanation : 20 men in 6 days can build 112 meters
25 men in 30 days can build=112*(25/20)*(3/6)
= 70 meters

19 .
In a race of 600 meters, A can beat B by 60 meters and in a race of 500 meters; B can beat C by 50 meters. By what number of meters will A beat C in a race of 400 meters?
A)
76 meters.
B)
84 meters.
C)
89 meters.
D)
92 meters.

Correct Answer :   76 meters.


Explanation : A runs B runs C runs
600 meters race 600 m 540 m
500 meters race 500 m 450 m
Coming ratio A runs B runs C runs
300 meters-2700 meters-2430 meters
Unitary A runs B runs C runs
Methods 400m-360m-324m
A beat C by 400- 324=76 meters.

20 .
A boat running upstream takes 8 hours 48 minutes to cover a specific separation, while it takes 4 hours to cover a similar separation running downstream. What is the proportion between the speed of the boat and speed of the water current and flow individually?
A)
2 : 1
B)
3 : 2
C)
8 : 3
D)
Can't be resolved

Correct Answer :   8 : 3


Explanation : Solution: At that point, remove canvassed upstream in 8 hrs. 48 min = Distance covered downstream in 4 hrs.
X* 8 4 /5= (y x 4)
44/5 x =4y
y = 11/5 x.
Required proportion = y + x/2: y - x /2
= 16/5 x 1/2: 6/5 x 1/2
= 8/5:3/5
= 8: 3.

21 .
3, 5, 11, 14, 17, 21
A)
3
B)
14
C)
17
D)
21

Correct Answer :   14


Explanation : Every one of the numbers aside from 14 is an odd number.
The number '14' is the main EVEN number.

22 .
10, 25, 45, 54, 60, 75, 80
A)
10
B)
45
C)
54
D)
75

Correct Answer :   54

23 .
396, 462, 572,427,671,264
A)
264
B)
291
C)
396
D)
427

Correct Answer :   427


Explanation : In each number except 427, the middle digit of the sum of other two.

24 .
16, 33, 65, 131, 261, (....)
A)
523
B)
545
C)
613
D)
721

Correct Answer :   523


Explanation : Each number is double the former one with 1 included or subtracted then again.
Along these lines, the following number is (2 x 261 + 1) = 523.

25 .
A vessel is loaded up with fluid, 3 sections of which are water and 5 sections syrup. What amount of the blend must be drawn off and supplanted with water so the blend might be half water and half syrup?
A)
1/3
B)
1/4
C)
1/5
D)
1/7

Correct Answer :   1/5

26 .
A man has Rs. 480 in the divisions of one-rupee notes, five-rupee notes and ten-rupee notes. The quantity of notes in every section is equivalent. What is the aggregate number of notes that he has?
A)
45
B)
60
C)
75
D)
90

Correct Answer :   90


Explanation : Give the number of notes of every division a chance to be x.
At that point x + 5x + 10x = 480
16x = 480 x = 30.
Consequently, add up to number of notes = 3x = 90

27 .
270 meters in length prepare running at the speed of 120 km ph crosses another prepare running inverse way at the speed of 80 km ph in 9 seconds. What is the length of the other prepare?
A)
210 m
B)
230 m
C)
240 m
D)
260 m

Correct Answer :   230 m


Explanation : Relative speed = (120 + 80) km/hr
= 200 x 5/18 m/sec
= 500/9 m/sec.

Give the length of the other prepare a chance to be x meters.
At that point, (X+270)/9=500/9
X+270=500
X=230

28 .
Merchandise prepares keeps running at the speed of 72 km ph and crosses a 250 m long stage in 26 seconds. What is the length of the products prepared?
A)
230 m
B)
240 m
C)
255 m
D)
270 m

Correct Answer :   270 m

29 .
Two Train, every 100 m long, moving in opposite Direction, cross each other in 8 seconds. On the off chance that one is moving twice as quick the other, at that point the speed of the speedier train is:
A)
60 km/hr
B)
75 km/hr
C)
85 km/hr
D)
95 km/hr

Correct Answer :   60 km/hr

30 .
An entirety of cash at basic premium adds up to Rs. 815 out of 3 years and to Rs. 854 out of 4 years. The aggregate is:
A)
Rs. 650
B)
Rs. 690
C)
Rs. 698
D)
Rs. 700

Correct Answer :   Rs. 698


Explanation : S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for a long time = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.

31 .
An organic product vendor had a few apples. He offers 40% apples and still has 420 apples. Initially, he had:
A)
588 apples
B)
600 apples
C)
672 apples
D)
700 apples

Correct Answer :   700 apples


Explanation : Assume initially he had x apples.
At that point, (100 - 40)% of x = 420.
60/100 x x = 420
x = 420 x 100 = 700.

32 .
A sum of money is to be distributed among A, B, C, D in the proportion of 5: 2: 4: 3. If C gets Rs. 1000 more than D, what is B's share?
A)
Rs.1000
B)
Rs.2000
C)
Rs.2500
D)
Rs.3000

Correct Answer :   Rs.2000

33 .
Three pipes A, B and C can fill a tank from void to full in 30 minutes, 20 minutes, and 10 minutes individually. At the point when the tank is unfilled, all the three funnels are opened. A, B and C release compound arrangements P, Q and R separately. What is the extent of the arrangement R in the fluid in the tank following 3 minutes?
A)
6/11
B)
7/11
C)
8/11
D)
9/11

Correct Answer :   6/11


Explanation : Part filled by (A + B + C) in 3 minutes = 3 (1/30+1/20+1/10)= 3*11/60=11/20
Required proportion = 3/10 x 20/11 = 6 /11

34 .
The Speed of a boat in standing water is 9 km ph and the speed of the stream is 1.5 km ph. A man lines to a place at a separation of 105 km, and returns to the beginning stage. The aggregate time taken by him is:
A)
32 hours
B)
24 hours
C)
20 hours
D)
18 hours

Correct Answer :   24 hours


Explanation : Speed upstream = 7.5 km ph.
Speed downstream = 10.5 km ph.
Add up to time taken = 105/7.5 + 105/10.5 hours = 24 hours.

35 .
A man has Rs. 480 in the sections of one-rupee notes, five-rupee notes, and ten-rupee notes. The quantity of notes in every section is equivalent. What is the aggregate number of notes that he has?
A)
60
B)
75
C)
90
D)
105

Correct Answer :   90


Explanation : Give the number of notes of every group a chance to be x.
At that point x + 5x + 10x = 480
16x = 480
x = 30.
Consequently, add up to number of notes = 3x = 90.

36 .
Statements: Prime age school-going youngsters in urban India have now turned out to be energetic and in addition more customary watchers of TV, even in family units without a TV. Thus there has been a disturbing decrease in the degree of the readership of daily papers.
Conclusions:
I. Technique for expanding the readership of daily papers ought to be conceived.
II. A group of specialists ought to be sent to different nations to ponder the effect of TV. On the readership of daily papers.
A)
Only conclusion I follow
B)
Only conclusion II follows
C)
Either I or II follows
D)
Neither I nor II follows

Correct Answer :   Neither I nor II follows


Explaination : The statement focuses on the expanding viewership of TV and does not pressure either on expanding the readership of daily papers or making thinks about with respect to the same. In this way, neither I nor II takes after.

37 .
(A) the predetermination of Asia will be formed by the triangular connection between the Asian countries, India, China, and Japan.
(B) India, China, and Japan which have enrolled a sensational development, in the course of the most recent decade specifically, has gone about as southern engine of development for the entire world.
A)
If statement (A) is the cause and statement (B) is its effect.
B)
If statement (B) is the cause and statement (A) is its effect.
C)
On the off chance that both the announcements (A) and (B) are impacts of independent clauses.
D)
On the off chance that both the announcements (An) and (B) are impacts of independent causes.

Correct Answer :   If statement (B) is the cause and statement (A) is its effect.


Explaination : Since the three nations are driving the monetary development of the entire world, they will shape the predetermination of Asia. Consequently, (B) is the reason and (An) is its impact.

38 .
Statements: Quality has a price tag. India is allocating lots of funds to education.
Conclusions:
I. Nature of instruction in India would enhance soon.
II. Subsidizing alone can improve the nature of instruction.
A)
Only conclusion I follow
B)
Only conclusion II follows
C)
Either I or || follow
D)
Neither I nor II follows

Correct Answer :   Only conclusion I follow

39 .
Fill the clear amidst the arrangement or end of the arrangement.
ELFA, GLHA, ILJA, _____, MLNA
A)
LLMA
B)
KLMA
C)
KLLA
D)
OLPA

Correct Answer :   KLLA

40 .
Look at this arrangement: 36, 34, 30, 28, 24, ... What number should come straightaway?
A)
20
B)
22
C)
24
D)
26

Correct Answer :   22


Explanation : The first difference is of 2
And the second difference is of 4
And the sequence continues so 24-2=22

41 .
Blueberries cost more than strawberries.
Blueberries cost more than raspberries.
Raspberries cost more than the two strawberries and blueberries.
If the initial two conditions are true, then the third condition is
A)
False
B)
Genuine
C)
Indeterminate
D)
None

Correct Answer :   Genuine


Explaination : Because the first two statements are true, raspberries are the most expensive of the three.

42 .
7 13 25 49 97 194 385. Find out the wrong number?
A)
13
B)
49
C)
97
D)
194

Correct Answer :   194

43 .
Find the number that can be put in place of the question mark. 3 12 7 26 15 b?
A)
35
B)
40
C)
45
D)
54

Correct Answer :   54


Explanation : (Logic: 3*2+1=7 12*2+2=26
7*2+1=15 26*2+2=54)

44 .
Pick the right elective that will proceed with a similar example and fill in the clear spaces:
1, 4, 9, 16, 25, (.....)
A)
36
B)
38
C)
42
D)
49

Correct Answer :   36

45 .
Find the number that can be put in place of the question mark
5, 6? 87, 412, 2185.
A)
13
B)
15
C)
18
D)
20

Correct Answer :   20

46 .
SCD, TEF, UGH, ____, WKL
A)
CMN
B)
UJI
C)
VIJ
D)
IJT

Correct Answer :   VIJ


Explanation : There are two in order arrangement here. The principal arrangement is with the main letters just: STUVW. The second arrangement includes the rest of the letters: CD, EF, GH, IJ, KL.

47 .
B2CD, _____, BCD4, B5CD, BC6D
A)
BC3D
B)
BCD7
C)
B2C2D
D)
B2C3D

Correct Answer :   BC3D


Explanation : Since the letters are the same, focus on the number arrangement, which is a basic 2, 3, 4, 5, 6 arrangement, and takes after each letter in order.

48 .
FAG, GAF, HAI, IAH, ____
A)
JAI
B)
JAK
C)
HAK
D)
HAL

Correct Answer :   JAK


Explanation : The center letters are static, so focus on the first and third letters. The arrangement includes a sequential request with an inversion of the letters. The main letters are in order arrange: F, G, H, I , J. The second and fourth fragments are inversions of the first and third sections. The missing section starts with another letter.

49 .
ELFA, GLHA, ILJA, _____, MLNA
A)
KLLA
B)
OLPA
C)
KLMA
D)
LLMA

Correct Answer :   KLLA


Explanation : The second and forward letters in the arrangement, L and A, are static. The first and third letters comprise of an in sequential order arrange to start with the letter E.

50 .
CMM, EOO, GQQ, _____, KUU
A)
ITT
B)
GSS
C)
ISS
D)
GRR

Correct Answer :   ISS


Explanation : The central letters are in successive request orchestrate with a letter skipped amidst each bit: C, E, G, I, K. The second and third letters are repeated; they are in like manner all together with a skipped letter: M, O, Q, S, U.