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ECE : Electronic Devices and Circuits - Quiz(MCQ)
A)
Intrinsic semiconductor
B)
Degenerated semiconductor
C)
Compound semiconductor
D)
Compensated semiconductor

Correct Answer :   Compound semiconductor


Explanation : LEDs need compound type semiconductors because they have direct band gap. In direct band gap, photons are easily generated when electrons release energy during recombination.

A)
Tin
B)
Silicon
C)
Selenium
D)
Germanium

Correct Answer :   Silicon


Explanation : Silicon is mostly used to construct electronic circuits because silicon has a much higher PIV (Peak Inverse Voltage) than the other semiconductors. It is also very cheap.

A)
ions
B)
holes
C)
electrons
D)
holes and electrons

Correct Answer :   holes and electrons


Explanation : Intrinsic material has equal number of holes and electrons.

A)
silicon
B)
germanium
C)
mixture of silicon and germanium
D)
None of the above

Correct Answer :   silicon


Explanation : Germanium is rarely used.

A)
PIN diode
B)
Tunnel diode
C)
Zener diode
D)
Schottky diode

Correct Answer :   Schottky diode


Explanation : In schottky diode there is no charge storage and hence almost zero reverse recovery time.

A)
100
B)
99
C)
1.01
D)
0.99

Correct Answer :   100


Explanation :

A)
A mobile
B)
A keyboard
C)
A magnifying glass
D)
A computer

Correct Answer :   A magnifying glass


Explanation : A mobile, a computer and a keyboard are electronics devices because they are controlled by the flow of electrons for information processing. A magnifying glass is a non-electronic device.

A)
Diode
B)
Temperature
C)
Inductor
D)
Capacitor

Correct Answer :   Temperature


Explanation : Capacitors, inductors, and diodes are the physical components of electronic circuits because they affect the flow of electrons or current in the circuit.

A)
They don’t emit light
B)
They excite electrons
C)
They have high thermal conductivity
D)
They have variable electrical conductivity

Correct Answer :   They don’t emit light


Explanation : Semiconductors excite electrons. They have variable electrical conductivity and high thermal conductivity. Some compound semiconductors also emit light which is popularly known as light-emitting diodes.

A)
Recombination rate is independent of temperature
B)
Recombination of electrons doesn’t occur in semiconductors
C)
Recombination rate increases with increase in the temperature
D)
Recombination rate decreases with increase in the temperature

Correct Answer :   Recombination rate decreases with increase in the temperature


Explanation : Recombination rate decreases when temperature increases because the electrons that are going to combine with holes in the valence bond are re-excited.

A)
frequency of incident radiation
B)
intensity of incident radiation
C)
both frequency and intensity of incident radiation
D)
None of the above

Correct Answer :   intensity of incident radiation


Explanation : Only the intensity of incident radiation governs the amount of photoelectric emission.

A)
drive in diffusion of dopants and carriers
B)
band to band transition is balanced by impurity ionization
C)
band to band transition dominants over impurity ionization
D)
impurity ionization dominants over band to band transition

Correct Answer :   band to band transition dominants over impurity ionization


Explanation : Covalent bonds are broken

A)
holes
B)
electrons
C)
both holes and electrons
D)
either holes or electrons

Correct Answer :   electrons


Explanation : Emitter is n type and emits electrons which diffuse through the base.

A)
towards negative terminal
B)
towards positive terminal
C)
either towards positive terminal or negative terminal
D)
towards positive terminal for 1 μs and towards negative terminal for next 1 μs

Correct Answer :   towards positive terminal


Explanation : Since electrons are negatively charged they will flow towards positive terminal.

A)
low resistivity
B)
low copper loss
C)
low eddy current loss
D)
higher specific gravity compared to iron

Correct Answer :   low resistivity


Explanation :

Ferrite is a low density material of composition with Fe2O3 x O, where x is a bivalent metal, such as Cobart, Ni, Mn. These magnetic materials having very low loss of current and used in high frequency circuit.

A)
0 to 200 Ω
B)
200 - 400 Ω
C)
200 Ω and above
D)
400 Ω and above

Correct Answer :   400 Ω and above


Explanation :

A)
1
B)
2
C)
3
D)
1 or 2

Correct Answer :   2


Explanation : A PIN diode has p and n doped regions separated by intrinsic layer.

A)
both junctions are forward biased
B)
both junctions are reverse biased
C)
one junction is forward biased and the other is reverse biased
D)
None of the above

Correct Answer :   one junction is forward biased and the other is reverse biased


Explanation : Emitter-base junction is forward biased and base collector junction is reverse biased.

A)
30 pA
B)
40 pA
C)
50 pA
D)
60 pA

Correct Answer :   40 pA


Explanation :

By increasing of temperature by 10°C, Io become double so by increasing temperature 20°C, Io become 4 time than initial value... and it is 40 PA.

A)
Doping is done in Intrinsic semiconductors
B)
Elemental semiconductors have direct band gap
C)
Compound semiconductors have indirect band gap
D)
Extrinsic semiconductors are injected with impurities

Correct Answer :   Extrinsic semiconductors are injected with impurities


Explanation : Elemental semiconductors have indirect band gap. Compound semiconductors have direct band gap. Doping is done with impurities in extrinsic semiconductors, not in intrinsic semiconductors.

A)
Impurity injection
B)
Photo excitation
C)
Impact ionization
D)
Thermal excitation

Correct Answer :   Impurity injection


Explanation : Electron-hole pairs can be generated by increasing temperature or ionization or photo excitation. Impurity injection is done for doping of semiconductors. This process doesn’t generate electron-hole pairs.

A)
Degenerated semiconductors behave like a conductor
B)
Electrons are present below Fermi level in a semiconductor
C)
Fermi level is independent of temperature and doping
D)
Pentavalent atoms are used in an n-type extrinsic semiconductor

Correct Answer :   Fermi level is independent of temperature and doping


Explanation : Fermi level is the highest level of electrons at 0K. Below Fermi level, all levels are filled with electrons. Fermi level depends on the temperature and the doping of the semiconductor.

A)
Hall voltage is directly proportional to the charge density
B)
Hall voltage is very weak in metals as compared to semiconductors
C)
Hall voltage is inversely proportional to the intensity of the magnetic field
D)
Intrinsic semiconductor has a positive temperature coefficient of hall constant

Correct Answer :   Hall voltage is very weak in metals as compared to semiconductors


Explanation : Metals have an ocean of electrons. So, there is very little difference between positive and negative charges in metals. Thus, Hall voltage is very weak in metals as compared to semiconductors.

A)
They are designed with abrupt junction
B)
Diodes with step-graded junctions are slower than a normal diode
C)
Depletion layer penetrates more into the lightly doped region
D)
None of the above

Correct Answer :   Diodes with step-graded junctions are slower than a normal diode


Explanation : Step-graded junctions are designed with abrupt junctions. They are either p+– n or p – n+ junction and diodes with step-graded junctions are faster than the normal diodes.

A)
Metals
B)
Insulators
C)
Semiconductors
D)
All of the above

Correct Answer :   Metals

A)
Drift of electrons
B)
Drift of holes
C)
Diffusion of electrons
D)
Diffusion of holes

Correct Answer :   Diffusion of holes

A)
Potential barrier
B)
Forward bias voltage
C)
Rate of thermal generation of electron hole pairs
D)
None of the above

Correct Answer :   Rate of thermal generation of electron hole pairs

A)
Loses its charge easily
B)
Jumps to the top of the crystal
C)
Has lower energy than the electron in the valence band
D)
Has higher energy than the electron in the valence band

Correct Answer :   Has higher energy than the electron in the valence band

A)
Thermometer
B)
Miniature resistance
C)
Thermocouple
D)
Heat sensitive explosive

Correct Answer :   Miniature resistance

A)
6 MOS transistor
B)
4 MOS transistor, 2 capacitor
C)
2 MOS transistor, 4 capacitor
D)
1 MOS transistor and 1 capacitor

Correct Answer :   6 MOS transistor

A)
Is constant
B)
Varies directly with current
C)
Varies inversely with current
D)
Is either constant or varies directly with current

Correct Answer :   Varies inversely with current

A)
Reverse, current
B)
Forward, voltage
C)
Reverse, voltage
D)
Forward, current

Correct Answer :   Reverse, voltage

A)
It is a photovoltaic cell
B)
P-N junction is connected in reverse bias.
C)
Electron-hole pairs are generated by impurity injection in depletion layer
D)
No external voltage is applied

Correct Answer :   P-N junction is connected in reverse bias.


Explanation : Photo diode is a photoconductive cell. External voltage is applied and P-N junction is connected in reverse bias. Electron-hole pairs are generated by photons in the depletion layer.

A)
It produces dark current
B)
It is a photovoltaic cell
C)
No external voltage is applied
D)
Solar cell responsivity is directly proportional to the wavelength of light

Correct Answer :   It produces dark current


Explanation : Solar cell is a photovoltaic cell. No external voltage is applied and solar cell responsivity is directly proportional to the wavelength of the incident light. It doesn’t produce dark current.

A)
It has N-substrate
B)
NMOS has holes as the majority of carriers
C)
For accumulation positive voltage is applied to the gate terminal
D)
For inversion positive voltage is applied to the gate terminal

Correct Answer :   For inversion positive voltage is applied to the gate terminal


Explanation : NMOS has P-substrate and it has electrons as the majority carriers. For accumulation negative voltage is applied to the gate terminal and for inversion positive voltage is applied to the gate terminal.

37 .
Which of the following is wrong about threshold voltage (VT) in a MOSFET electronic circuit?
A)
VT is independent of ion implementation
B)
If VT is less, channel form quickly for conductivity
C)
VT can be reduced by reducing substrate doping
D)
VT can be reduced by reducing oxide layer thickness

Correct Answer :   VT is independent of ion implementation


Explaination : VT can be reduced by suitable ion implementation. Like in NMOS, positive donor ions are implemented to reduce repulsion to the electrons present in the channel.

A)
Active
B)
Cut-off
C)
Saturation
D)
Reverse saturation

Correct Answer :   Reverse saturation


Explanation : In the active region, the emitter-base junction is forward biased, the collector-base junction is reversed biased. This is the operating mode when amplification of signals occurs in BJT.

A)
Extrinsic semiconductor
B)
Elemental semiconductor
C)
Degenerated semiconductor
D)
Compound semiconductor

Correct Answer :   Degenerated semiconductor


Explanation : Degenerative N-type and degenerative p-type semiconductors are used in tunnel diodes. Tunnel diodes are used in microwave electronic devices and circuits.

A)
has higher cut in voltage
B)
has lower cut in voltage
C)
lower reverse saturation current
D)
Both (A) and (C)

Correct Answer :   has lower cut in voltage


Explanation : Cut in voltage in Schottky diode is about 0.3 V as compared to 0.7 V in ordinary semiconductor diode.

41 .
Assertion (A) : When a high reverse voltage is applied to a p-n junction the diode breaks down.

Reason (R) : High reverse voltage causes Avalanche effect.
A)
A is true but R is false
B)
A is false but R is true
C)
Both A and R are true and R is correct explanation of A
D)
Both A and R are true but R is not a correct explanation of A

Correct Answer :   Both A and R are true and R is correct explanation of A


Explaination : Avalanche breakdown occurs at high reverse voltage.

A)
class B O/P stage
B)
class A O/P stage
C)
class AB output stage
D)
common pulse O/P state

Correct Answer :   class B O/P stage


Explanation : It is a characteristics of class B output stage as the amplifier is biased in cut-off region.

In class B amplifier, two transistor are operated in such a way that one is amplify the half cycle and second is amplify -ve half cycle.

A)
emitter is positive with respect to base
B)
collector is positive with respect to base
C)
base is positive with respect to emitter and collector is positive with respect to base
D)
None of the above

Correct Answer :   base is positive with respect to emitter and collector is positive with respect to base


Explanation : In forward active mode emitter base junction is forward biased and base collector junction is reverse biased.

A)
amplifier circuits
B)
voltage regulator circuit
C)
both voltage regulator and amplifier circuit
D)
None of the above

Correct Answer :   voltage regulator circuit


Explanation : Zener diode is used only in voltage regulator circuits.

A)
there are two p-n junctions
B)
the ratio v-i can be negative
C)
the forward current is very high
D)
sharp breakdown occurs at a certain reverse voltage

Correct Answer :   sharp breakdown occurs at a certain reverse voltage


Explanation : When reverse voltage equals breakdown value it starts conducting and voltage does not increase further.

A)
emitter current
B)
base current
C)
collector current
D)
base current or emitter current

Correct Answer :   emitter current


Explanation : Emitter current is larger, collector current is slightly less than emitter current and base current is very small.

A)
is in valence band
B)
is in conduction band
C)
is very near valence band
D)
is at the centre in between valence and conduction bands

Correct Answer :   is in conduction band


Explanation : This is due to high level of doping.

A)
1
B)
2
C)
3
D)
4

Correct Answer :   2


Explanation : Holes and electrons.

A)
0
B)
0.7 mA
C)
6.3 mA
D)
7 mA

Correct Answer :   6.3 mA


Explanation :

50 .
Calculate the stability factor and change in IC from 25°C to 100°C for, β = 50, RB/ RE = 250, ΔIC0 = 19.9 nA for emitter bias configuration.
A)
40.91, 0.58 μA
B)
40.91, 0.58 μA
C)
41.10, 0.39 μA
D)
42.53, 0.85 μA

Correct Answer :   42.53, 0.85 μA


Explaination :

A)
JFET
B)
MOSFET
C)
tunnel diode
D)
photo diode

Correct Answer :   MOSFET


Explanation : MOSFET may be depletion mode or enhancement mode.

A)
Active region
B)
Saturation region
C)
Breakdown region
D)
Both saturation and active region

Correct Answer :   Active region


Explanation : It is used as amplifier when it operates in this region.

A)
a non-linear v-i characteristics
B)
low forward and high reverse resistance
C)
zero forward current till the forward voltage reaches cut in value
D)
All of the above

Correct Answer :   All of the above


Explanation : A p-n Junction has all these features.

A)
Velocity of emitted electrons is dependent on light intensity
B)
Rate of photo emission is inversely proportional to light intensity
C)
Maximum velocity of electron increases with decreasing wave length
D)
Both holes and electrons are produced

Correct Answer :   Maximum velocity of electron increases with decreasing wave length


Explanation : As wavelength decreases, frequency increases and maximum velocity of electron increases.

A)
constant voltage region
B)
constant current region
C)
either constant voltage or constant current region
D)
both constant voltage and constant current regions

Correct Answer :   constant current region


Explanation : In major portion of drain characteristics ID is constant.

A)
emitter current and emitter to base voltage
B)
emitter current and collector to emitter voltage
C)
collector current and collector to emitter voltage
D)
None of the above

Correct Answer :   collector current and collector to emitter voltage


Explanation : Maximum power dissipation occurs at collector junction.

A)
ac property of the device at desired operating point
B)
dc property of the device at all operating points
C)
ac property of the device at all operating points
D)
complete ac and dc behaviour at all operating points

Correct Answer :   ac property of the device at desired operating point


Explanation : Incremental model is used for ac response at one operating point.

A)
UJT
B)
MOSFET
C)
PIN diode
D)
Tunnel diode

Correct Answer :   UJT


Explanation : Its output is used to trigger SCR.

59 .
Calculate the resistivity of n-type semiconductor from the following data, Density of holes = 5 x 1012 cm-3. Density of electrons = 8 x 1013 cm-3, mobility of conduction electron = 2.3 x 104 cm2/ V-sec and mobility of holes = 100 cm2/V-sec.
A)
0.24 Ω-m
B)
0.34 Ω-m
C)
0.42 Ω-m
D)
0.43 Ω-m

Correct Answer :   0.34 Ω-m


Explaination :

A)
are negatively charged
B)
are produced when indium is added as impurity to germanium
C)
are produced when phosphorus is added as impurity to silicon
D)
None of the above

Correct Answer :   are produced when phosphorus is added as impurity to silicon


Explanation : n type semiconductor is produced when pentavalent impurity is added.

A)
is constant in forward direction
B)
is constant in reverse direction
C)
is constant in both forward and reverse directions
D)
None of the above

Correct Answer :   is constant in reverse direction

A)
current flow by electrons as well as by holes
B)
resistivity decreases with increase in temperature
C)
conductivity decreases with increase in temperature
D)
the gap between valence and conduction bands is small

Correct Answer :   conductivity decreases with increase in temperature


Explanation : In all metals conductivity decreases (and resistance increases) with increase in temperature.

63 .
The threshold voltage of an n-channel enhancement mode MOSFET is 0.5 when the device is biased at a gate voltage of 3V. Pinch off would occur at a drain voltage of
A)
1.5 V
B)
2.5 V
C)
3.5 V
D)
4.5 V

Correct Answer :   2.5 V


Explaination : It is used with reverse bias.

A)
PIN diode
B)
Zener diode
C)
Photo diode
D)
Tunnel diode

Correct Answer :   Tunnel diode


Explanation : Tunnel diode has heavily doped p and n layers called degenerate p and n materials.

A)
reducing the switching time
B)
increasing the value of β
C)
reducing the base current
D)
reducing the power dissipation

Correct Answer :   reducing the switching time


Explanation : Schottky diode has very low switching time.

A)
shift in the Fermi level
B)
electrical polarization in the crystal
C)
magnetic dipoles in the crystal
D)
plastic deformation of the crystal

Correct Answer :   electrical polarization in the crystal


Explanation : In piezoelectric materials mechanical stress produces electric polarization.

A)
Schottky diode
B)
PIN diode
C)
Photo diode
D)
Tunnel diode

Correct Answer :   Schottky diode


Explanation : Schottky diode has very small depletion layer.

A)
will increase
B)
will decrease
C)
will decrease by an approximate factor of about 2
D)
will increase by an approximate factor of about 2

Correct Answer :   will decrease by an approximate factor of about 2


Explanation : Increase of reverse voltage widens the depletion layer and junction capacitance decreases. However the decrease in capacitance is not proportional to increase in voltage.

A)
volts
B)
siemens
C)
ohms
D)
amperes

Correct Answer :   siemens


Explanation : Its units are the same as the units of conductance.

A)
recovery time of stored carrier
B)
Fermi level and forbidden energy gap
C)
temperature coefficient and thermal conductivity
D)
type of conductivity and concentration of charge carriers

Correct Answer :   type of conductivity and concentration of charge carriers


Explanation : If a potential difference is developed across a current carrying metal strip when the strip is placed in transverse magnetic field.

Hall effect is very weak in metals, but it is large semiconductors.

A)
PIN diode
B)
Photodiode
C)
Tunnel diode
D)
Schottky diode

Correct Answer :   Tunnel diode


Explanation : Tunnel diode has heavily doped p and n regions leading to very thin depletion layer.

A)
the width of depletion layer decreases
B)
the width of depletion layer increases
C)
the current is very small
D)
the majority carriers move away from the junction

Correct Answer :   the width of depletion layer decreases


Explanation : Forward voltage decreases the width of depletion layer leading to low resistance.

A)
When the temperature decreases f(E) also increases
B)
f(E) doesn’t give the number of energy levels with electrons
C)
f(E) is the probability of finding an electron in an energy level E
D)
f(E) doesn’t give the number of electrons in a given energy level

Correct Answer :   When the temperature decreases f(E) also increases


Explanation : Fermi-Dirac distribution function f(E) is the probability of finding an electron in an energy level E. When temperature increases f(E) also increases.

A)
Elemental
B)
Degenerative
C)
Compound
D)
Compensated

Correct Answer :   Degenerative


Explanation : Mass action law is related to the concentration of electrons and holes in a semiconductor. Degenerative type semiconductors show similar behavior to metal. So, Mass action law is not valid for them.

75 .
Which of the following is the correct expression of current in an intrinsic semiconductor electronic circuit?
A)
ITotal = Ie + 2Ih
B)
ITotal = 2Ie + Ih
C)
ITotal = Ie – Ih
D)
ITotal = Ie + Ih

Correct Answer :   ITotal = Ie + Ih


Explaination : When electric field is applied to an intrinsic semiconductor, electrons and holes move in the opposite direction. So, the total current will be the sum of the current due to electrons and holes.

A)
They can act as ON-OFF switches
B)
They have three modes of operations
C)
They have dynamic resistance at low-frequency AC voltage
D)
They have diffusion capacitance at high-frequency AC voltage

Correct Answer :   They have three modes of operations


Explanation : P-N junction diodes have two modes of operations i.e. forward and reverse bias. Forward bias is called ON switch and reverse bias is called OFF switch.

A)
zero
B)
minimum
C)
maximum
D)
can’t be determined

Correct Answer :   zero


Explanation : At T = 0K, conductivity will be zero because donar level ionization is zero, so no free electron is there in the conduction band. Conductivity is measured when free electrons are present in the conduction band for conduction.

A)
Zero
B)
Minimum
C)
Maximum
D)
Can’t be determined

Correct Answer :   Maximum


Explanation :  At 300k, conductivity is maximum because of complete ionization of dopant levels which causes more free electrons conductivity in the conduction band.

A)
Thermal effect
B)
Electronic drift effect
C)
Lattice vibration effect
D)
Bandgap narrowing effect

Correct Answer :   Electronic drift effect


Explanation : With a very high amount of doping in degenerative type semiconductors, atoms come closer. For this reason, the interatomic interaction cannot be neglected. So, the effective band gap becomes narrow.

A)
Zener diode
B)
Schottky diode
C)
Varactor diode
D)
Tunnel diode

Correct Answer :   Tunnel diode


Explanation : Due to tunneling, a large number of electrons penetrate through the junction, so a large amount of current is produced. And as we are considering a special diode, we can control its I-V characteristics to improve the switching speed.

A)
Silicon diodes
B)
Germanium diodes
C)
Either of the above
D)
None of the above

Correct Answer :   Silicon diodes

A)
Wideband gap semiconductor
B)
Narrowband gap semiconductor
C)
Direct band gap semiconductor
D)
An indirect band gap semiconductor

Correct Answer :   An indirect band gap semiconductor

A)
Hard drawn copper
B)
Pure annealed copper
C)
Induction hardened copper
D)
Copper containing traces of silicon

Correct Answer :   Pure annealed copper

A)
First band
B)
Second band
C)
Third band
D)
Conduction band

Correct Answer :   Conduction band

A)
For full cycle
B)
For less than fourth cycle
C)
Only for the positive half cycle of the input signal
D)
Only for the negative half cycle of the input signal

Correct Answer :   Only for the positive half cycle of the input signal

A)
holes
B)
free electrons
C)
free electrons or holes
D)
free electrons and holes

Correct Answer :   free electrons

A)
hole
B)
electron
C)
immobile charges
D)
None of the above

Correct Answer :   immobile charges

A)
recombine with electrons in base
B)
recombine with electrons in emitter
C)
diffuse through base into collector region
D)
None of the above

Correct Answer :   diffuse through base into collector region

89 .
Assertion (A): Silicon is preferred over germanium in manufacture of semiconductor devices.

Reason (R): Forbidden gap in silicon is more than that in germanium.
A)
A is true but R is false
B)
A is false but R is true
C)
Both A and R are true but R is not a correct explanation of A
D)
Both A and R are true and R is correct explanation of A

Correct Answer :   Both A and R are true and R is correct explanation of A


Explaination : Wider forbidden gap in silicon makes it less sensitive to temperature than germanium.

A)
conductor
B)
slightly conducting
C)
perfect insulator
D)
Any of the above

Correct Answer :   slightly conducting


Explanation : At 0 K a semiconductor is perfect insulator. At room temperature it is slightly conducting.

91 .
A diode is operating in forward region and the forward voltage and current are v = 3 + 0.3 sin ωt (volts) and i = 5 + 0.2 sin ωt (mA). The average power dissipated is
A)
1.5 mW
B)
15 mW
C)
about 15 mW
D)
about 1.5 mW

Correct Answer :   about 15 mW


Explaination : The contribution of sine terms to power dissipation is zero.

92 .
For BJT transistor. The maximum power dissipation is specified as 350 mW if ambient temperature is 25°C. If ambient temperature is 60°C the maximum power dissipation should be limited to about
A)
100 mW
B)
250 mW
C)
450 mW
D)
600 mW

Correct Answer :   250 mW


Explaination : 350 - 2.5 (60 - 25) ∼ 250 mW.

A)
temperature
B)
the applied bias
C)
the extent of doping
D)
None of the above

Correct Answer :   temperature


Explanation : Minority carriers are generated due to thermal excitation.

A)
Silver
B)
Tungsten
C)
Platinum
D)
Aluminium

Correct Answer :   Silver


Explanation : Silver has highest conductivity (and lowest resistivity) in all metals.

A)
base can be easily biased
B)
base can be easily fabricated
C)
electric field gradient in base is high
D)
recombination in base region is minimum

Correct Answer :   recombination in base region is minimum


Explanation :

Since recombination in base region is minimum, I - IE.

A)
higher voltage gain
B)
lower input impedance
C)
high input impedance and high voltage gain
D)
high input impedance and low voltage gain

Correct Answer :   high input impedance and low voltage gain


Explanation : JFET is voltage controlled device. Therefore its input impedance is high. But voltage gain is lower than in BJT.

A)
almost flat
B)
inclined upwards
C)
inclined downwards
D)
inclined upwards or downwards

Correct Answer :   almost flat


Explanation : The drain current is almost constant. Therefore, characteristics is flat.

A)
the forbidden energy gap in silicon and germanium increase
B)
the forbidden energy gap in silicon and germanium decrease
C)
the forbidden energy gap in silicon increases while that in germanium decreases
D)
the forbidden energy gap in silicon decreases while that in germanium decreases

Correct Answer :   the forbidden energy gap in silicon and germanium decrease


Explanation : Therefore, conductivity increases.

A)
decreases
B)
remains the same
C)
increases
D)
may be increase or decrease

Correct Answer :   increases


Explanation : Therefore, the resistance is very high.

A)
JFET
B)
MOSFET
C)
Tunnel diode
D)
NPN transistor

Correct Answer :   MOSFET


Explanation : The SiO2 layer provides very high input impedance.

A)
Holes and electrons recombine
B)
Holes constitute positive charges
C)
Holes exist only in semiconductors
D)
Holes exist in conductors as well as semiconductors

Correct Answer :   Holes exist in conductors as well as semiconductors


Explanation : Holes do not exist in conductors.

A)
wave length of incident radiation is less than threshold value
B)
wave length of incident radiation is equal to threshold value
C)
frequency of incident radiation is less than threshold frequency
D)
None of the above

Correct Answer :   wave length of incident radiation is less than threshold value


Explanation : The frequency of incident radiation has to be more than threshold value. Wavelength is inversely proportional to frequency.

Therefore wavelength of incident radiation must be less than threshold value.

A)
shift in the Fermi level
B)
magnetic Dipoles in the crystal
C)
electric polarization in the crystal
D)
plastic deformation of the crystal

Correct Answer :   electric polarization in the crystal


Explanation : Commonly material used as piezoelectric crystal is Barium Nitrate. Generally ferroelectric crystals and piezoelectric.

A)
is about 0.1
B)
is about 0.4
C)
is always equal to 1
D)
is less than 1 but more than 0.9

Correct Answer :   is less than 1 but more than 0.9


Explanation : A is about 0.98.

A)
PIN diode
B)
Zener diode
C)
Photo diode
D)
Schottky diode

Correct Answer :   PIN diode


Explanation : p layer, i layer and n layer.

106 .
For an P-channel enhancement type MOSFET determine the drain current if K = 0.278 x 10-3A/V2, VGS = -4V, VT = -2V, Voltage equivalent at 27°C = 26 mV.
A)
0.751 mA
B)
1.11 mA
C)
10 mA
D)
46.98 mA

Correct Answer :   1.11 mA


Explaination :

Drain current Id  = k (|Vgs| - |VT|)2

= 0.278 x 10-3(4 - 2)2

= 1.11 mA.

107 .
The skin depth of copper is found to be 66 mm at 1 MHz at a certain temperature. At the same temperature and at 2 MHz, the skin depth would be approximately
A)
33 μm
B)
47 μm
C)
92 μm
D)
1.22 μm

Correct Answer :   47 μm

A)
Zener diode
B)
Tunnel diode
C)
Varactor diode
D)
Schottky diode

Correct Answer :   Varactor diode


Explanation : Band pass filter depends upon the value of the resistance and capacitance. In varactor diode, we can obtain capacitance by varying the input voltage. As capacitance becomes adjustable, it can be considered as an adjustable band pass filter.

A)
Electron affinity
B)
Interatomic distance
C)
Material constant
D)
Recombination and Generation

Correct Answer :   Interatomic distance


Explanation : Forbidden energy gap (EG) of a semiconductor is directly proportional to the bond strength. And bond strength depends on the interatomic distance.

110 .
Which of the following is the correct order of turn-off times?
A)
MOSFET < BJT < IGBT < SCR
B)
MOSFET < IGBT < BJT < SCR
C)
SCR < BJT < IGBT < MOSFET
D)
BJT < MOSFET < IGBT < SCR

Correct Answer :   MOSFET < BJT < IGBT < SCR


Explaination : Electronic devices like MOSFET have the lowest turn-off times (nanoseconds). BJT has turn-off times in between nanoseconds to microseconds. IGBT and SCR have turn-off times of about 1 and 5 microseconds respectively.

A)
BJT
B)
FET
C)
JFET
D)
MOSFET

Correct Answer :   MOSFET


Explanation : MOSFET is preferred in digital and analog electronic circuits because it is faster than all other transistors. Also, it has a very high input impedance.

A)
Inverted charge remain constant
B)
Potential in the channel decreases from source to drain
C)
Inverted change in the channel decreases from source to drain
D)
Inverted change in the channel increases from source to drain

Correct Answer :   Inverted change in the channel decreases from source to drain


Explanation : When the depletion layer starts moving into the channel, due to the reverse bias of drain and substrate voltage, the inverted charge in the channel decreases from source to drain.

A)
It is lightly doped
B)
It is used in forward bias
C)
It has avalanche breakdown
D)
It is mostly used in voltage regulator electronic circuits

Correct Answer :   It is mostly used in voltage regulator electronic circuits


Explanation : Zener diode is a heavily doped diode. It is used in reverse bias. It has Zener breakdown. It is used in voltage regulators because it passes an excess amount of current in breakdown mode by maintaining constant voltage across the load.

A)
Active
B)
Cut-off
C)
Saturation
D)
Reverse saturation

Correct Answer :   Saturation


Explanation : In the saturation region, the emitter-base junction is forward biased, the collector-base junction is also forward biased. This is the operating mode when no current flows through BJT.

A)
Only those produced by doping
B)
Only those produced by thermal energy
C)
Those produced by doping as well as thermal energy
D)
Any of the above

Correct Answer :   Only those produced by thermal energy

A)
Intrinsic semiconductor
B)
Highly doped semiconductor
C)
Lightly doped semiconductor
D)
Either (A) or (B)

Correct Answer :   Lightly doped semiconductor

A)
Forward bias
B)
Zero bias
C)
Reverse bias
D)
Zero or reverse bias

Correct Answer :   Forward bias

A)
Increases with heavy doping
B)
Decreases with light doping
C)
Is independent of applied voltage
D)
Is increased under reverse bias

Correct Answer :   Is increased under reverse bias

119 .
An intrinsic silicon sample has 1 million free electrons at room temperature. As the temperature is increased
A)
The number of free electrons increases
B)
The number of free electrons and holes increase by the same amount
C)
The number of free electrons increases but the number of holes decreases
D)
The number of free electrons and holes increase but not by the same amount

Correct Answer :   The number of free electrons and holes increase by the same amount

A)
Diode will emit light
B)
All electrons will leave
C)
All holes will freeze
D)
Excessive heat may damage the diode

Correct Answer :   Excessive heat may damage the diode

A)
Air
B)
Mica
C)
Mineral oil
D)
Paraffin wax

Correct Answer :   Air

A)
I
B)
0
C)
less than I
D)
0.5

Correct Answer :   less than I


Explanation : Small current due to minority carriers also. Therefore hole current is less than.

A)
Saturation and active
B)
Cut off and saturation
C)
Cut off and forward active
D)
Forward active and cut off

Correct Answer :   Cut off and saturation


Explanation : In cut off mode a BJT is an open switch and in saturation mode it is a closed switch.

A)
photo voltaic device
B)
photo resistive device
C)
photo emissive device
D)
Either (A) or (C)

Correct Answer :   photo resistive device


Explanation : Resistance of LDR depends on light.

A)
is very small
B)
may destroy the diode
C)
is almost constant
D)
decreases with increase in current

Correct Answer :   is almost constant


Explanation : Therefore, it is used in voltage regulator circuits.

A)
tuning
B)
rectification
C)
amplification
D)
rectification and amplification

Correct Answer :   tuning


Explanation : Its voltage dependent capacitance is used for tuning.

127 .
Assertion (A) : When VDS is more than rated value the drain current in a JFET is very high.

Reason (R) : When VDS is more than rated value, avalanche breakdown occurs.
A)
A is true but R is false
B)
A is false but R is true
C)
Both A and R are true and R is correct explanation of A
D)
Both A and R are true but R is not a correct explanation of A

Correct Answer :   Both A and R are true and R is correct explanation of A


Explaination : Avalanche breakdown causes high current.

A)
insulators
B)
conductors
C)
both conductor and semiconductor
D)
semiconductors

Correct Answer :   conductors


Explanation : This is the reason for high conductivity of conductors.

A)
a change in S.C. current
B)
a change in O.C. voltage
C)
an increase in resistance
D)
a decrease in resistance

Correct Answer :   a decrease in resistance


Explanation : Increase in illumination reduces resistance of a photoconductor.

A)
0
B)
1
C)
2
D)
1 or 2

Correct Answer :   1


Explanation : Semiconductor diode has one p-n junction, BJT has two and SCR has three p-n junctions.

A)
zero
B)
reverse
C)
forward
D)
zero or reverse

Correct Answer :   zero or reverse


Explanation : Diode conducts only when forward biased. There is no conduction when bias is zero or reverse.

A)
5 kHz
B)
15 kHz
C)
20 kHz
D)
30 kHz

Correct Answer :   5 kHz


Explanation : For inverter grade SCR, typical turn off time (toff) is 5 to 50 μsec while 50 to 100 μsec for converter grade SCR.

Hence supply frequency of 5 kHz will turn off the SCR by voltage reversal because 1/5KHz = 200 μsec.

A)
2
B)
3
C)
4
D)
5

Correct Answer :   5


Explanation : Therefore, it can donate one electron.

A)
a fixed inductance
B)
a fixed capacitance
C)
a voltage variable capacitance
D)
a current variable inductance

Correct Answer :   a voltage variable capacitance


Explanation : The applied bias governs the width of depletion layer. Therefore, capacitance varies with bias.

A)
flash point and viscosity
B)
dielectric strength, flash point and viscosity
C)
dielectric strength and viscosity
D)
dielectric strength and flash point

Correct Answer :   dielectric strength, flash point and viscosity


Explanation : Oil used in transformer work as cooling as well as dielectric strength.

136 .
A voltage of 9 V is applied in forward direction to a semiconductor diode in series with a load resistance of 1000 Ω. The voltage across the load resistance is zero. It indicates that
A)
diode is short circuited
B)
diode is open circuited
C)
resistor is open circuited
D)
diode is either o.c or s.c

Correct Answer :   diode is open circuited


Explaination : Since there is no voltage across load resistor, the current is zero and diode is open-circuit. If diode is short- circuited or resistor is open-circuited almost 9 V will appear across resistor.

A)
0.05
B)
0.5
C)
50
D)
500

Correct Answer :   0.05

A)
0.5 mW/°C
B)
2.5 mW/°C
C)
10 mW/°C
D)
25 mW/°C

Correct Answer :   2.5 mW/°C


Explanation : For every 1°C rise in ambient temperature the power dissipation must be reduced by 2.5 mW so that transistor is safe.

A)
2 million
B)
almost zero
C)
more than 2 million
D)
less than 2 million

Correct Answer :   2 million


Explanation : In intrinsic semiconductor, the number of free electrons is equal to number of holes.

A)
number of free electrons and holes are equal
B)
number of holes is greater than the number of free electrons
C)
number of free electrons is much greater than the number of holes
D)
number of free electrons may be equal or less than the number of holes

Correct Answer :   number of free electrons is much greater than the number of holes


Explanation : Therefore, in n type semiconductor electrons are majority carriers.

141 .
In an n type semiconductor the fermi level is 0.35 eV below the conduction band, the concentration of donor atoms is increased to three times. The new position of Fermi level will be
A)
0.35 eV below conduction band
B)
about 0.32 eV below conduction band
C)
about 0.1 eV below conduction band
D)
about 0.32 eV above conduction band

Correct Answer :   about 0.32 eV below conduction band


Explaination : Therefore, conductivity increases.

A)
recombination in base regions of both n-p-n and p-n-p transistor is low
B)
recombination in base regions of both n-p-n and p-n-p transistors is high
C)
recombination in base region of n-p-n transistor is low but that in p-n-p transistor is high
D)
recombination in base region of p-n-p transistor is low but that in n-p-n transistor is high

Correct Answer :   recombination in base regions of both n-p-n and p-n-p transistor is low


Explanation : Base is very thin and therefore recombination is minimum in both p-n-p and n-p-n transistors.

A)
1
B)
2
C)
3
D)
4

Correct Answer :   3


Explanation : p, n, p or n, p, n.

A)
visible region of the spectrum
B)
infrared region of the spectrum
C)
ultraviolet region of the spectrum
D)
for ultraviolet region of the spectrum

Correct Answer :   infrared region of the spectrum


Explanation : GaAs has very large band gap and high carrier mobility.

A)
LED
B)
Diode
C)
Zener diode
D)
Varactor diode

Correct Answer :   Varactor diode


Explanation : Therefore, varactor is used for tuning in TV.

A)
zero
B)
minimum
C)
maximum
D)
equal to rated value

Correct Answer :   zero


Explanation : i is plotted on y-axis and v on x-axis. When passing through origin current can be zero only.

A)
LED
B)
photovoltaic cell
C)
photo electric relay
D)
photo sensitive device

Correct Answer :   photo sensitive device


Explanation : The resistance of photosensitive device depends on the light.

148 .
Which of the following expressions represents the correct distribution of the electrons in the conduction band? (gc(E)=density of quantum states, fF(E)=Fermi dirac probability
A)
n(E)=gc(E)*fF(E)
B)
n(E)=gc(E)*fF(-E)
C)
n(E)=gc(-E)*fF(E)
D)
n(E)= gc(-E)*fF(-E)

Correct Answer :   n(E)=gc(E)*fF(E)


Explaination : The distribution of the electrons in the conduction band is given by the product of the density into Fermi-dirac distribution.

A)
fF(E)=exp(-[EF-E]/KT)
B)
fF(E)=exp([E-EF]/KT)
C)
fF(E)=exp(-[E-EF]/KT)
D)
fF(E)=exp(-[EF-E]/KT)

Correct Answer :   fF(E)=exp(-[EF-E]/KT)


Explanation : It is the correct formula for the Fermi probability function.

A)
Factor of 1
B)
Factor of 2
C)
Factor of 3
D)
Factor of 4

Correct Answer :   Factor of 2


Explanation : This is practically proved.

A)
Extrinsic
B)
Elemental
C)
Intrinsic
D)
Compound

Correct Answer :   Intrinsic


Explanation : In the intrinsic semiconductor, ni=pi that is the number of the electrons is equal to the number of the holes. Whereas in the extrinsic conductor ni is not equal to pi.

A)
m
B)
Ω
C)
Ωm
D)
(Ωm)-1

Correct Answer :   (Ωm)-1


Explanation : The formula of the conductivity is the σ=1/ρ.

So, the unit of resistivity is Ωm.

Now, the unit of conductivity becomes the inverse of resistivity.

A)
J=σE
B)
J=µE
C)
J=qnµE
D)
None of the above

Correct Answer :   J=µE


Explanation : The following formulae represent the correct expression for drift current density,
J=σE
And J=qnµE.

A)
Lower range
B)
Middle range
C)
Higher range
D)
None of the above

Correct Answer :   Lower range


Explanation : At lower range of temperature, the concentration and conductivity decreases with lowering of the temperature.

A)
0.5V/m
B)
5V/m
C)
50V/m
D)
None of the above

Correct Answer :   50V/m


Explanation : E=V/L=5/100cm=5V/m.

A)
38eV
B)
3.8eV
C)
0.38eV
D)
0.038eV

Correct Answer :   0.038eV


Explanation : Average random thermal energy=3/2*k*T=0.038eV.

A)
Forward biased
B)
Equilibrium
C)
Reverse biased
D)
Schottky barrier

Correct Answer :   Forward biased


Explanation : When a positive terminal is connected to the anode, the diode is forward biased which lets the flow of the current in the circuit.

A)
Active current
B)
Reverse current
C)
Forward current
D)
Reverse saturation current

Correct Answer :   Reverse saturation current


Explanation : When the diode is reverse biased, a small current flows between the p-n junction which is of the order of the Pico ampere. This current is known as reverse saturation current.

159 .
What is the maximum electric field when Vbi=2V , VR=5V and width of the semiconductor is 7cm?
A)
-100V/m
B)
-200V/m
C)
100V/m
D)
200V/m

Correct Answer :   -200V/m


Explaination : Emax=-2(Vbi+VR)/W
=-2(2+5)/ (7*10-2)
=-200V/m.

A)
V*I
B)
V/I
C)
V+I
D)
V-I

Correct Answer :   V/I


Explanation : According to Ohms law the electric current in the circuit is directly proportion to voltage and inversely proportional to resistance so, R=V/I.

161 .
In the volt ampere characteristics of the diode, the slope of the line joining the operating point to the origin at any point is equal to reciprocal of the _________
A)
voltage
B)
current
C)
resistance
D)
conductance

Correct Answer :   resistance


Explaination : In the diode’s volt ampere characteristics, the line joining the operating point and the origin, at any point of the line is equal to the conductance so, it is reciprocal of the resistance.

162 .
At room temperature (VT = 26) what will be the approximate value of r when n=1 and I=100mA?
A)
2.6 ohms
B)
26 ohms
C)
260 ohms
D)
2600 ohms

Correct Answer :   260 ohms


Explaination : We know that R= (n*VT) /I, by substituting the value of n, VT, I we get R= 260 ohms, (1*26)/100*10-3 = 260 ohms.

163 .
In the diode volt ampere characteristics what will be the resistance if a slope is drawn between the voltages 50 to 100 and corresponding current 5 to 10?
A)
5 ohms
B)
10 ohms
C)
50 ohms
D)
100 ohms

Correct Answer :   10 ohms


Explaination : We know that, in volt ampere characteristics the resistance is equal to the reciprocal of the line joining the origin and operating point, R = dV/dI, by substituting the value of dV and dI we get R= 10ohms.

A)
cut off voltage
B)
leakage voltage
C)
threshold voltage
D)
saturation voltage

Correct Answer :   threshold voltage


Explanation : The diode made up of semiconductor has a certain threshold voltage only after which it behave as closed circuit in the sense it performs some operation if the threshold voltage is greater than the voltage in circuit.

A)
25mV at 180K
B)
25mV at 300K
C)
30mV at 180K
D)
30mV at 300K

Correct Answer :   25mV at 300K


Explanation : We know that the thermal voltage of diode is approximately equal to room temperature which is 300K then for all practical purpose the thermal voltage of diode is taken as 25mV so it will be 25mV at 300K.

A)
0 ohms
B)
0.3 ohms
C)
0.7 ohms
D)
1 ohms

Correct Answer :   0 ohms


Explanation : When the current in the circuit is zero there will be no flow of charges to resist hence the diode resistance will be zero.

A)
Perfect insulator when reverse bias
B)
Perfect conductor when forward bias
C)
Zero voltage across it when forward bias
D)
Zero current through it when forward bias

Correct Answer :   Zero current through it when forward bias


Explanation : The diode acts as an ideal diode when it is a perfect conductor and has zero voltage across it during forward bias, a perfect insulator and zero current through it during reverse bias.

168 .
Compared to a PN junction with NA=1014/CM3, which one of the following is true for NA=ND= 1020/CM3?
A)
depletion capacitance increases
B)
depletion capacitance decreases
C)
depletion capacitance remains same
D)
depletion capacitance can’t be predicted

Correct Answer :   depletion capacitance increases


Explaination : We know, CT=Aε/W and
W ∝ (1/NA+1/ND) 1/2. So, CT ∝ (1/NA+1/ND)-1/2
So when NA and ND increases, depletion capacitance CT increases.

169 .
The built in capacitance V0 for a step graded PN junction is 0.75V. Junction capacitance Cj at reverse bias when VR=1.25V is 5pF. The value of Cj when VR=7.25V is?
A)
0.1pF
B)
1pF
C)
1.7pF
D)
2.5Pf

Correct Answer :   2.5Pf


Explaination : We know, Cj1/ Cj2=[(V0+VR2)/(V0+VR2)]1/2
So, Cj2=Cj1/ {(0.75+7.25)/(0.75+1.25)}1/2 we get Cj2=Cj1 /2 =5/2=2.5Pf.

A)
decreases with increasing current and increasing temperature
B)
increasing with increasing current and increasing temperature
C)
decreases with decreasing current and increasing temperature
D)
doesnot depend on current and temperature

Correct Answer :   decreases with decreasing current and increasing temperature


Explanation : CD =τ I /n0 VT
Where, I is the current and VT is temperature factor. The diffusion capacitance is directly proportional to current and indirectly proportional to the temperature.

A)
diffusion capacitance
B)
depletion capacitance
C)
resistive capacitance
D)
conductance capacitance

Correct Answer :   depletion capacitance


Explanation : Transition capacitance occurs in reverse bias. We obtain a depletion layer in that case. Hence it’s also called as depletion capacitance. The diffusion capacitance occurs in forward bias.

A)
It does not allow the flow of current in reverse bias
B)
It allows the passage of current in the forward bias with zero potential drop across the diode
C)
All of the mentioned
D)
None of the above

Correct Answer :   All of the mentioned


Explanation : Both of the facts mentioned hold true for an ideal operational amplifier.

A)
Rectifiers
B)
LED lamps
C)
Logic gates
D)
All of the above

Correct Answer :   All of the above


Explanation : Diodes are used to make rectifiers (full wave or half wave rectifiers are the most common examples), LED lamps uses diodes (diodes are generally doped for their use in this purpose) and logic gates can also be made using diodes using the fact that diodes are conducting only in the forward biased configuration.

A)
mA and µA respectively
B)
mA and mA respectively
C)
µA and µA respectively
D)
µA and mA respectively

Correct Answer :   mA and µA respectively


Explanation : The currents in forward bias is generally in MA and in the reverse bias it is very small and is generally measured in µA.

A)
Peak Rectifier
B)
Bridge Rectifier
C)
Precision Half-wave Rectifier
D)
None of the above

Correct Answer :   None of the above


Explanation : All of the mentioned are different types of a rectifier.

A)
Equal to the input voltage
B)
Smaller than the input voltage
C)
Greater than the input voltage
D)
Greater than the input voltage for full wave rectifier and smaller for the half wave rectifier

Correct Answer :   Smaller than the input voltage


Explanation : The peak input voltage is smaller than the input voltage due to the presence of diode(s). A single diode reduces the output voltage by approximately 0.7V.

A)
Peak rectifier
B)
Half wave rectifier
C)
Full wave rectifier
D)
None of the above

Correct Answer :   Full wave rectifier


Explanation : Bridge rectifier is a better alternative for a full wave rectifier.

A)
The output voltage for the center tapped rectifier is lower than the identical bridge rectifier
B)
A transistor of higher number of coil is required for center tapped rectifier than the identical bridge rectifier
C)
The peak inverse voltage or PIV for the bridge rectifier is lower when compared to an identical center tapped rectifier
D)
All of the above

Correct Answer :   All of the above


Explanation : All of the given statements are true for a bridge rectifier.

179 .
The diode rectifier works well enough if the supply voltage is much than greater than 0.7V. For smaller voltage (of few hundreds of millivolt) input which of the following can be used?
A)
Superdiode
B)
Peak rectifier
C)
Precision rectifier
D)
None of the above

Correct Answer :   Superdiode


Explaination : For the supply voltages less than 0.7V super diodes are used.

A)
46%
B)
50%
C)
70%
D)
81.2%

Correct Answer :   81.2%


Explanation : Efficiency of a rectifier is the effectiveness to convert AC to DC. It’s obtained by taking ratio of DC power output to maximum AC power delivered to load. It’s usually expressed in percentage. For centre tapped full wave rectifier, it’s 81.2%.

A)
1V
B)
2V
C)
3V
D)
4V

Correct Answer :   2V


Explanation : We know that, PDC=VDC2/RL. So, VDC=(PDC*RL)1/2=100001/2=100V.
Here, ϒ=0.02
ϒ=VAC/VDC=VAC/100.So, VAC=0.02*100=2V.

182 .
In a centre tapped full wave rectifier, RL=1KΩ and for diode Rf=10Ω. The primary voltage is 800sinωt with transformer turns ratio=2. The ripple factor will be _________
A)
26%
B)
48%
C)
54%
D)
81%

Correct Answer :   48%


Explaination : The ripple factor ϒ= [(IRMS/IAVG)2 – 1]1/2. IRMS =Im /√2=Vm/(Rf+RL)√2=200/1.01=198.
(Secondary line to line voltage is 800/2=400. Due to centre tap Vm=400/2=200)
IRMS=198/√2=140mA, IAVG=2*198/π=126mA. ϒ=[(140/126)2-1]1/2=0.48. So, ϒ=48%.

A)
25Hz
B)
50Hz
C)
100Hz
D)
500Hz

Correct Answer :   100Hz


Explanation : In the output of the centre tapped rectifier, one of the half cycle is repeated. The frequency will be twice as that of input frequency. So, it’s 100Hz.

A)
0.623
B)
0.625
C)
0.678
D)
0.693

Correct Answer :   0.693


Explanation : Transformer utilisation factor is the ratio of AC power delivered to load to the DC power rating. This factor indicates effectiveness of transformer usage by rectifier. For a half wave rectifier, it’s low and equal to 0.693.

A)
25Hz
B)
50Hz
C)
100Hz
D)
200Hz

Correct Answer :   100Hz


Explanation : The equation of sine wave is in the form Vmsinωt. So, by comparing we get ω=100. Frequency, f =ω/2=50Hz. The output of centre tapped full wave rectifier has double the frequency of inpu. Hence, fout = 100Hz.

A)
The property of capacitor to store electrical energy
B)
The current passing through the capacitor
C)
Uniform charge flow through the rectifier
D)
The voltage variations produced by shunting the capacitor

Correct Answer :   The property of capacitor to store electrical energy


Explanation : Filtering is frequently done by shunting the load with capacitor. It depends on the fact that a capacitor stores energy when conducting and delivers energy during non conduction. Throughout this process, the ripples are eliminated.

A)
The instant at which the conduction stops
B)
The instant at which the conduction starts
C)
The time after which the output is not filtered
D)
The time during which the output is perfectly filtered

Correct Answer :   The instant at which the conduction starts


Explanation : The capacitor charges when the diode is in ON state and discharges during the OFF state of the diode. The instant at which the conduction starts is called cut-in point. The instant at which the conduction stops is called cut-out point.

A)
Mixer
B)
Switch
C)
Oscillator
D)
Voltage regulator

Correct Answer :   Switch


Explanation : The diode permits charge to flow in capacitor when the transformer voltage exceeds the capacitor voltage. It disconnects the power source when the transformer voltage falls below that of a capacitor.

189 .
A half wave rectifier, operated from a 50Hz supply uses a 1000µF capacitance connected in parallel to the load of rectifier. What will be the minimum value of load resistance that can be connected across the capacitor if the ripple% not exceeds 5?
A)
114.87Ω
B)
115.47Ω
C)
167.98Ω
D)
451.35Ω

Correct Answer :   115.47Ω


Explaination : For a half wave filter,
ϒ=1/2√3 fCRL=1/2√3*50*10-3*RL
RL=103/5√3=115.47Ω.

190 .
A full wave rectifier uses a capacitor filter with 500µF capacitor and provides a load current of 200mA at 8% ripple. Calculate the dc voltage.
A)
11.98V
B)
14.43V
C)
15.56V
D)
20.43V

Correct Answer :   14.43V


Explaination : The ripple factor ϒ=IL/ 4√3 fCVDC
VDC=200*10-3/ 4√3 *50*500*8
=14.43.

A)
It is electrolytic
B)
It is connected in parallel to load
C)
It helps in storing the magnetic energy
D)
It is also called as capacitor output filter

Correct Answer :   It is electrolytic


Explanation : The rectifier may be full wave or half wave. The capacitors are usually electrolytic even though they are large in size.

192 .
A shunt capacitor of value 500µF fed rectifier circuit. The dc voltage is 14.43V. The dc current flowing is 200mA. It is operating at a frequency of 50Hz. What will be the value of peak rectified voltage?
A)
11.43V
B)
15.98V
C)
16.43V
D)
18.67V

Correct Answer :   16.43V


Explaination : We know, Vm=Vdc+Idc/4fC
=14.43+ {200/ (200*500)} 103
=14.43+2=16.43V.

A)
Only an ohmic region
B)
Only a saturation region
C)
An ohmic region at low voltage value followed by a saturation region at higher voltages
D)
An ohmic region at large voltage values preceded by a saturation region at lower voltages

Correct Answer :   An ohmic region at low voltage value followed by a saturation region at higher voltages

A)
Red portion of spectrum
B)
Violet portion of spectrum
C)
White portion of spectrum
D)
Green portion of spectrum

Correct Answer :   Green portion of spectrum

A)
1 A
B)
10 A
C)
20 A
D)
100 A

Correct Answer :   1 A

A)
Modulation of signal is required
B)
Rectification of the signal is required
C)
Signal amplification is required
D)
Signal frequency control is required

Correct Answer :   Rectification of the signal is required

A)
100 mg
B)
150 mg
C)
200 mg
D)
500 mg

Correct Answer :   200 mg

A)
0.78 eV
B)
2 eV
C)
5 eV
D)
10 eV

Correct Answer :   0.78 eV

A)
Holes in P-region only
B)
Free electrons in N-region only
C)
Majority carriers in both regions
D)
Majority as well as minority carriers in both regions

Correct Answer :   Majority carriers in both regions

A)
Is less noisy
B)
Has better thermal stability
C)
Has higher input resistance
D)
All of the above

Correct Answer :   All of the above

A)
A polymer
B)
A variety of stainless steel
C)
A conon-ferrous alloy used in aircraft industry
D)
A nickel an iron alloy having high permeability

Correct Answer :   A nickel an iron alloy having high permeability

A)
No hysteresis
B)
Electric dipole moment
C)
Ferroelectric characteristic only above the curie point
D)
High dielectric constant

Correct Answer :   Ferroelectric characteristic only above the curie point

203 .
Hall effect is observed in a specimen when it is carrying current and is placed in a magnetic field. The resultant electric field inside the specimen is
A)
In arbitrary direction
B)
In the direction of current
C)
Antiparallel to magnetic field
D)
Normal to both current and magnetic field

Correct Answer :   Normal to both current and magnetic field

A)
A hole can have at room temperature
B)
An electron can have at room temperature
C)
Must be given to an electron move to conduction band
D)
None of the above

Correct Answer :   Must be given to an electron move to conduction band

A)
should not exceed the breakdown voltage
B)
should not exceed one third the breakdown voltage
C)
should not exceed half the breakdown voltage
D)
may be equal to or less than breakdown voltage

Correct Answer :   should not exceed one third the breakdown voltage

A)
Diffusion process
B)
Oxidation
C)
Evaporation
D)
None of the above

Correct Answer :   Diffusion process

A)
causes a large increase in reverse saturation current
B)
does not affect reverse saturation current
C)
causes a small increase in reverse saturation current
D)
may cause an increase or decrease in reverse saturation current depending on rating of diode

Correct Answer :   causes a large increase in reverse saturation current


Explanation : Reverse saturation current doubles for every 10°C rise in junction temperature.

A)
flux leakage
B)
hysteresis loss
C)
heat generation
D)
core saturation

Correct Answer :   core saturation

A)
skin effect
B)
coupling capacitor at the I/P
C)
internal capacitance of the device
D)
coupling capacitor at the O/P

Correct Answer :   internal capacitance of the device

210 .
A Si sample is doped with a fixed number of group N impurities. The electron density n is measured from 4 K to 1200 k for the sample. Which one of the following is correct?
A)
n increases monotonicaliy with increasing temp
B)
n remains constant over the temperature range
C)
n increases show a peak and then decrease with temperature
D)
n increases first remains constant over a range and again increases with increasing temperature

Correct Answer :   n increases monotonicaliy with increasing temp

A)
SCR
B)
PNP transistor
C)
Vacuum triode
D)
NPN transistor

Correct Answer :   Vacuum triode


Explanation : Both JFET and vacuum triode are voltage controlled devices.

A)
0.05
B)
0.5
C)
50
D)
500

Correct Answer :   0.05

A)
The duration of output waveform is less than 180°
B)
Output voltage is less than input voltage
C)
Output voltage is more than input voltage
D)
Both (A) and (B)

Correct Answer :   Both (A) and (B)


Explanation : Since the duration of output waveform is less than 180°, output voltage is less than input voltage.

A)
increases
B)
decreases
C)
remains the same
D)
may increase or decrease

Correct Answer :   increases


Explanation : Increase of temperature increases conductivity of semiconductors.increases

A)
1.2 V
B)
0.72 V
C)
zero voltage
D)
breakdown voltage

Correct Answer :   breakdown voltage

A)
10 kV/mm
B)
40 kV/mm
C)
100 kV/mm
D)
140 kV/mm

Correct Answer :   40 kV/mm

A)
same as that of annealed copper
B)
less than that of annealed copper
C)
more than that of annealed copper
D)
decreasing when temperature increases

Correct Answer :   more than that of annealed copper

218 .
The voltage across the secondary of the transformer in a half wave rectifier with a shunt capacitor filter is 50 volts. The maximum voltage that will occur on the reverse biased diode will be
A)
25 V
B)
50 V
C)
88 V
D)
100 V

Correct Answer :   100 V

A)
slave mask
B)
working mask
C)
photo mask
D)
master mask

Correct Answer :   working mask


Explanation : The mask that is prepared first is called the master mask made from glass substrates covered by thin chromium film.

From the master masks are prepared working masks by contact pointing and used for Photolithography which means Photo engraving.

A)
decrease in capacitance
B)
increase in capacitance
C)
no change in capacitance
D)
Either (B) or (C)

Correct Answer :   decrease in capacitance


Explanation : Capacitance is inversely proportional to distance between plates.

A)
0.103 eV
B)
0.673 eV
C)
1.03 eV
D)
1.27 eV

Correct Answer :   1.03 eV

A)
boron
B)
aluminium
C)
germanium
D)
phosphorus

Correct Answer :   phosphorus

A)
holes and electrons move towards the junction
B)
holes and electrons move away from the junction
C)
holes move towards junction and electrons move away from junction
D)
holes move away from junction and electrons move towards junction

Correct Answer :   holes and electrons move away from the junction


Explanation : Holes and electrons move away from junction and therefore resistance increases to a high value.

A)
resistivity of Si will be higher than of germanium
B)
both will have equal -ve resistivity
C)
both will have equal value of resistivity
D)
resistivity of germanium will be higher than that of silicon

Correct Answer :   resistivity of Si will be higher than of germanium


Explanation : Since the majority of charge carrier is better in Ge than in Si, for the same concentration of charge carriers, the conductivity of Ge is higher than that of Si.

A)
the energy levels of inner shell electrons are affected appreciably by the presence of other neighbouring atoms.
B)
The energy levels of outer shell electrons are affected appreciably by the presence of other neighbouring atoms.
C)
the energy levels of both inner and outer shell electrons are affected appreciably by the presence of other neighbouring atoms.
D)
None of the above

Correct Answer :   The energy levels of outer shell electrons are affected appreciably by the presence of other neighbouring atoms.


Explanation : Inner shell electrons are tightly bound to the nucleus. Their energy levels cannot be affected by presence of other atoms.

A)
0.1 V
B)
0.3 V
C)
0.7 V
D)
1 V

Correct Answer :   0.7 V


Explanation : This 0.7 V is also called cut in voltage. When forward voltage is 0.7 V or less there is no current.

A)
barrier potential
B)
applied reverse voltage
C)
applied forward voltage
D)
None of the above

Correct Answer :   barrier potential

A)
0 V
B)
0.7 V
C)
10 V
D)
18 V

Correct Answer :   18 V

A)
JFET
B)
Depletion Type MOSFET
C)
Enhancement type MOSFET
D)
Both (B) and (C)

Correct Answer :   Both (B) and (C)


Explanation : All MOSFETs have substrate.

A)
is in conduction band
B)
is in the valence band
C)
is very near conduction band
D)
is at the centre in between valence and conduction bands

Correct Answer :   is in the valence band


Explanation : This is due to heavy doping.

A)
is less
B)
is more
C)
is almost the same
D)
may be more or less

Correct Answer :   is more


Explanation : Tunnel diode has heavily doped p and n regions.

A)
saturate quickly
B)
are non-linear in nature
C)
are bulky and unsuitable for miniaturisation
D)
are always associated with some resistance

Correct Answer :   are bulky and unsuitable for miniaturisation


Explanation : In active circuit, Inductors are used by Op-Amp resistors and capacitor instead of simple inductor.

A)
mainly holes
B)
only holes
C)
only electrons
D)
mainly electrons

Correct Answer :   mainly holes


Explanation : Since emitter is p-type, emitter current is mainly due to holes. This current diffuses through the base.

A)
3 million each
B)
6 billion each
C)
3 million free electrons and very small number of holes
D)
3 million holes and very small number of free electrons

Correct Answer :   3 million free electrons and very small number of holes


Explanation : When pentavalent impurity is added, the number of fresh electrons is very large as compared to number of holes.

A)
semiconductors
B)
metallic conductors
C)
good quality insulators
D)
Either (B) or (C)

Correct Answer :   semiconductors

A)
fast turn on
B)
fast turn off
C)
large emitter base forward bias
D)
large collector base reverse bias

Correct Answer :   large collector base reverse bias

237 .
In a common emitter BJT amplifier, the maximum usable supply voltage is limited by
A)
avalanche Beakdown of Base-Emitter junction
B)
zener break down voltage of the emitter base junction
C)
collector emitter breakdown voltage with base open(βVCEO)
D)
collector emitter breakdown voltage with emitter open(βVCEO)

Correct Answer :   collector emitter breakdown voltage with emitter open(βVCEO)

A)
0.1%
B)
4%
C)
50%
D)
150%

Correct Answer :   150%

239 .
Eg is the band gap, A is pre-factor, k is Boltzmann constant? Which one of the following is the remaining grade of paper used in paper capacitor, besides the other two grade of paper-low and extra low loss?
A)
Rough
B)
Regular
C)
High loss
D)
Strong dielectric

Correct Answer :   Regular

240 .
Barkhausen criterion of oscillation is
A)
Aβ = 1
B)
Aβ > 1
C)
Aβ ≤ 1
D)
Aβ = < 1

Correct Answer :   Aβ = 1

A)
Voltage
B)
Current
C)
Frequency
D)
Power factor

Correct Answer :   Frequency

A)
only an ohmic region
B)
an ohmic region at low voltage value and a saturation region at high voltage
C)
only a saturation region
D)
a saturation region at low voltage value and an ohmic region at high voltage

Correct Answer :   an ohmic region at low voltage value and a saturation region at high voltage

A)
half cycle of the input signal
B)
one-fourth cycle of the input signal
C)
the complete cycle of the input signal
D)
less than half cycle of the input signal

Correct Answer :   half cycle of the input signal

A)
1 kVA
B)
108 VA
C)
175 VA
D)
350 VA

Correct Answer :   350 VA

A)
Bridge rectifier
B)
Full wave rectifier
C)
Half wave rectifier
D)
Three phase full wave rectifier

Correct Answer :   Three phase full wave rectifier

A)
Vacum triode
B)
FET
C)
SCR
D)
Both (A) and (B)

Correct Answer :   Both (A) and (B)

A)
Arsenic
B)
Boron
C)
Antimony
D)
Phosphorus

Correct Answer :   Boron

A)
in lightly doped junctions
B)
mostly in germanium junctions
C)
due to rapture of covalent band
D)
due to thermally generated minority carriers

Correct Answer :   due to rapture of covalent band

A)
resistance value
B)
total surface area
C)
thermal capacity of the resistor
D)
resistivity of the material used in the resistor

Correct Answer :   thermal capacity of the resistor

A)
Saturation
B)
Active
C)
Cut off
D)
Reverse active

Correct Answer :   Saturation

A)
increased resistance
B)
formation of P-type semiconductor
C)
more free electrons than holes in the semiconductor
D)
antimony concentrating on the edges of the crystals

Correct Answer :   more free electrons than holes in the semiconductor

A)
conducts in reverse direction only
B)
conducts in forward direction only
C)
low resistance in forward as well as reverse direction
D)
high resistance in forward as well as reverse direction

Correct Answer :   conducts in forward direction only

A)
high purity silica
B)
high purity silicon
C)
epitaxial grown silicon
D)
heavily doped polycrystalline silicon

Correct Answer :   heavily doped polycrystalline silicon

A)
base is positive with respect to emitter and collector
B)
base is negative with respect to emitter and collector
C)
emitter is negative with respect to base and base is positive with respect to collector
D)
emitter is positive with respect to base and base is positive with respect to collector

Correct Answer :   emitter is positive with respect to base and base is positive with respect to collector

A)
saturated region
B)
active region
C)
cut off region
D)
inverse mode

Correct Answer :   saturated region

A)
unbiased
B)
forward biased
C)
reverse biased
D)
biased to breakdown

Correct Answer :   reverse biased

A)
zero
B)
negative
C)
positive
D)
zero or positive

Correct Answer :   negative

A)
collector
B)
emitter base junction
C)
collector base junction
D)
None of the above

Correct Answer :   collector base junction

259 .
Hall effect is observed in a specimen when it is carrying current and is placed in a magnetic field. The resulting electric field inside the speciment will be in
A)
the direction of current
B)
direction antiparallel to magnetic field
C)
an arbitrary direction depend upon conductivity
D)
direction normal to both current and magnetic field

Correct Answer :   direction normal to both current and magnetic field

A)
depletion region
B)
active region
C)
neutral region
D)
transition zone

Correct Answer :   depletion region

A)
majority carriers
B)
minority carriers
C)
both majority and minority carriers
D)
Either (A) or (C)

Correct Answer :   minority carriers

A)
the majority carrier density doubles
B)
the minority carrier density doubles
C)
both majority and minority carrier densities double
D)
the minority carrier density becomes 4 times the original value

Correct Answer :   both majority and minority carrier densities double

A)
resistance of diode
B)
conductance of diode
C)
incremental resistance of diode
D)
incremental conductance of diode

Correct Answer :   incremental conductance of diode

A)
The maximum velocity of emission varies with the intensity of light
B)
The maximum velocity of emission varies with the frequency of incident light
C)
The quantum yield depends on the frequency and not the intensity of incident light
D)
The amount of photoelectric emission is directly proportional to the intensity of light

Correct Answer :   The maximum velocity of emission varies with the intensity of light

A)
potential barrier is reduced to zero
B)
reverse bias exceeds the limiting value
C)
forward bias exceeds the limiting value
D)
forward current exceeds the limiting value

Correct Answer :   reverse bias exceeds the limiting value

A)
bridge rectifier
B)
half wave rectifier
C)
full wave rectifier
D)
three phase full wave rectifier

Correct Answer :   half wave rectifier

A)
a proton is also lost
B)
atom becomes an ion
C)
a hole is created
D)
rest of the electron move at a faster rate

Correct Answer :   a hole is created

A)
X-ray region
B)
visible region
C)
infrared region
D)
ultraviolet region

Correct Answer :   ultraviolet region

A)
Saturation
B)
Cut off
C)
Reverse active
D)
Forward active

Correct Answer :   Saturation

A)
casting
B)
rolling casting
C)
induction heating
D)
electrolytic refining

Correct Answer :   electrolytic refining

A)
drain current
B)
gate voltage
C)
source current
D)
All of the above

Correct Answer :   gate voltage

272 .
Figure represents a
A)
LED
B)
Varactor
C)
Zener diode
D)
Temperature dependent diode

Correct Answer :   Zener diode

A)
clapp oscillator
B)
colpitt's oscillator
C)
phase shift oscillator
D)
weinbridge oscillator

Correct Answer :   colpitt's oscillator

A)
dipole semi-conductor
B)
impure semi-conductor
C)
extrinsic semi-conductor
D)
bipolar semi-conductor

Correct Answer :   extrinsic semi-conductor

A)
a zero and a pole
B)
a zero and a zero
C)
a pole and a pole
D)
a pole and a zero

Correct Answer :   a zero and a pole

A)
applied electric field
B)
square of the electric field
C)
cube of the applied electric field
D)
concentration gradient of charge carrier

Correct Answer :   concentration gradient of charge carrier

A)
Temperature
B)
Current
C)
Applied voltage
D)
Extent of doping

Correct Answer :   Temperature

A)
a linear B-H behaviour
B)
a non-linear B-H behaviour
C)
an exponential B-H behaviour
D)
None of the above

Correct Answer :   a non-linear B-H behaviour

A)
depends on reverse voltage
B)
depends on forward voltage
C)
is due to thermally generated minority carriers
D)
None of the above

Correct Answer :   is due to thermally generated minority carriers

A)
hysteresis
B)
diamagnetism
C)
magnetostriction
D)
bipolar relaxation

Correct Answer :   magnetostriction

A)
make silicon semimetal
B)
reduce the recombination rate
C)
increase the recombination rate
D)
make silicon a direct gap semiconductor

Correct Answer :   make silicon a direct gap semiconductor

282 .
In the figure shows the circuits symbol of
A)
FET
B)
NMOSFET
C)
PMOSFET
D)
CMOSFET

Correct Answer :   NMOSFET

283 .
A)
ferromagnetic materials
B)
ferroelectric materials
C)
ferrimagnetic materials
D)
ferri-ferromagnetic materials

Correct Answer :   ferromagnetic materials

A)
holes, drift
B)
holes, diffusion
C)
electrons, drift
D)
electrons, diffusion

Correct Answer :   holes, diffusion

A)
diode
B)
triode
C)
tetrode
D)
pentode

Correct Answer :   tetrode

A)
2
B)
3
C)
4
D)
6

Correct Answer :   6

A)
cooling the anode
B)
heating the cathode
C)
coating the cathode ray by an active materials
D)
coating the cathode by an insulating material

Correct Answer :   coating the cathode ray by an active materials

A)
silver, copper, gold, aluminium
B)
gold, silver, copper, aluminium
C)
copper, silver, gold, aluminium
D)
aluminium, silver, gold, copper

Correct Answer :   silver, copper, gold, aluminium

A)
JFET
B)
Tunnel diode
C)
Zener diode
D)
MOSFET and tunnel diode

Correct Answer :   Tunnel diode

A)
emission of holes
B)
emission of electrons
C)
conversion of heat energy into illumination
D)
generation of electromagnetic radiations

Correct Answer :   generation of electromagnetic radiations

A)
Capacitor
B)
Transistor
C)
Vacuum tube
D)
Tunnel diode

Correct Answer :   Capacitor

A)
always periodic
B)
never periodic
C)
periodic under certain conditions
D)
periodic only if all the sinusoidals are identical in frequency and phase

Correct Answer :   periodic only if all the sinusoidals are identical in frequency and phase

A)
bridge rectifier
B)
full wave rectifier
C)
half wave rectifier
D)
three phase full wave rectifier

Correct Answer :   full wave rectifier

A)
μ ohm-cm
B)
μ ohm
C)
μ ohm/cm
D)
μ ohm-cm/°C

Correct Answer :   μ ohm-cm

A)
Ohm's law
B)
Boltzmann's law
C)
Langmuir Child law
D)
Richardson Dushman equation

Correct Answer :   Langmuir Child law

A)
40.6%
B)
66.6%
C)
81.2%
D)
100%

Correct Answer :   81.2%

A)
50 Hz
B)
100 Hz
C)
200 Hz
D)
400 Hz

Correct Answer :   100 Hz

A)
bridge rectifier
B)
full wave rectifier
C)
half wave rectifier
D)
three phase full wave rectifier

Correct Answer :   three phase full wave rectifier

A)
Rochelle salt
B)
Barium titanate
C)
Potassium dihydrogen phosphate
D)
All of the above

Correct Answer :   All of the above

A)
life time
B)
half life
C)
life cycle
D)
recombination time

Correct Answer :   life time

A)
the extent of doping
B)
the number of donor atoms
C)
the temperature of the material
D)
the number of acceptor atoms

Correct Answer :   the temperature of the material

A)
0.7 eV
B)
1.1 eV
C)
1.3 eV
D)
1.4 eV

Correct Answer :   1.1 eV

A)
reverse bias and forward bias
B)
reverse bias and reverse bias
C)
forward bias and reverse bias
D)
forward bias and forward bias

Correct Answer :   reverse bias and reverse bias

A)
transparent to the visible light
B)
opaque to the infrared radiation
C)
transparent to the ultraviolet radiation
D)
opaque to the visible light

Correct Answer :   opaque to the visible light

A)
lower melting point
B)
abundance of Si on the surface of earth
C)
larger band gap of Si in comparison to Ge
D)
favourable properties of Silicon-dioxide (SiOâ‚‚)

Correct Answer :   favourable properties of Silicon-dioxide (SiOâ‚‚)

A)
65
B)
6.5
C)
0.65
D)
0.065

Correct Answer :   6.5

A)
drift current
B)
induced current
C)
diffusion current
D)
recombination current

Correct Answer :   diffusion current

A)
widens
B)
reduce to zero
C)
becomes narrow
D)
remains the same

Correct Answer :   widens

A)
500 eV
B)
500 mV
C)
500 ergs
D)
500 joules

Correct Answer :   500 eV

A)
PIN diode
B)
Zener diode
C)
Schottky diode
D)
Tunnel diode

Correct Answer :   Tunnel diode

A)
1 Ω-cm
B)
400 Ω-cm
C)
10000 Ω-cm
D)
230000 Ω-cm

Correct Answer :   230000 Ω-cm

A)
Potential barrier is increased
B)
Potential barrier is decreased
C)
Majority carrier current is reduced to zero
D)
Minority carrier current is reduced to zero

Correct Answer :   Potential barrier is decreased

A)
CMRR
B)
slew rate
C)
bandwidth
D)
open-loop gain

Correct Answer :   open-loop gain

A)
Fermi-Dirac Distribution
B)
Maxwell's Distribution
C)
Richardson Dushman Distribution
D)
None of the above

Correct Answer :   Fermi-Dirac Distribution

A)
slightly higher than that of the ferromagnetic metals
B)
slightly lower than that of the ferromagnetic materials
C)
very much higher than that of the ferromagnetic metals
D)
very much lower than that of the ferromagnetic metals

Correct Answer :   very much higher than that of the ferromagnetic metals

A)
has no stable state
B)
has one stable state
C)
has two stable states
D)
switches automatically from one state to other state

Correct Answer :   has one stable state

A)
Half wave rectifier
B)
Full wave rectifier
C)
Bridge type full wave rectifier
D)
Three phase full wave rectifier

Correct Answer :   Three phase full wave rectifier

A)
Fermi's effect
B)
Hall's effect
C)
Joule's effect
D)
Photo electric effect

Correct Answer :   Hall's effect

A)
few milli amperes
B)
1 A to 10 A
C)
0.1 A to 1 A
D)
few nano amperes

Correct Answer :   few milli amperes

A)
Joule effect
B)
Peltier effect
C)
Seeback effect
D)
Thomson effect

Correct Answer :   Seeback effect

A)
10 to 70 m-ohm-cm
B)
80 to 130 m-ohm-cm
C)
800 to 1300 m-ohm-cm
D)
8000 to 13000 m-ohm-cm

Correct Answer :   800 to 1300 m-ohm-cm

A)
NIO
B)
CrSb
C)
MnO
D)
All of the above

Correct Answer :   All of the above

A)
during the base diffusion
B)
during the entire diffusion
C)
during the collector diffusion
D)
while growing the epitaxial layer

Correct Answer :   during the entire diffusion

A)
zero drain current
B)
high values of drain current
C)
saturation values of drain current
D)
gate current equal to the drain current

Correct Answer :   zero drain current

A)
filter promotes ripple at peak voltage
B)
the increase in ripple with load current causes a increase in average voltage
C)
the increase in ripple with load current causes a decrease in average voltage
D)
None of the above

Correct Answer :   the increase in ripple with load current causes a decrease in average voltage

A)
holes
B)
electrons
C)
holes in pnp and electrons in npn
D)
electrons in pnp and holes in npn

Correct Answer :   holes

A)
0.01 eV
B)
1 eV
C)
6 eV
D)
10 eV

Correct Answer :   1 eV

A)
emitter base : reverse, collector base : reverse
B)
emitter base : reverse, collector base : forward
C)
emitter base : forward, collector base : forward
D)
emitter base : forward, collector base : reverse

Correct Answer :   emitter base : forward, collector base : reverse

A)
gallium arsenide
B)
zinc sulphide
C)
gallium phosphide
D)
None of the above

Correct Answer :   zinc sulphide

A)
angle of incidence of radiation
B)
surface conditions of the surface
C)
intensity of the incident radiation
D)
wavelength of the incident radiation

Correct Answer :   wavelength of the incident radiation