Correct Answer : Either lead or lag
Explanation : In an impedance parallel network the reactive component will either lead or lag the voltage by 90 degrees.
Correct Answer : 90
Correct Answer : Voltage
Correct Answer : 20 kΩ
Correct Answer : 25 Ω
Correct Answer : Less than 120 Ω but greater than 100 Ω
Correct Answer : Is less than 600 Ω
Correct Answer : 22 mA
Correct Answer : 61 mA
Correct Answer : 5.5 Ω
Correct Answer : 12 mA
Correct Answer : 72 W
Correct Answer : 4.8 W
Correct Answer : 7.06 A
Correct Answer : 70 mA
Correct Answer : True
Correct Answer : 170 mA
Correct Answer : decrease
Correct Answer : series, series
Correct Answer : 2.5 mA
Correct Answer : Leads
Explanation : The reactive component in an impedance parallel circuit leads the voltage when the current leads the voltage.
Correct Answer : Be in phase with
Explanation : The active component in an impedance parallel network will always be in phase with the voltage in the circuit.
Correct Answer : 0
Explanation : The active component in an impedance parallel network will always be in phase with the voltage in the circuit. Hence the phase difference is 0.
Correct Answer : Reactive component
Explanation : The quadrature component is also known as the reactive component because the reactive component forms a quadrature with the voltage.
Correct Answer : An increase in source voltage
Correct Answer : 490 mA
Correct Answer : 1.8 A
Correct Answer : R3 is open
Correct Answer : 60 Ω
Correct Answer : 31.25 mA
Correct Answer : 1.24 A
Correct Answer : 7 A
Correct Answer : 560 Ω
Correct Answer : Increases
Correct Answer : Decreases
Correct Answer : 12 V
Correct Answer : I=IL+IR
Explaination : I is the total current in the circuit. Since this is a parallel connection, the total current in the circuit is equal to the sum of the currents in each branch of the circuit. Hence I=IR+IL.
Correct Answer : 2A
Explaination : We know that I=IR+IL.10=IR+8 => IR=2A.
Correct Answer : 10A
Explaination : We know that I=IR+IL.I=8+2=10A.
Correct Answer : False
Correct Answer : The remaining two will glow with the same brightness as before
Correct Answer : 6.25 mA
Correct Answer : resistance
Correct Answer : least current
Correct Answer : 4.8Ω
Correct Answer : 30 mW
Correct Answer : more than one current path exists
Correct Answer : branch current
Correct Answer : remain unchanged
Correct Answer : 128 mA