Correct Answer : RC
Explanation : The time constant of an R-C circuit is RC and it is denoted by τ and the value of τ in dc response of R-C circuit is RC sec.
Correct Answer : 5
Explanation : After five time constants, the transient part of the response reaches more than 99 percent of its final value.
Correct Answer : i=(V/R)expâ¡(-t/RC)
Explanation : The particular solution of the current equation is zero. So the expression of current in R-C circuit is i=(V/R)expâ¡(-t/RC).
Correct Answer : decays with time
Explanation : In a R-C circuit, when the switch is closed, the response decays with time that is the response V/R decreases with increase in time.
Correct Answer : -330°
Correct Answer : False
Correct Answer : 8.48 ∠45°
Correct Answer : Cannot be determined without values
Correct Answer : 2121 Ω and θ = -19.5°
Correct Answer : 180°
Correct Answer : 129 Ω
Correct Answer : First quadrant
Correct Answer : Fourth quadrant
Correct Answer : 2.12 mS + j3.14 mS
Correct Answer : 6 kHz
Correct Answer : True
Correct Answer : Decreases
Correct Answer : 141 mA
Correct Answer : 26.0 V
Correct Answer : 22.94 + j32.76
Correct Answer : 84.5 mW
Correct Answer : 2
Explaination : At t = 0, switch S is closed. Since the capacitor does not allow sudden changes in voltage, the current in the circuit is i = V/R = 20/10 = 2A. At t = 0, i = 2A.
Correct Answer : di/dt+i=0
Explaination : By applying Kirchhoff’s law, we get
Correct Answer : VC = 60(1-e-t)V
Explaination : The expression of voltage across capacitor in the circuit VC = V(1-e-t/RC) = 20(1-e-t)V.
Correct Answer : Increases
Correct Answer : Z = 150 ∠-90° ohm
Correct Answer : 4.11 V
Correct Answer : 195.2 W
Correct Answer : 19.2 V
Correct Answer : R < Xc
Correct Answer : 21.63
Correct Answer : 4 units right of the origin on the real axis
Correct Answer : 37.9 Ω
Correct Answer : Z = 47 Ω - j150 Ω
Correct Answer : i=2(e-2t)A
Explaination : At t = 0, switch S is closed. Since the capacitor does not allow sudden changes in voltage, the current in the circuit is i = V/R = 20/10 = 2A. At t = 0, i = 2A. The current equation is i=2(e-2t)A.
Correct Answer : VR = 20(e-t)V
Explaination : The expression of voltage across resistor in the circuit is VR = iR =(2(e-t))×10=20(e-t)V.
Correct Answer : 4.6 mA