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EEE : Series Circuits - Quiz(MCQ)
1 .
A series circuit consists of three resistors. Two resistors are 1.2 kΩ each. The total resistance is 12 kΩ. The value of the third resistor is
A)
1.2 kΩ
B)
960 Ω
C)
9,600 Ω
D)
Cannot be determined

Correct Answer :   9,600 Ω

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   True

A)
0 A
B)
2 mA
C)
5 mA
D)
15 mA

Correct Answer :   0 A

A)
3 V
B)
6 V
C)
9 V
D)
15 V

Correct Answer :   15 V

5 .
The following resistors (one each) are connected in a series circuit: 470 Ω, 680 Ω, 1 kΩ, and 1.2 kΩ. The voltage source is 20 V. Current through the 680 Ω resistor is approximately
A)
6 mA
B)
30 mA
C)
60 mA
D)
300 mA

Correct Answer :   6 mA

6 .
Two 6 V batteries are connected series aiding across two 1.2 kΩ resistors in series. Current through each resistor is
A)
0 A
B)
2.5 mA
C)
5 mA
D)
10 mA

Correct Answer :   5 mA

7 .
What is the current flow through R1, R2, and R3?
A)
1A, 1A, 1A
B)
1A, 2A, 3A
C)
3A, 2A, 1A
D)
3A, 3A, 3A

Correct Answer :   1A, 1A, 1A


Explaination : V = IR

V = I(R1 + R2 + R3)

I = V/(R1 + R2 + R3)

= 9/(3 + 3 + 3)

= 9/9

= 1 Amp.

A)
divider control
B)
current control
C)
voltage control
D)
volume control

Correct Answer :   volume control

A)
be doubled
B)
be halved
C)
be the same
D)
reduce source voltage

Correct Answer :   be halved

A)
work
B)
joules
C)
the conversion of energy
D)
the rate at which work is done

Correct Answer :   the rate at which work is done

11 .
What is the dc source voltage?
A)
0 V
B)
13 V
C)
39 V
D)
78 V

Correct Answer :  

A)
Zero
B)
The source voltage
C)
The total of the voltage drops
D)
The total of the source voltage and the voltage drops

Correct Answer :   Zero

A)
22 Ω
B)
88 Ω
C)
220 Ω
D)
880 Ω

Correct Answer :   220 Ω

14 .
Find the current in the circuit.
A)
1 A
B)
2 A
C)
3 A
D)
4 A

Correct Answer :   2 A


Explaination : I=V/R. Total resistance R = 20+40=60ohm. V=120V. I=120/60=2A.

15 .
In a series circuit, which of the parameters remain constant across all circuit elements such as resistor, capacitor and inductor etcetera?
A)
Voltage
B)
Current
C)
Both (A) and (B)
D)
None of the above

Correct Answer :   Current


Explaination : In a series circuit, the current across all elements remain the same and the total voltage of the circuit is the sum of the voltages across all the elements.

16 .
Voltage across the 60ohm resistor is______
A)
0V
B)
48V
C)
72V
D)
120V

Correct Answer :   0V


Explaination : The 60ohm resistance is shorted since current always choses the low resistance path. Voltage across short circuit is equal to zero, hence voltage across the resistor is 0.

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   True

18 .
A series circuit consists of three resistors with values of 120 Ω, 270 Ω, and 330 Ω. The total resistance is
A)
Less than 120 Ω
B)
120 Ω
C)
720 Ω
D)
The average of the values

Correct Answer :   720 Ω

19 .
A 12 V battery is connected across a series combination of 68 Ω, 47 Ω, 220 Ω, and 33 Ω. The amount of current is
A)
16.3 mA
B)
32.6 mA
C)
163 mA
D)
326 mA

Correct Answer :   32.6 mA

20 .

Calculate the voltage at point B in the given circuit.
A)
+0.94 V
B)
+2.6 V
C)
+3 V
D)
+10.48 V

Correct Answer :   +10.48 V

21 .

In the given circuit, what type of failure will cause the voltage at point B to equal the voltage at point C?
A)
R1 shorts
B)
R2 shorts
C)
R3 shorts
D)
R2 opens

Correct Answer :   R2 shorts

A)
20 mA
B)
24 mA
C)
120 mA
D)
200 mA

Correct Answer :   200 mA

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   True

24 .
A string of five series resistors is connected across a 6 V battery. Zero voltage is measured across all resistors except R3. The voltage across R3 is
A)
0 V
B)
0.6 V
C)
1.2 V
D)
6 V

Correct Answer :   6 V

25 .
Two resistors are in series: a 5.6 kΩ resistor and a 4.7 kΩ resistor. The voltage drop across the 5.6 kΩ resistor is 10 V. The voltage across the 4.7 kΩ resistor is
A)
0 V
B)
2.32 V
C)
8.39 V
D)
10 V

Correct Answer :   8.39 V

26 .

What is the voltage at points B to D in the given circuit?
A)
+8.8 V
B)
+19.2 V
C)
+28 V
D)
–19.2 V

Correct Answer :   +19.2 V

27 .

Calculate the voltage at point C in the given circuit.
A)
+0.94 V
B)
+1.48 V
C)
+3 V
D)
+11.6 V

Correct Answer :   +11.6 V

29 .
Find the voltage across the 6 ohm resistor.
A)
27.27V
B)
54.48V
C)
150V
D)
181.6V

Correct Answer :   27.27V


Explaination : Total current I=150/(6+12+15)=(150/33)V.
V across 6 ohm = 6*I = 6*(150/33)V = 27.27V.

A)
The other bulb also burns out
B)
The other bulb stops glowing
C)
The other bulb glows with increased brightness
D)
The other bulb continues to glow with the same brightness

Correct Answer :   The other bulb stops glowing


Explanation : Since the two bulbs are connected in series, if the first bulb burns out there is a break in the circuit and hence the second bulb does not glow.

32 .
Five resistors are connected in a series and there is a current of 3 A into the first resistor. The amount of current into the second resistor is
A)
0.3 A
B)
1 A
C)
3 A
D)
4 A

Correct Answer :   3 A

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   False

A)
At any point in the circuit
B)
At the negative terminal of the source
C)
Between the second and third resistors
D)
Between the third and fourth resistors

Correct Answer :   At any point in the circuit

A)
The 2.2 kΩ
B)
The 4.7 kΩ
C)
The 12 kΩ
D)
Impossible to determine from the given information

Correct Answer :   The 12 kΩ

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   True

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   True

A)
One 220 Ω resistor
B)
Two 220 Ω resistors
C)
Three 220 Ω resistors
D)
Four 220 Ω resistors

Correct Answer :   One 220 Ω resistor

A)
0 V
B)
18 V
C)
24 V
D)
30 V

Correct Answer :   18 V

A)
Increases
B)
Decreases
C)
Remains the same
D)
Increases by one-fourth

Correct Answer :   Increases

A)
8 Ω
B)
4,480 Ω
C)
5,600 Ω
D)
44,800 Ω

Correct Answer :   44,800 Ω

42 .
What is wrong, if anything, with this circuit?
A)
R1 is open.
B)
R2 is open.
C)
R1 is shorted.
D)
R2 is shorted.

Correct Answer :   R1 is shorted.

A)
the algebraic sum of the resistances is equal to the sum of the voltages
B)
the algebraic sum of the individual currents around a closed loop is zero
C)
the voltages developed across each element in a series circuit are identical
D)
the sum of the voltage drops in a series circuit is equal to the total applied voltage

Correct Answer :   the sum of the voltage drops in a series circuit is equal to the total applied voltage

A)
voltage is reduced
B)
voltage is doubled
C)
resistance is halved
D)
resistance is doubled

Correct Answer :   resistance is halved

45 .
What is the value of x if the current in the circuit is 5A?
A)
15 ohm
B)
25 ohm
C)
55 ohm
D)
75 ohm

Correct Answer :   15 ohm


Explaination : Total voltage=sum of voltages across each resistor. =>150=10*5+5*5+5*x. Solving the equation, we get x=15 ohm.

A)
The power in the circuit
B)
The value of the resistance itself
C)
The amount of time the circuit was on for
D)
The value of the other resistances in the circuit

Correct Answer :   The value of the resistance itself


Explanation : V=IR hence the voltage across a series resistor circuit is proportional to the value of the resistance.

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   False

A)
6 V
B)
30 V
C)
Depends on the current flow
D)
Depends on the resistor values

Correct Answer :   30 V

A)
Increases
B)
Increases by one-third
C)
Decreases by one-third
D)
Decreases by the amount of current through the removed resistor

Correct Answer :   Increases

A)
23 mA
B)
69 mA
C)
230 mA
D)
690 mA

Correct Answer :   230 mA

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   True

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   False

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   True

54 .
The total resistance of a circuit is 680 Ω. The percentage of the total voltage appearing across a 47 Ω resistor that makes up part of the total series resistance is
A)
6.91 %
B)
47 %
C)
68 %
D)
69 %

Correct Answer :   6.91 %

55 .
What are the minimum and maximum output voltages?
A)
0 V, 4 V
B)
0 V, 8 V
C)
0 V, 12 V
D)
0 V, 16 V

Correct Answer :   0 V, 16 V

56 .
What is the total power in the circuit?
A)
1.7 W
B)
17 W
C)
170 mW
D)
170 W

Correct Answer :   170 mW

A)
reduce the power to zero
B)
cause the current to divide
C)
increase the source voltage in proportion to the values
D)
divide the source voltage in proportion to their values

Correct Answer :   divide the source voltage in proportion to their values

A)
Zero
B)
Infinite
C)
The value of the source voltage
D)
None of the above

Correct Answer :   Zero


Explanation : A short is just a wire. The potential difference between two points of a wire is zero hence the voltage measured is equal to zero.

A)
It becomes zero
B)
It becomes double its original value
C)
It becomes half its original value
D)
It becomes infinity

Correct Answer :   It becomes half its original value


Explanation : I=V/R. If R becomes 2R then I becomes I/2 i.e. half of its original value.

A)
11 V
B)
16 V
C)
21 V
D)
80 V

Correct Answer :   11 V