Which of the following is the valid host range for the subnet on which the IP address 192.168.168.188 255.255.255.192 resides?

A)  192.168.168.128-190
B)  192.168.168.129-191
C)  192.168.168.129-190
D)  192.168.168.128-192

Correct Answer :   192.168.168.129-190

Explanation : 256 - 192 = 64. 64 + 64 = 128. 128 + 64 = 192. The subnet is 128, the broadcast address is 191, and the valid host range is the numbers in between, or 129-190.

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