The PHP echo statement is a language construct not actually a function, so you can use it without parentheses e.g. echo or echo(). But if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses.
echo command (That the text can contain HTML)<!DOCTYPE html>
<html>
<head>
<title>PHP echo Statement</title>
</head>
<body>
<?php
echo "<h1>Free Time Learn</h1>";
echo "<h2>www.freetimelearning.com</h2>";
echo "<p>www.freetimelearn.com</p>";
echo "Free Time Learning!<br /><br />";
echo "This is ", "Sample ", "string.";
?>
</body>
</html>​The following example shows how to output text and variables with the echo statement :
<!DOCTYPE html>
<html>
<head>
<title>PHP echo Statement</title>
</head>
<body>
<?php
$var_name = "FTL (Free Time Learning)";
$var_website = "www.freetimelearning.com";
$x = 9;
$y = 18;
$z = 27;
echo "<h2>" . $var_name . "</h2>";
echo "Learn PHP at " . $var_website . "<br /><br />";
echo $x + $y. "<br /><br />";
echo $y * $z;
?>
</body>
</html>The PHP print statement (an alternative to echo) to display output to the browser. Like echo the print is also a language construct not a real function. So you can also use it without parentheses like: print or print().
print command (That the text can contain HTML).<!DOCTYPE html>
<html>
<head>
<title>PHP print Statement</title>
</head>
<body>
<?php
print "<h1>Free Time Learn</h1>";
print "<h2>www.freetimelearning.com</h2>";
print "<p>www.freetimelearn.com</p>";
print "Free Time Learning!";
?>
</body>
</html>print statement :<!DOCTYPE html>
<html>
<head>
<title>PHP print Statement</title>
</head>
<body>
<?php
print "<h1>Free Time Learn</h1>";
print "<h2>www.freetimelearning.com</h2>";
print "<p>www.freetimelearn.com</p>";
print "Free Time Learning!";
?>
</body>
</html>