Here, we have used nested
if
statements to check whether the year given by the user is a leap year or not.
First, we check
if year
is divisible by
4 or not
. If it is not divisible, then it is not a leap year.
If it is divisible by 4, then we use an inner if statement to check whether year is divisible by
100
.
If it is not divisible by
100
, it is still divisible by
4
and so it is a
leap year
.
We know that the century years are not leap years unless they are divisible by
400
.
So, if
year
is divisible by
100
, another inner
if
statement checks whether it is divisible by
400
or not.
If it's divisible by
400
, it is a leap year. Otherwise, it's not a leap year.
Check Leap Year Using Logical Operators :
We can combine the conditions required for a leap year into a single
if...else
statement using the
&&
and
||
operators.
#include <iostream>
using namespace std;
int main() {
int year;
cout << "Enter a year: ";
cin >> year;
// if year is divisible by 4 AND not divisible by 100
// OR if year is divisible by 400
// then it is a leap year
if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) {
cout << year << " is a leap year.";
}
else {
cout << year << " is not a leap year.";
}
return 0;
}
Output :
Enter a year: 2024
2024 is a leap year.