In control word format, if RL1=1, RL0=1 then the operation performed is

read/load least significant byte only

read/load most significant byte only

read/load LSB first and then MSB

read/load MSB first and then LSB

Correct Answer : Option (C) : read/load LSB first and then MSB

Explanation : To access 16 bit, first LSB is loaded first, and then MSB.

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If I = J = K = 13, then in Fortran 1 = 10 - (1 / 10) * 10 + (J / 5) * 4 + K ** (- 2) is equal to

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