For a constant thrust of 6000 N, find the total impulse for the burning time of 3s.

A)
0 Ns
B)
9000 Ns
C)
18000 Ns
D)
36000 Ns

Correct Answer :   18000 Ns


Explanation : Here we assume that the start and stop transients are negligible during the operation of the system. Then, for a constant thrust (F), and for the total burning time of t seconds, the total impulse It = Ft.
It = 6000 x 3 = 18000 Ns