Correct Answer : The ratio of change in length to the original length
Explanation : The tensile stress is the ratio of tensile force to the change i length. It is the stress induced in a body when subjected to two equal and opposite pulls. The ratio of change in length to the original length is the tensile strain.
Correct Answer : If three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two
Correct Answer : increases more rapidly
Correct Answer : Sum of resolved parts in any two perpendicular directions are both zero
Correct Answer : All of the above
Correct Answer : √2
Correct Answer : None of the above
Correct Answer : WL³/9√3
Correct Answer : WL²/2 EI
Correct Answer : more than that necessary to continue it
Correct Answer : 8
Correct Answer : M/I = E/R = Y/F
Correct Answer : Elasticity
Explanation : When an external force acts on a body, the body tends to undergo some deformation. If the external force is removed and the body comes back to its original shape and size, the body is known as elastic body and this property is called elasticity.
Correct Answer : Malleability
Explanation : A material can be beaten into thin plates by its property of malleability.
Correct Answer : Hooke's law
Explanation : The hooke's law is valid under the elastic limit of a body. It itself states that stress is proportional to the strain within the elastic limit.
Correct Answer : heterogeneous material
Correct Answer : diamond riveting
Correct Answer : Elastic modulus
Explanation : The elastic modulus is the ratio of stress and strain. So on the stress strain curve, it is the slope.
Correct Answer : It is the relationship between stress and strain
Explanation : The relationship between stress and strain on a graph is the stress strain curve. It represents the change in stress with change in strain.
Correct Answer : Elastic limit
Explanation : The curve will be stress strain proportional upto the proportionality limit. After these, the elastic limit will occur.
Correct Answer : no shear stress acts
Correct Answer : plastic
Correct Answer : Q and R each is equal to 10 tonnes
Correct Answer : 0.0012
Explanation : Strain = dL/L = 0.3/250 = 0.0012
Correct Answer : 0.5mm
Explanation : dL = strain x L = 0.005 x 100 = 0.5mm.
Correct Answer : b-d / b
Correct Answer : less than one
Correct Answer : horizontal and vertical components at both the ends
Correct Answer : σV²/2E
Correct Answer : s²V/2E
Explanation : Strain energy = s²V/2E.
Correct Answer : τ²/E x (1+ v)
Explanation : σ₁=τ, σ₂= -τσ₃=0U = (τ²+- τ²-2μτ(-τ))V = τ²/E x (1+ v)V.
Correct Answer : 0
Correct Answer : under the load
Correct Answer : 1.08 tonnes
Correct Answer : 12.88
Correct Answer : compressive force
Correct Answer : 2/1.5
Explanation : Normal stress at B = Total load acting at B / Area of a cross-section at B= (P + P) / 1.5 A = 2P/ 1.5A = 2/1.5.
Correct Answer : The work done by the applied load In stretching the body
Explanation : The strain energy stored in a body is equal to the work done by the applied load in stretching the body.
Correct Answer : Maximum stress in gradual load is half to the maximum stress in sudden load
Explanation : Maximum stress in gradual loading = P/AMaximum stress in sudden loading = 2P/A.
Correct Answer : 47.746 N/mm²
Explanation : Stress = Load/ area = 60,000 / (π/4 D²) = 47.746 N/mm²
Correct Answer : 4.77mm
Explanation : Stress = Load/ area = 60,000 / (π/4 D²) = 47.746 N/mm²So stretch = stress x length / E = 4.77mm.
Correct Answer : 125 N/mm²
Explanation : Stress = load / area = 100,000/ (20×40) = 125 N/mm²
Correct Answer : Three times its shear modulus
Explanation : Elastic modulus = EShear modulus = GE = 2G ( 1 + μ )Given, μ= 0.5, E = 2×1.5xGE = 3G.
Correct Answer : 3
Correct Answer : L²/2E
Explanation : The elongation of bar due to its own weight is δ= WL/2AENow W = ρALThere fore δ= L² / 2E.
Correct Answer : 1/3
Explanation : Longitudinal strain = 0.09/200Lateral strain = – 0.0045/30Poissons ratio = – lateral strain/ longitudinal strain= 0.0045/30 x 200/0.09= 1/3.
Correct Answer : 2.5
Explanation : Modulus of rigidity, G = E/2(1 + μ)Therefore, E/G = 2x(1+0.25) = 2.5.
Correct Answer : limit of proportionality
Correct Answer : 8 cm
Correct Answer : Isotropic
Explanation : Same elastic properties in all direction is called the homogenity of a material.
Correct Answer : Plastic
Explanation : A plastic material does not regain its original shape after removal of load. An elastic material regain its original shape after removal of load.
Explanation : The body only regain its previous shape and size only upto its elastic limit.
Correct Answer : plane frame
Correct Answer : both the ends are fixed
Explanation : Isotropic materials have the same elastic properties in all directions.
Correct Answer : Increases more rapidly
Explanation : On reaching the tensile stress to the elastic limit after the proportionality limit, the stress is no longer proportional to the strain. Then the value of strain rapidly increases.
Correct Answer : Hyper elastic materials
Explanation : The hyper elastic materials are derived from a strain energy density function. A model is hyper elastic if and only if it is possible to express the cauchy stress tensor as a function of the deformation gradient.
Correct Answer : at the top of the surface
Correct Answer : Yield plateau
Explanation : The points on the curve comes in the given order :A. proportionality limitB. elastic limitC. upper yield pointD. lower yield pointE. yield plateauF. ultimate pointG. breaking point.
Correct Answer : Ultimate point
Explanation : After the yield plateau the curve will go up to its maximum limit of stress which is its ultimate point.
Correct Answer : WL / 3
Correct Answer : at all the three hinges
Correct Answer : 2
Correct Answer : inversely proportional to the distance from the axis
Correct Answer : fibres do not undergo strain
Correct Answer : 0.00105
Explanation : Strain = dL/L = 0.21/200 = 0.0005.
Explanation : The percentage elongation = dL/L x 100 = 2/100 x 100 = 2.
Correct Answer : The strain at right angles to the direction of applied load
Explanation : The lateral strain is the strain at right angles to the direction of the applied load. The lateral strain is accompanied by the longitudinal strain.
Correct Answer : n : 1
Correct Answer : 173.2
Correct Answer : 1/8
Correct Answer : 2 l
Correct Answer : h/4
Correct Answer : 0.5 l
Correct Answer : 3/4 times the rise of the crown
Correct Answer : to reduce the bending moment throughout
Correct Answer : P²L³/6EI
Explanation : We may do it taking averageStrain energy = Average force x displacement = (P/2) x PL³/3EI = P²L³/6EI.
Correct Answer : 125 kg-cm
Explanation : Strain energy stored = τ²V/2G = 500²/2×10⁶ x 40x5x5 = 125 kg-cm.
Correct Answer : varies with slope
Correct Answer : thrust, shear force and bending moment.
Correct Answer : Normal stress
Explanation : Normal stress acts in a direction perpendicular to the area. Normal stress is of two types tensile and compressive stress.
Correct Answer : Tensile and compressive stresses
Explanation : The normal stress is divided into tensile stress and compressive stress.
Explanation : In a body loaded under plane stress conditions, the number of independent stress components is 3 I.e. two normal components and one shear component.
Correct Answer : At the built-in upper cross-section
Explanation : The stress is the load per unit area. After the addition of weight in the bar due to its loading on the lower end the force will increase in the upper cross-section resulting in the maximum stress at the built-in upper cross-section.
Correct Answer : 312.5 N-m
Explanation : Stress = load / area = 100,000/ (20×40) = 125 N/mm²Strain energy = σ²V/2E = 125x125x20x40x5000/ (2×100,000) = 312500 N-mm = 312.5N-m.
Correct Answer : 0.125
Explanation : We know that, μ = (3K – 2G) / (6K + 2G)Here K = GTherefore, μ = 3-2 / 6+2 = 0.125.
Correct Answer : 0.33
Explanation : Longitudinal strain = 0.150/400 = 0.000375Lateral strain = – 0.005/40 = -0.000125Poissons ratio = – lateral strain/longitudinal strain= 0.33.
Correct Answer : 73 GN/m²
Explanation : The relationship between E, G, and μ is given byE = 2G (1 + μ)G = 189.8 / 2(1 + 0.30)G = 73 GN/m²
Correct Answer : 80
Explanation : The relationship between E, G and μ is E = 2G (1 + μ)G = 200 / 2(1 + 0.25)G = 80.
Correct Answer : Compressive stress
Explanation : Concrete has the property of taking a good amount of compressive stress. So, In the reinforcement bar, the compressive stress is taken by the concrete.
Correct Answer : Zero
Explanation : As volumetric strain = (1-2μ)σ/EHere the value of μ is 0.5 so 1 – 2 * 0.5 becomes zero.Therefore whatever be the stress the value of volumetric strain will be zero.
Correct Answer : 8 / 3
Correct Answer : bending moment (M)
Correct Answer : 20 tonnes metre
Correct Answer : b = 57.73 cm d = 81.65 cm
Correct Answer : infinite
Correct Answer : 0.207 L
Explanation : The elastic modulus is the ratio of stress to strain.
Correct Answer : one-quarter of the radius
Correct Answer : bending stress is same throughout the beam
Correct Answer : 100 √2 kg/cm²
Correct Answer : of any type
Correct Answer : 10 π
Correct Answer : 5/8th the distributed load
Correct Answer : Breaking point
Explanation : After the ultimate point the value of stress will reduce on increasing of strain and ultimately the material will break.
Correct Answer : Up to which if the load is removed, original volume and shapes are regained
Explanation : The elastic limit is that limit up to which any material behaves like an elastic material.
Correct Answer : The area between the ultimate point and rupture
Explanation : Necking is a tensile strain deformation which is cased in after the ultimate amount of stress occurs in the material.
Correct Answer : zero
Correct Answer : true stress at fracture is higher than the ultimate stress
Correct Answer : intermediate columns
Explanation : * In T-sections, the shear centre is at the C.G. of the section* The point through which the resultant of the shear stresses, passes is known as shear centre* In the standard rolled channels, the shear centre is on the horizontal line passing through and away from the C.G. beyond web* In equal angles, the shear centre is on the horizontal plane and away from the C.G., outside of the leg projection
Correct Answer : WL / 8
Correct Answer : IE / L
Correct Answer : hoop stress
Correct Answer : l = 2a
Correct Answer : over hanging beams only
Correct Answer : fatigue of the metal
Correct Answer : body of equal strength
Correct Answer : yielding point
Correct Answer : Newton
Explanation : Force = mass x acceleration = kg x m/s² = N.
Correct Answer : Milestone
Explanation : Milestone means achievement. it is not and unit of distance.
Correct Answer : X=3
Explanation : The volumetric strain is the change in dimension in three directions and the linear strain depends on the change in only one direction so the volumetric strain is 1 times the linear strain in any of the three directions.
Correct Answer : 0.001
Explanation : The strain is given by = dL / L = 2/2000 = 0.001.
Correct Answer : creeping
Correct Answer : 10 cm
Correct Answer : 32 and 120
Correct Answer : pd / 2t
Correct Answer : axial tension loads
Correct Answer : one
Correct Answer : Stress diagram
Explanation : The stress diagram shows the variation of the axial load for all sections of the pan. The bending moment diagram shows the variation of moment in a beam. The shear force diagram shows the variation in the shear force due to loading in the beam.
Correct Answer : Shear stress
Explanation : Shear stress makes the body to shear off across the section. It is tangential to the area over which it acts. The corresponding strain is the shear strain.
Correct Answer : Shear resistance/shear area
Explanation : When force is applied, the twisting divides the body. The resistance is known as shear resistance and shear resistance per unit area is known as shear stress.
Correct Answer : a column
Correct Answer : elasticity
Correct Answer : 955.41 kg/cm²
Correct Answer : P and Q
Explaination : Bending stress comes when there is some kind of eccentric load. Torsional stress will come when the nut is rotating. Shear stress will come in tightening of a nut on bolt.
Correct Answer : triangle
Correct Answer : 8 times
Correct Answer : one-third of the base
Correct Answer : does not change during deformation
Correct Answer : 270 kg
Correct Answer : polar modulus
Correct Answer : maximum at the supports
Correct Answer : 0.25
Correct Answer : equal to 3π/16
Explanation : For circular plate, MI = π*d^4/64.For square plate, MI = d^4/12.So, Ratio = MI of circular plate/MI of square plate.= 3*π/16.
Correct Answer : equally on each fibre along horizontal plane
Correct Answer : (b/d)²
Correct Answer : twice the number of joints minus three
Correct Answer : top fibre
Correct Answer : large spans
Correct Answer : rectangle
Correct Answer : d/4
Correct Answer : 3S / bh
Correct Answer : 416
Correct Answer : 25 cm
Correct Answer : 1 / 2 (stress)² x volume of the member + Young's modulus E.
Explanation : Strain = dL/L = 0.1/100 = 0.001.
Correct Answer : 1.118
Correct Answer : double riveted double cover butt joint
Correct Answer : parabola
Correct Answer : square beam is more economical
Correct Answer : for triangular section is same as that of a rectangular section
Correct Answer : statically indeterminate
Correct Answer : cubic parabola
Correct Answer : r
Correct Answer : (σ₁² + σ₂² – 2σ₁σ₂ ) / 2E
Explanation : Strain energy = (σ₁ε₁+ σ₁ε₁ ) / 2E= (σ₁² + σ₂² – 2σ₁σ₂ ) / 2E.
Correct Answer : Not be in equilibrium
Explanation : The forces are not concurrent so the resultant force and couple both may be present. Thus the best choice is that forces are not in equilibrium.
Correct Answer : Product of strain and Young’s modulus of the material
Explanation : Strain energy per unit volume for solid = q² / 4G.
Correct Answer : 15.9 N-m
Explanation : Stress = 50,000 / 625π = 25.46Strain energy = σ²V/2E = 25.46×25.46×9817477 / (2×200000) = 15909.5 N-mm = 15.9 N-m.
Correct Answer : most distant
Correct Answer : moment-area-theorem
Correct Answer : 1/10
Correct Answer : algebraic sum of the transverse forces of the section
Correct Answer : statically determinate
Correct Answer : 120°
Correct Answer : 1/2 WL
Correct Answer : middle fourth rule of columns
Correct Answer : pass through the centroid of the section
Correct Answer : perpendicular to the axis of arch
Correct Answer : 1250 kg
Explanation : * The material of the beam is homogeneous and isotropic* The resultant pull or thrust on transverse section of a beam is zero* The value of the Young's modulus is the same in tension as well as in compression* Transverse section of a beam remains plane before and after bending
Correct Answer : Mr / ∑r²
Correct Answer : 24 / 15
Correct Answer : parabolic
Correct Answer : Variable with maximum on the neutral axis
Explanation : Maximum value of shear stress at neutral axis is τ = 3/2 τmeanSo, transverse shear stress is variable with a maximum in the neutral axis.
Correct Answer : 1MPa
Explanation : Shear stress = 10kN / 100mmx100mm = 1 N/mm² = 1MPa.
Correct Answer : cubical
Correct Answer : every-horizontal plane
Correct Answer : tension divided by the length
Correct Answer : 0.2275 mm
Correct Answer : changes sign
Correct Answer : 14.14 cm
Correct Answer : 100 N at the centre
Correct Answer : All radii get twisted due to torsion
Correct Answer : statically determinate structure
Correct Answer : linear
Correct Answer : Radians
Explanation : The slope is defined as at any point on the bent beam is the angle measured in terms of radians to which the tangent at that point makes with the x axis.
Correct Answer : Deflection curve
Explanation : An elastic curve is defined as the line to which the longitudinal axis of a beam deviates under given load. It is also called a deflection curve.
Correct Answer : Isoheytal method
Explanation : The method “Isoheytal” can be used for calculating run-off over an area. The remaining methods are effectively adopted to calculate the slope and deflection at a point in any type of beam.
Correct Answer : m
Explanation : The term “deflection” is defined as the transverse displacement of a point on any straight axis to the curved axis. It is expressed in metres (m).
Correct Answer : Macaulay's method
Explanation : Macaulay's method was devised by Mr WH Macaulay.Advantages : * Gives one continuous expression for bending moment* Constants of integration can be found by using end conditions* By using this method, slope and deflection at any section can be determined throughout the length of the beam.
Correct Answer : y
Explanation : The deflection of a point on the axis of the deflected beam is defined as the angle developed in radians with tangent at the section makes with the original axis of the beam.
Correct Answer : 15/16
Correct Answer : first row
Correct Answer : bending moment is zero or changes sign
Correct Answer : Center of gravity
Explanation : The centre of gravity of a body is the point through which the whole weight of the body acts. A body’s center of gravity is the point around which the resultant torque due to gravity forces vanishes. Where a gravity field can be considered to be uniform and the centre of gravity will be the same.
Correct Answer : Centroid
Explanation : The centroid is the point at which the total area of a plane figure is assumed to be concentrated. The centroid and centre of gravity are at the same point.
Correct Answer : At its middle point
Explanation : The centre of gravity of a uniform rod lies at its middle point. The whole weight of the rod acts through its middle point.
Correct Answer : from zero at the centre to a maximum at the circumference
Correct Answer : 1.2
Explanation : Bond stress is the shear stress acting parallel to the bar on the interface between the reinforcing bar and the surrounding concrete. Hence it is the stress developed between the contact surface of Steel and concrete to keep them together. The value of M20 designs Bond stress is 1.2 in tension.
Explanation : Bending is usually accompanied by shear. The combination of shear and bending stresses produces the principle stresses which causes diagonal tension in the beam section. This should be resisted by providing shear reinforcement in the form of vertical stirrups (or) bent up bars along with stirrups.
Correct Answer : 0.96
Explanation : The limiting percentage of steel for singly reinforced sections of M20 grade & Fe415 is 0.96.
Correct Answer : Base width
Explanation : In dams, the economy prevails if the cross section of a dam is provided with minimum base width. Base width “b” can be determined from the equation: b2 +ab+ a2 = H2/ S.
Correct Answer : 1775.12 kN/m²
Explanation : The maximum stress at the base section = W/b (1+6e/b)P= 4400/8 (1+6×2.97/8)= 1775.12 kN/m²
Correct Answer : Compressive
Explanation : If the stress developed in the dam section at the base is positive there it indicates the nature of stress to be compressive.
Correct Answer : tensile stress
Correct Answer : directly proportional
Correct Answer : rhombus of diagonals b/3 and h/3
Correct Answer : d = 6.05 √t
Correct Answer : at the built-in upper cross-section
Correct Answer : axial compressive loads
Correct Answer : Thin cylinder
Explanation : The thickness of plate is negligible when compared to the diameter of the cylindrical shell, and then it can be termed as a thin cylinder. The radius stress in the cylinder walls is negligible.
Correct Answer : 1/20
Explanation : In thin shells, the stress distribution over the thickness of the material is assumed to be uniform and the wall thickness is equal to or less than 1/ 20 of the internal diameter.
Correct Answer : Thin cylinders
Explanation : In thin cylindrical shells, the stresses are uniformly distributed throughout the wall. The type of stresses developed in thin cylinders is hoop stress and longitudinal stress. Ex: water supply mains, oil tanks, steam boilers and gas pipes.
Correct Answer : Proof resilience
Explanation : Proof resilience is defined as the maximum that can be absorbed with in the proportionality limit without creating a permanent distortion.
Correct Answer : Greater than
Explanation : The compressive strength of brittle materials is greater than its tensile strength. The tensile strength of ductile material is greater than its compressive strength.
Correct Answer : Less than
Explanation : The stress developed in a material without any permanent stress is called elastic limit and the breaking stress is always less than the ultimate stress.
Correct Answer : Column
Explanation : A vertical member subjected to direct compressive forces is called a column or pillar. The column transfers the load from the beams or slab to the footings and foundations.
Correct Answer : Strut
Explanation : The inclined member carrying compressive load in case of frames and trusses is called as a strut. A strut is a member of a structure in any position carrying an axial load. Strut may be horizontal, inclined or even vertical.
Correct Answer : Stanchion
Explanation : A built up rolled Steel section carrying compressive force is known as “stanchion”. A wood member carrying compressive force is called a “post”.
Correct Answer : Strain energy
Explanation : The capability of a material to absorb energy when it is deformed elastically and release that energy upon unloading is known resilience. This resilience is also termed as Strain energy.
Correct Answer : Work done
Explanation : By the principle of work, the amount of strain energy in a body is found. When a load acts on a body there will be deformation, which causes movement of the applied load. This work is done by the applied load.
Correct Answer : Long wall and short wall method
Explanation : Long wall short wall method is tedious and long lasting. In this method, the length of wall running in one direction are measured first out to out and that of running in the perpendicular direction are measured in to in.
Correct Answer : Specifications
Explanation : Drawings cannot give every information about materials and quality. The specifications give the nature and class of work, quantity of materials and workmanship. They are very useful during the execution of work.
Correct Answer : Frame
Explanation : Frame is a structure made up of several members riveted and welded together. The members of the frame are made in such a way that the form angle iron or channel sections.
Correct Answer : Perfect frame
Explanation : A perfect frame is 1 for which the following equation is satisfied m = 2j-3.A perfect frame is that which is composed of members just sufficient to keep it in equilibrium when loaded without any change.
Correct Answer : Bending moment
Explanation : If conditions of equilibrium are sufficient to analyse the structure fully, then it is statically determinate structure. In this bending moment at a section is independent of the material of the components of the structure.
Correct Answer : 45°
Explanation : Splayed wing walls permit smooth entry and exit of water under the bridge. The splay is usually provided at 45°. The weep holes are also provided.
Correct Answer : Stresses
Explanation : Statically indeterminate structures need some extra conditions for the further simplification. Normally stresses are produced due to variation in indeterminate beams.
Correct Answer : Gradient
Explanation : The gradient is defined as the longitudinal rise or fall off road surface love its length is expressed as ratio 1 vertical: n horizontal or as a percentage.
Correct Answer : 100 mm
Explanation : Sight distance is an important requirement for the safety of travel on highways the height of the object is taken to be at a depth of 100 mm above road.
Correct Answer : 0.5 m
Explanation : The minimum shoulder width provided for village roads is 0.5m.
Correct Answer : Earth quantities
Explanation : The line of sight of a driver above the road is taken as 1.2m. The height of the object is taken to be height of 100 mm. Sight distance is an important resource requirement for the safety of travel. The designing layout plays a very vital role.
Correct Answer : Transition curves
Explanation : The transition curves are necessary for a vehicle to have smooth entry of straight section into circular curve. They provide aesthetic experience of the road. They provide a graduate introduction of super elevation.
Correct Answer : 0.0036 radians
Explanation : Maximum slope at supports be i = A/EI= 180/50000i = 0.0036 radians.
Explanation : The slope in cantilever beam is zero at the fixed end of the cantilever and the slope is maximum at it’s free end. The slope is determined in the moment area method through Mohr’s theorems.
Correct Answer : Mid span
Explanation : In case simply supported beams, the slope is maximum at the end supports of the beam and relatively zero at midspan of a symmetrically loaded beam.
Correct Answer : 0.0225 radians
Explanation : The maximum slope at free support (in cantilever beam) = i = A/EI= 90/4000= 0.0225 radians.
Correct Answer : Protective canal
Explanation : The construction of protective canals and their development may be started during summer in hence they provide employment to the farmers at the time of drought and famine. Protective canals are not remunerative as productive canals.
Correct Answer : Dolomite
Explanation : Dolomite bricks are made especially from dolomite it contains nearly 30% lime and 22% of magnesium these bricks are inferior to magnesite bricks. They are generally used in the lining of blast furnaces.
Correct Answer : bauxite bricks
Explanation : Bauxite bricks contain nearly 75% of aluminium and it is mixed with fire clay 15 to 30% and added some water to mould. High alumina bricks are resistant to corrosion.
Correct Answer : 45mm
Explanation : The deflection at any point on the elastic curve equal to Ax/EIBut, we know that A/EI is already slope equation.So, slope × (the distance of centre of gravity of bending moment to free end = 2m).0.0225 × 20.045m ~ 45 mm.
Correct Answer : Head regulator
Explanation : The head regulator is one of the canal regulation works. It can control the entry of silt into the canal. It can be used as a metre for measuring the discharge. It can shut out river floods.
Correct Answer : Weir type escape
Explanation : The crest of the weir is fixed at canal FSL. When the water level rises above FSL, it is disposed of into the natural drain. Hence, the tale escape is also known as weir type escape.
Correct Answer : Recharge to ground water
Explanation : The methods which are adopted for preserving the water in the soil from being lost are called as soil moisture conservation methods. The major part of the water is lost through evapotranspiration. The recharge to groundwater is one of the techniques in rainwater harvesting.
Correct Answer : 125 years
Explanation : Warabandi is a rotational method for allocation of the available water equally in an irrigation system. It provides continuous rotation of water generally lasts 7 days. It has been effectively practiced in India for more than 125 years.
Correct Answer : Plasticity
Explanation : Plasticity in the property of Material by which the material can undergo permanent deformation and fails to regain its original shape on removal of load. Examples are gold, lead, etc.
Correct Answer : Spinel
Explanation : The spinal bricks belong to neutral bricks. The spinel bricks mainly consist of alumina and magnesia. These bricks are widely used in the lining of electric furnace.
Correct Answer : 212mm
Explanation : The limiting depth of neutral axis Fe 250 steel isXu (max) = 0.53 × d ( for Fe250)= 0.53 × 400= 212mm.
Correct Answer : Bends
Explanation : In situations, where straight anchorage length cannot be provided due to lack of space. To improve the anchorage of bars, standard bends are provided in deformed bars.
Correct Answer : One way slab
Explanation : If the ratio of the longest span the shorter span is greater than 2 or A slab supporting only in two edges (opposite to each other) is called one way slab. This slab spans across shorter span practically.
Correct Answer : 1m
Explanation : The stair consists of series of steps with landings at appropriate intervals. The width of stair depends upon the type of building in which it is provided. Generally, in residential buildings, the width of stair is 1 m.
Correct Answer : 2.5 m
Explanation : e = Z – b/2. [The value of Z = 5.5m] = 5.5 – 6/2= 5.5 – 3= 2.5 m.
Correct Answer : Character of material
Explanation : The upstream and downstream slopes of the Dam should be stable in all situations the side slopes depend upon1.Height of the dam2.Character of material3.Nature of foundation.
Correct Answer : x = 3
Correct Answer : n > 2j - 3
Correct Answer : crown of the arch
Correct Answer : Algebraic sum of the moments of all the forces on either side of the section
Correct Answer : malleability
Correct Answer : elastic structures
Correct Answer : l > 2a
Correct Answer : single inverted V-butt joint
Correct Answer : Top width
Explanation : Hydraulic depth is the ratio of wetted area to the top with (T). It is denoted by DD = A/T.
Correct Answer : Lock gates
Explanation : Gates which are used to change the water level in a canal or a river are known as lock gates. If a canal or a river has a vertical fall at any section, it is necessary to raise or lower the water level in order to transfer the boat from upper water level to lower one.
Correct Answer : Sluice gates
Explanation : In hydraulic structures, the openings are provided to carry water from its storage place to place of utilisation. The flow of water through such openings is controlled by means of sluice gates.
Correct Answer : inversely proportional
Explanation : The ductility of material increases with the increase in percentage reduction in area of a specimen under tensile stress.
Correct Answer : Osmoscope
Explanation : The main causes of odour in water are algae, sewage and dissolved gases. Taste and odour can also be expressed in terms of odour density. Odour can be estimated by osmoscope.
Correct Answer : Platinum cobalt scale
Explanation : Colour is caused by the presence of colloidal substance is aquatic growth etc. in water should be distinguished from turbidity which is termed as apparent colour. The colour is expressed in Platinum Cobalt scale. Colour may be removed by coagulation and adsorption method.
Correct Answer : De chlorination
Explanation : De chlorination means removing the chlorine from the water this is generally required when super chlorination has been practiced.
Correct Answer : 5 %
Explanation : According to the board of Indian Standards [BIS], the sand which is used for filtration process should not lose weight more than 5% when placed in hydrochloric acid for one day (24 hours).
Correct Answer : 1 to 3 months
Explanation : For the purpose of cleaning the top layer of sand is removed to a depth of 15 mm to 25 mm. The water is admitted to the filter the cleaning interval varies from 1 to 3 months.
Correct Answer : 40 mm
Explanation : Generally foundation concrete is laid about thickness of 30 cm with proportion 1:4:8 (or) 1:5:10 and are measured in m³.Before laying the concrete bed level, sand filling and sinking must be done and checked properly.
Correct Answer : Seal coat
Explanation : Seal code is final coat lay over bituminous pavements which are not impervious. Seal coat develops skid resistant texture and they provide better riding surface.
Correct Answer : Rail joint
Explanation : The joint which is made between two rails together with two fish plates and four fish bolts to form an expansion gap of 1.5 to 3 mm. Rail joint is the weakest part in the railway track.
Correct Answer : Screw spike
Explanation : Holding capacity of rails to sleepers is more and costly. Hence screw spike is used in driving and extraction. Though it is costly and time consuming, the sabotage problem is eliminated due to screw spike.
Correct Answer : 1 in 20
Explanation : The wheels of rolling stock are made in the shape of a frustum of a cone having a slope of 1 in 20 is known as coning of wheels. The objective of coning of wheels is to prevent lateral movement of trains in straight track.
Correct Answer : Sleepers
Explanation : Sleepers are transverse ties on which the rails are laid and transfer the load from rails to ballast. The main function of a sleeper is to provide a firm and even support to rails.
Correct Answer : Wave height
Explanation : The minimum height of the free board for wave action is generally taken to be equal to 1.5 hw. Where hw = height of wave action.It can be calculated using 0.032(VF)½.
Correct Answer : Breaching
Explanation : Sometimes during construction, the surplus works are avoided in many tanks. In such circumstances, breaching sections are provided in the dams to allow the surplus flood discharge. With this the scouring of section can be avoided.
Correct Answer : Baylis turbidometer
Explanation : The turbidity of potable water should be within 10 PPM or with in 10 units on the silica scale. High turbidity of water can be determined by Jackson turbidity metre and low turbidity of water can be determined by baylis turbidity metre.
Correct Answer : 500 ppm
Explanation : Analytically, the total solids content of water is defined as all the matter that remains as residue upon evaporation. The standards for drinking water is acceptable limit is 500 ppm.
Correct Answer : B. Coli
Explanation : The pathogenic bacteria are generally inherent in the qualifying group of Bacteria of which the bacillus coli (B. Coli) now called as Escherichia coli (E.Coli ) is prominent.
Correct Answer : 150 mg/L
Explanation : Sulphates ion is one of the major ions occurring in natural waters. In drinking water, sulphate causes a laxative effect and leads to scale formation in boilers. The desirable limit in drinking water is 150 mg /L.
Correct Answer : 2 to 3 ppm
Explanation : Ozone easily breaks down with oxygen and releases nascent oxygen which is powerful in killing bacteria. It also reduces organic matter present in the water the dosage of ozone is about 2 to 3 ppm.
Correct Answer : 99 %
Explanation : The slow sand filters remove suspended and bacterial impurities to an extent of 98 to 99%. It requires a large area and unsuitable for treating high turbid water.
Correct Answer : 0.25 to 5 cumecs
Explanation : The major distributary takes off from a branch canal to distribute the water to various parts of the field. The supply of the water varies from 0.25 to 5 cumecs.
Correct Answer : 2.5:1
Explanation : According to Terazghi, the following upstream slopes should be recommended.1. Homogeneous well graded – 2.5 : 12. Homogeneous coarse silt – 3 : 13. Sand and gravel with RCC core wall – 2.5 : 1.
Correct Answer : Outlets
Explanation : An outlet is a simple and small irrigation structure which is constructed along the distributaries. The amount of water that is withdrawn through the outlet is in proportion to the area that is irrigated below respective point.