What is the ratio of area swept by the object and the corresponding time of flight equal to?

h/2

h/3

Correct Answer : h/2

Explanation : According to the figure below, the rate of area swept by the radius vector is always a constant. This is h/2. Where A1 is the area swept by the planet by moving from periapsis to point P. The relation is given by:
dA/dt = h/2

Recently Updated in Spaceflight Mechanics Questions

Which of the equations determines the time of flight for a parabolic trajectory?

Barker�s equation

Euler�s equation

Kepler�s equation

Madelung equation

Correct Answer : Option (A) : Barker�s equation

Explanation : Barker’s equation is used to determine the time of flight from periapsis to a position on the parabolic trajectory at a true anomaly of θ.

What is the imaginary angle between the periapsis point and the imagined position of an object for the same elapsed time called?

Eccentricity

True anomaly

Mean anomaly

Eccentric anomaly

Correct Answer : Option (C) : Mean anomaly

Explanation : The mean anomaly is an angle an imaginary satellite would have if it were in a circular orbit around the center point O with a time period T equal to the true satellite orbit.

Which of the angles defined by Kepler is used to obtain the position of the body using the auxiliary circle?

Eccentricity

True anomaly

Mean anomaly

Eccentric anomaly

Correct Answer : Option (D) : Eccentric anomaly

Explanation : Eccentric anomaly is the angle that is formed by drawing an auxiliary circle of an ellipse with center O and focus F. A perpendicular line is drawn to the semimajor axis intersecting at A. The angle E thus formed is the eccentric anomaly. It is used to obtain the position of the body in the orbit.