A twin turbo prop is flying with power loading of 12. What will be the maximum velocity?

48.225 m/s

48.225 km/h

48.225 mph

225.48 m/h

Correct Answer : 48.225 mph

Explanation : Given, Power loading P.L. = 12.
P.L. is given by,
W/hp = 1 / (a*Vmax^c), for twin turbo prop a=0.012, c=0.5.
Hence, maximum velocity Vmax is given by,
12 = 1 / (0.012*Vmax^0.5)
0.012*Vmax^0.5 = 1/12.
Vmax^0.5 = 1 / (0.012*12) = 6.944
Takin log at both sides,
0.5*ln (Vmax) = ln (6.944) = 1.937
Now, taking anti-log,
Vmax = e^(1.937/0.5) = e^3.875 = 48.225mph

Recently Updated in Aircraft Design Questions

What should be the aspect ratio (AR) of the prop aircraft if it is designed to work with maximum loiter wing loading of 32, CD0 = 0.06, dynamic pressure of 20 unit and Oswald efficiency as 0.6.

9.65

8.54

7.65

7.54

Correct Answer : Option (B) : 7.54

Explaination :

An aircraft is to be designed to have max lift coefficient as 2.8 and at q=10Pa. If maximum load factor n=5 then, what will be the stall speed?

1.80m/s

1.80mph

2.80mph

2.80m/s

Correct Answer : Option (A) : 1.80m/s

Explanation :

An aircraft has lift to drag ratio during cruise as 2.5 and load factor as 1.2. Which value of thrust loading should be selected?

0.28

0.38

0.48

0.58

Correct Answer : Option (C) : 0.48

Explanation : Given, load factor n=1.2, lift to drag L/D = 2.5
Now, n at cruise is given by, n = (T/W)*(L/D).
Hence, T/w is given as,
T/W = n / (L/D) = 1.2/2.5 = 0.48.