A)
Wing drag
B)
Wing fillet
C)
Wing chamfer
D)
T-tail arrangement

Correct Answer :  

Recently Updated in Aircraft Design Questions
If for a given fuselage Stop=10m2, Aside=14m2, L = 10m then, find the ratio of wetted area to the volume of fuselage.
A)
3.42 per m
B)
4.001
C)
6.68 per m3
D)
8.36 m

Correct Answer : Option (A) :   3.42 per m

Explaination : Given, Stop=10m2, Aside=14m2, L = 10m.
Now ratio of wetted area Aw and volume V is given by,
Aw/V = 2*L*(Stop + Aside) / (Stop*Aside)
Aw/V = 2*10*(10+14) / (10*14) = 20*24/140 = 3.42 per m.

Wing has planform area of 2m². If wing is paper thin then, find wetted area of the wing.
A)
4m²
B)
5m²
C)
10m²
D)
20m²

Correct Answer : Option (A) :   4m²

Explaination : Given, planform area = 2m².
Since, wing is paper thin wetted are = 2*planform area = 2*2 = 4m².

Wetted area of a rectangular body is 64.64m². Find the average projected area.
A)
15.85 m²
B)
16.16m²
C)
25.368 km
D)
45.45 cm

Correct Answer : Option (B) :   16.16m²

Explaination : Given, Aw = 64.64m².
Now, average projected area A = Aw/4 = 64.64/4 = 16.16m².

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