Find the strain of a brass rod of length 100mm which is subjected to a tensile load of 50kN when the extension of rod is equal to 0.1mm?

A)
0.01
B)
0.05
C)
0.001
D)
0.005

Correct Answer :   0.001


Explanation : Strain = dL/L = 0.1/100 = 0.001.