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Civil Engineering : Strength of Materials - Quiz(MCQ)
A)
The ratio of change in length to the original length
B)
The ratio of tensile force to the change in length
C)
The ratio of original length to the change in length
D)
The ratio of change in length to the tensile force applied

Correct Answer :   The ratio of change in length to the original length


Explanation : The tensile stress is the ratio of tensile force to the change i length. It is the stress induced in a body when subjected to two equal and opposite pulls. The ratio of change in length to the original length is the tensile strain.

A)
Three forces acting at a point will be in equilibrium
B)
Three forces acting at a point can be represented by a triangle, each side being proportional to force
C)
If three forces acting upon a particle are represented in magnitude and direction by the sides of a triangle, taken in order, they will be in equilibrium
D)
If three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two

Correct Answer :   If three forces acting at a point are in equilibrium, each force is proportional to the sine of the angle between the other two

A)
decreases more rapidly
B)
increases more rapidly
C)
decreases in proportion to the stress
D)
increases in proportion to the stress

Correct Answer :   increases more rapidly

A)
Their total sum is zero
B)
Two resolved parts in two directions at right angles are equal
C)
Sum of resolved parts in any two perpendicular directions are both zero
D)
All of the above

Correct Answer :   Sum of resolved parts in any two perpendicular directions are both zero

A)
Shear strain
B)
Tensile strain
C)
Compressive strain
D)
All of the above

Correct Answer :   All of the above

A)
square root of the moment of inertia
B)
square root of the inverse of the area
C)
square root of the moment of inertia divided by area of the section
D)
None of the above

Correct Answer :   None of the above

A)
WL/9√3
B)
WL/4
C)
WL³/9√3
D)
WL/8

Correct Answer :   WL³/9√3

A)
WL²/4 EI
B)
WL²/2 EI
C)
WL²/6 EI
D)
WL²/5 EI

Correct Answer :   WL²/2 EI

A)
more than that necessary to stop it
B)
more than that necessary to continue it
C)
less than that necessary to stop it
D)
less than that necessary to continue it

Correct Answer :   more than that necessary to continue it

A)
to deform it
B)
to resist elongation
C)
to resist shortening
D)
All of the above

Correct Answer :   All of the above

A)
A rigid material has no plastic zone
B)
A brittle material has no plastic zone
C)
A ductile material has large plastic zone
D)
All of the above

Correct Answer :   All of the above

A)
M/I = R/E = Y/F
B)
I/M = E/R = Y/F
C)
M/I = E/R = Y/F
D)
None of the above

Correct Answer :   M/I = E/R = Y/F

A)
Elasticity
B)
Ductility
C)
Plasticity
D)
Malleability

Correct Answer :   Elasticity


Explanation : When an external force acts on a body, the body tends to undergo some deformation. If the external force is removed and the body comes back to its original shape and size, the body is known as elastic body and this property is called elasticity.

A)
Ductility
B)
Malleability
C)
Elasticity
D)
Plasticity

Correct Answer :   Malleability


Explanation : A material can be beaten into thin plates by its property of malleability.

A)
Hooke's law
B)
Stress law
C)
Poisson’s law
D)
Bernoulli’s law

Correct Answer :   Hooke's law


Explanation : The hooke's law is valid under the elastic limit of a body. It itself states that stress is proportional to the strain within the elastic limit.

A)
isotropic material
B)
homogeneous material
C)
Both (A) and (B)
D)
heterogeneous material

Correct Answer :   heterogeneous material

A)
chain riveting
B)
zig-zag riveting
C)
diamond riveting
D)
None of the above

Correct Answer :   diamond riveting

A)
Plastic modulus
B)
Poisson’s ratio
C)
Elastic modulus
D)
None of the above

Correct Answer :   Elastic modulus


Explanation : The elastic modulus is the ratio of stress and strain. So on the stress strain curve, it is the slope.

A)
It is the percentage of stress and stain
B)
It is the relationship between stress and strain
C)
It is the difference between stress and strain
D)
None of the above

Correct Answer :   It is the relationship between stress and strain


Explanation : The relationship between stress and strain on a graph is the stress strain curve. It represents the change in stress with change in strain.

A)
Elastic limit
B)
Ultimate point
C)
Lower yield point
D)
Upper yield point

Correct Answer :   Elastic limit


Explanation : The curve will be stress strain proportional upto the proportionality limit. After these, the elastic limit will occur.

A)
no shear stress acts
B)
maximum shear stress acts
C)
minimum shear stress acts
D)
None of the above

Correct Answer :   no shear stress acts

A)
rigid
B)
elastic
C)
plastic
D)
None of the above

Correct Answer :   plastic

A)
Q - R = zero
B)
Q + R = 10 tonnes
C)
Q = 10 tonnes and R = zero
D)
Q and R each is equal to 10 tonnes

Correct Answer :   Q and R each is equal to 10 tonnes

A)
0.025
B)
0.0012
C)
0.0046
D)
0.0014

Correct Answer :   0.0012


Explanation : Strain = dL/L = 0.3/250 = 0.0012

A)
0.3mm
B)
0.5mm
C)
0.2mm
D)
0.1mm

Correct Answer :   0.5mm


Explanation : dL = strain x L = 0.005 x 100 = 0.5mm.

A)
b+d / b
B)
b-d / b
C)
d-b / d
D)
b-d / d

Correct Answer :   b-d / b

A)
less than one
B)
equal to one
C)
greater than one
D)
None of the above

Correct Answer :   less than one

A)
vertical components at either end
B)
horizontal components at either end
C)
horizontal and vertical components at both the ends
D)
horizontal component at one end and vertical component at the other

Correct Answer :   horizontal and vertical components at both the ends

A)
σE²/V
B)
σE²/V
C)
σV²/E
D)
σV²/2E

Correct Answer :   σV²/2E

A)
sV/E
B)
s²V/2E
C)
sV²/E
D)
sV/2E

Correct Answer :   s²V/2E


Explanation : Strain energy = s²V/2E.

A)
τ²/E x (1+ v)
B)
τ²/E x (1+ v)
C)
τ²/2E x (1+ v)
D)
τ²/E x (2+ v)

Correct Answer :   τ²/E x (1+ v)


Explanation : σ₁=τ, σâ‚‚= -τσ₃=0
U = (τ²+- τ²-2μτ(-τ))V = τ²/E x (1+ v)V.

A)
under the load
B)
at the supports
C)
at the mid span
D)
anywhere on the beam

Correct Answer :   under the load

37 .
The length of a column, having a uniform circular cross-section of 7.5 cm diameter and whose ends are hinged, is 5 m. If the value of E for the material is 2100 tonnes/cm², the permissible maximum crippling load will be____.
A)
 
1.288 tonnes
B)
12.88
C)
128.8 tonnes
D)
288.0

Correct Answer :   12.88

A)
shear force
B)
compressive force
C)
tensile force
D)
bending moment

Correct Answer :   compressive force

A)
1
B)
2
C)
1/1.5
D)
2/1.5

Correct Answer :   2/1.5


Explanation : Normal stress at B = Total load acting at B / Area of a cross-section at B

= (P + P) / 1.5 A = 2P/ 1.5A = 2/1.5.

A)
The strain per unit volume
B)
The stress per unit are
C)
The force applied in stretching the body
D)
The work done by the applied load In stretching the body

Correct Answer :   The work done by the applied load In stretching the body


Explanation : The strain energy stored in a body is equal to the work done by the applied load in stretching the body.

A)
Maximum stress in gradual load is half to the maximum stress in sudden load
B)
Maximum stress in gradual load is twice to the maximum stress in sudden load
C)
Maximum stress in gradual load is equal to the maximum stress in sudden load
D)
Maximum stress in gradual load is four times to the maximum stress in sudden load

Correct Answer :   Maximum stress in gradual load is half to the maximum stress in sudden load


Explanation : Maximum stress in gradual loading = P/A
Maximum stress in sudden loading = 2P/A.

A)
71.02 N/mm²
B)
47.746 N/mm²
C)
48.456 N/mm²
D)
34.15 N/mm²

Correct Answer :   47.746 N/mm²


Explanation : Stress = Load/ area = 60,000 / (π/4 D²) = 47.746 N/mm²

A)
2.14mm
B)
3.45mm
C)
4.77mm
D)
6.58mm

Correct Answer :   4.77mm


Explanation : Stress = Load/ area = 60,000 / (π/4 D²) = 47.746 N/mm²

So stretch = stress x length / E = 4.77mm.

A)
100 N/mm²
B)
120 N/mm²
C)
125 N/mm²
D)
150 N/mm²

Correct Answer :   125 N/mm²


Explanation : Stress = load / area = 100,000/ (20×40) = 125 N/mm²

A)
Three times its shear modulus
B)
Four times its shear modulus
C)
Equal to its shear modulus
D)
Not determinable

Correct Answer :   Three times its shear modulus


Explanation : Elastic modulus = E
Shear modulus = G
E = 2G ( 1 + μ )
Given, μ= 0.5, E = 2×1.5xG
E = 3G.

A)
4
B)
3
C)
2
D)
1

Correct Answer :   3

A)
E/2L
B)
L/2E
C)
E/2L²
D)
L²/2E

Correct Answer :   L²/2E


Explanation : The elongation of bar due to its own weight is δ= WL/2AE
Now W = ρAL
There fore δ= L² / 2E.

A)
1/3
B)
1/4
C)
1/5
D)
1/6

Correct Answer :   1/3


Explanation : Longitudinal strain = 0.09/200
Lateral strain = – 0.0045/30
Poissons ratio = – lateral strain/ longitudinal strain
= 0.0045/30 x 200/0.09
= 1/3.

A)
1.5
B)
2.5
C)
3.00
D)
3.75

Correct Answer :   2.5


Explanation : Modulus of rigidity, G = E/2(1 + μ)
Therefore, E/G = 2x(1+0.25) = 2.5.

A)
plastic point
B)
elastic limit
C)
limit of proportionality
D)
None of the above

Correct Answer :   limit of proportionality

A)
Isotropic
B)
Hard
C)
Brittle
D)
Homogeneous

Correct Answer :   Isotropic


Explanation : Same elastic properties in all direction is called the homogenity of a material.

A)
Rigid
B)
Plastic
C)
Elastic
D)
None of the above

Correct Answer :   Plastic


Explanation : A plastic material does not regain its original shape after removal of load. An elastic material regain its original shape after removal of load.

A)
Plastic limit
B)
Elastic limit
C)
Deformation limit
D)
None of the above

Correct Answer :   Elastic limit


Explanation : The body only regain its previous shape and size only upto its elastic limit.

A)
plane frame
B)
grid frame
C)
truss frame
D)
space frame

Correct Answer :   plane frame

A)
one end is fixed and other end is hinged
B)
one end is fixed and the other end entirely free
C)
both the ends are fixed
D)
both ends are hinged or pin jointed

Correct Answer :   both the ends are fixed

A)
Hard
B)
Brittle
C)
Homogenous
D)
Isotropic

Correct Answer :   Isotropic


Explanation : Isotropic materials have the same elastic properties in all directions.

A)
Increases more rapidly
B)
Decreases more rapidly
C)
Increases in proportion to the stress
D)
Decreases in proportion to the stress

Correct Answer :   Increases more rapidly


Explanation : On reaching the tensile stress to the elastic limit after the proportionality limit, the stress is no longer proportional to the strain. Then the value of strain rapidly increases.

A)
Hypo elastic materials
B)
Hyper elastic materials
C)
Cauchy elastic materials
D)
None of the above

Correct Answer :   Hyper elastic materials


Explanation : The hyper elastic materials are derived from a strain energy density function. A model is hyper elastic if and only if it is possible to express the cauchy stress tensor as a function of the deformation gradient.

A)
at the centre of the section
B)
at a distance r/2 from the centre
C)
at the top of the surface
D)
at a distance 3/4 r from the centre

Correct Answer :   at the top of the surface

A)
Yield plateau
B)
Ultimate point
C)
Upper yield point
D)
None of the above

Correct Answer :   Yield plateau


Explanation : The points on the curve comes in the given order :

A. proportionality limit
B. elastic limit
C. upper yield point
D. lower yield point
E. yield plateau
F. ultimate point
G. breaking point.

A)
Upper yield point
B)
Ultimate point
C)
Breaking point
D)
lower yield point

Correct Answer :   Ultimate point


Explanation : After the yield plateau the curve will go up to its maximum limit of stress which is its ultimate point.

A)
WL / 3
B)
WL / 4
C)
5WL / 4
D)
3WL / 12

Correct Answer :   WL / 3

A)
at left hinge only
B)
at right hinge only
C)
at both right and left hinges
D)
at all the three hinges

Correct Answer :   at all the three hinges

A)
directly proportional to the applied torque
B)
inversely proportional to the distance from the axis
C)
directly proportional to the distance from the axis
D)
inversely proportional to the polar moment of inertia

Correct Answer :   inversely proportional to the distance from the axis

A)
fibres do not undergo strain
B)
fibres undergo maximum strain
C)
fibres undergo minimum strain
D)
None of the above

Correct Answer :   fibres do not undergo strain

A)
0.005
B)
0.0105
C)
0.0010
D)
0.00105

Correct Answer :   0.00105


Explanation : Strain = dL/L = 0.21/200 = 0.0005.

A)
2
B)
0.2
C)
0.02
D)
0.002

Correct Answer :   2


Explanation : The percentage elongation = dL/L x 100 = 2/100 x 100 = 2.

A)
The ratio of axial deformation to the original length
B)
The strain at right angles to the direction of applied load
C)
The ratio of deformation in area to the original area
D)
The ratio of length of body to the tensile force applied on it

Correct Answer :   The strain at right angles to the direction of applied load


Explanation : The lateral strain is the strain at right angles to the direction of the applied load. The lateral strain is accompanied by the longitudinal strain.

A)
17.3
B)
117.2
C)
137.2
D)
173.2

Correct Answer :   173.2

A)
l
B)
0.5 l
C)
2 l
D)
0.7 l

Correct Answer :   2 l

A)
l
B)
0.5 l
C)
0.7 l
D)
2 l

Correct Answer :   0.5 l

A)
1/2 times the rise of the crown
B)
1/3 times the rise of the crown
C)
1/4 times the rise of the crown
D)
3/4 times the rise of the crown

Correct Answer :   3/4 times the rise of the crown

A)
nothing on the bending throughout
B)
to increase the bending moment throughout
C)
to reduce the bending moment throughout
D)
All of the above

Correct Answer :   to reduce the bending moment throughout

A)
P²L³/3EI
B)
P²L³/6EI
C)
P²L³/4EI
D)
P²L³/24EI

Correct Answer :   P²L³/6EI


Explanation : We may do it taking average

Strain energy = Average force x displacement = (P/2) x PL³/3EI = P²L³/6EI.

A)
125 kg-cm
B)
100 kg-cm
C)
500 kg-cm
D)
1000 kg-cm

Correct Answer :   125 kg-cm


Explanation : Strain energy stored = τ²V/2G = 500²/2×10⁶ x 40x5x5 = 125 kg-cm.

A)
varies with slope
B)
maximum at crown
C)
maximum at springings
D)
maximum at quarter points

Correct Answer :   varies with slope

A)
shear and axial force
B)
shear force and thrust
C)
bending moment and shear force
D)
thrust, shear force and bending moment.

Correct Answer :   thrust, shear force and bending moment.

A)
Stress law
B)
Poisson's law
C)
Hooke's law
D)
Bernoulli's law

Correct Answer :   Hooke's law

A)
Shear stress
B)
Normal stress
C)
Thermal stress
D)
None of the above

Correct Answer :   Normal stress


Explanation : Normal stress acts in a direction perpendicular to the area. Normal stress is of two types tensile and compressive stress.

A)
Shear and bending
B)
Tensile and thermal stresses
C)
Tensile and compressive stresses
D)
Compressive and plane stresses

Correct Answer :   Tensile and compressive stresses


Explanation : The normal stress is divided into tensile stress and compressive stress.

A)
3
B)
2
C)
5
D)
6

Correct Answer :   3


Explanation : In a body loaded under plane stress conditions, the number of independent stress components is 3 I.e. two normal components and one shear component.

A)
At every point of the bar
B)
At the lower cross-section
C)
At the central cross-section
D)
At the built-in upper cross-section

Correct Answer :   At the built-in upper cross-section


Explanation : The stress is the load per unit area. After the addition of weight in the bar due to its loading on the lower end the force will increase in the upper cross-section resulting in the maximum stress at the built-in upper cross-section.

A)
634 N-m
B)
245.5 N-m
C)
312.5 N-m
D)
314500 N-mm

Correct Answer :   312.5 N-m


Explanation : Stress = load / area = 100,000/ (20×40) = 125 N/mm²

Strain energy = σ²V/2E = 125x125x20x40x5000/ (2×100,000) = 312500 N-mm = 312.5N-m.

A)
0.375
B)
0.125
C)
0.200
D)
0.150

Correct Answer :   0.125


Explanation : We know that, μ = (3K – 2G) / (6K + 2G)
Here K = G
Therefore, μ = 3-2 / 6+2 = 0.125.

A)
0.25
B)
0.33
C)
0.28
D)
0.30

Correct Answer :   0.33


Explanation : Longitudinal strain = 0.150/400 = 0.000375

Lateral strain = – 0.005/40 = -0.000125

Poissons ratio = – lateral strain/longitudinal strain

= 0.33.

A)
73 GN/m²
B)
80 GN/m²
C)
93.3 GN/m²
D)
103.9 GN/m²

Correct Answer :   73 GN/m²


Explanation : The relationship between E, G, and μ is given by

E = 2G (1 + μ)
G = 189.8 / 2(1 + 0.30)
G = 73 GN/m²

A)
70
B)
80
C)
125
D)
200

Correct Answer :   80


Explanation : The relationship between E, G and μ is E = 2G (1 + μ)

G = 200 / 2(1 + 0.25)

G = 80.

A)
Shear stress
B)
Tensile stress
C)
Bending stress
D)
Compressive stress

Correct Answer :   Compressive stress


Explanation : Concrete has the property of taking a good amount of compressive stress. So, In the reinforcement bar, the compressive stress is taken by the concrete.

A)
0.20
B)
0.25
C)
0.50
D)
Zero

Correct Answer :   Zero


Explanation : As volumetric strain = (1-2μ)σ/E

Here the value of μ is 0.5 so 1 – 2 * 0.5 becomes zero.

Therefore whatever be the stress the value of volumetric strain will be zero.

A)
M²
B)
√M
C)
√M²
D)
bending moment (M)

Correct Answer :   bending moment (M)

A)
5 tonnes metre
B)
10 tonnes metre
C)
15 tonnes metre
D)
20 tonnes metre

Correct Answer :   20 tonnes metre

A)
b = 57.73 cm d = 81.65 cm
B)
b = 81.65 cm d = 57.73 cm
C)
b = 50.00 cm d = 50.00 cm
D)
b = 40.00 cm d = 80.00 cm

Correct Answer :   b = 57.73 cm d = 81.65 cm

A)
zero
B)
infinite
C)
maximum
D)
minimum

Correct Answer :   infinite

A)
point of inflexion
B)
point of virtual hinge
C)
point of contraflexture
D)
All of the above

Correct Answer :   All of the above

A)
Stress modulus
B)
Plastic modulus
C)
Elastic modulus
D)
Poisson’s ratio

Correct Answer :   Elastic modulus


Explanation : The elastic modulus is the ratio of stress to strain.

A)
one-quarter of the radius
B)
one-third of the radius
C)
one-fifth of the radius
D)
one-sixth of the radius

Correct Answer :   one-quarter of the radius

A)
B.M. is same throughout the beam
B)
deflection is same throughout the beam
C)
shear stress is same throughout the beam
D)
bending stress is same throughout the beam

Correct Answer :   bending stress is same throughout the beam

A)
100 √2 kg/cm²
B)
150 √2 kg/cm²
C)
200 √2 kg/cm²
D)
250 √2 kg/cm²

Correct Answer :   100 √2 kg/cm²

A)
pin-jointed truss
B)
of any type
C)
statically determinate
D)
None of the above

Correct Answer :   of any type

A)
Ï€
B)
Ï€2
C)
1/Ï€
D)
10 π

Correct Answer :   10 Ï€

A)
distributed load.
B)
3/8th the distributed load
C)
5/8th the distributed load
D)
half the distributed load

Correct Answer :   5/8th the distributed load

A)
Last point
B)
Breaking point
C)
Elastic limit
D)
Material limit

Correct Answer :   Breaking point


Explanation : After the ultimate point the value of stress will reduce on increasing of strain and ultimately the material will break.

A)
Up to which if the load is removed, original volume and shapes are regained
B)
up to which stress is proportional to strain
C)
At which elongation takes place without application of additional load
D)
None of the above

Correct Answer :   Up to which if the load is removed, original volume and shapes are regained


Explanation : The elastic limit is that limit up to which any material behaves like an elastic material.

A)
The area between the ultimate point and rupture
B)
The area between the plastic limit and elastic limit
C)
The area between the ultimate point and initial point
D)
The area between lower yield point and upper yield point

Correct Answer :   The area between the ultimate point and rupture


Explanation : Necking is a tensile strain deformation which is cased in after the ultimate amount of stress occurs in the material.

A)
four
B)
three
C)
two
D)
zero

Correct Answer :   zero

A)
true stress at fracture is the same as the ultimate stress
B)
nominal stress at fracture is higher than the ultimate stress
C)
true stress at fracture is higher than the ultimate stress
D)
None of the above

Correct Answer :   true stress at fracture is higher than the ultimate stress

A)
long columns
B)
intermediate columns
C)
short columns
D)
very long columns

Correct Answer :   intermediate columns

A)
In T-sections, the shear centre is at the C.G. of the section
B)
The point through which the resultant of the shear stresses, passes is known as shear centre
C)
In equal angles, the shear centre is on the horizontal plane and away from the C.G., outside of the leg projection
D)
All of the above

Correct Answer :   All of the above


Explanation : * In T-sections, the shear centre is at the C.G. of the section
* The point through which the resultant of the shear stresses, passes is known as shear centre
* In the standard rolled channels, the shear centre is on the horizontal line passing through and away from the C.G. beyond web
* In equal angles, the shear centre is on the horizontal plane and away from the C.G., outside of the leg projection

A)
WL / 8
B)
WL / 6
C)
WL / 4
D)
WL / 2

Correct Answer :   WL / 8

A)
EI / 2L
B)
IE / L
C)
3EI / L
D)
4EI / L

Correct Answer :   IE / L

A)
yield stress
B)
longitudinal stress
C)
hoop stress
D)
circumferential stress

Correct Answer :   hoop stress

119 .
In a simply supported beam (l + 2a) with equal overhangs (a) and carrying a uniformly distributed load over its entire length, B.M. at the middle point of the beam will be zero if
A)
l = 2a
B)
l = 4a
C)
l < 2a
D)
l > 3a

Correct Answer :   l = 2a

A)
continuous beams only
B)
cantilever beams only
C)
over hanging beams only
D)
All of the above

Correct Answer :   over hanging beams only

A)
plasticity of the metal
B)
fatigue of the metal
C)
elasticity of the metal
D)
workability of the metal

Correct Answer :   fatigue of the metal

A)
body of equal
B)
body of equal section
C)
Both (A) and (B)
D)
body of equal strength

Correct Answer :   body of equal strength

A)
plastic point
B)
elastic point
C)
breaking point
D)
yielding point

Correct Answer :   yielding point

A)
Newton
B)
Watt
C)
Dyne
D)
None of the above

Correct Answer :   Newton


Explanation : Force = mass x acceleration = kg x m/s² = N.

A)
Micron
B)
Angstrom
C)
Milestone
D)
Light year

Correct Answer :   Milestone


Explanation : Milestone means achievement. it is not and unit of distance.

A)
X=1
B)
X=2
C)
X=3
D)
X=4

Correct Answer :   X=3


Explanation : The volumetric strain is the change in dimension in three directions and the linear strain depends on the change in only one direction so the volumetric strain is 1 times the linear strain in any of the three directions.

A)
0.01
B)
0.02
C)
0.002
D)
0.001

Correct Answer :   0.001


Explanation : The strain is given by = dL / L = 2/2000 = 0.001.

A)
yielding
B)
creeping
C)
breaking
D)
None of the above

Correct Answer :   creeping

A)
160 and 180
B)
120 and 160
C)
32 and 120
D)
20 and 32

Correct Answer :   32 and 120

A)
pd / 2t
B)
pd / 3t
C)
pd / 4t
D)
2pd / t

Correct Answer :   pd / 2t

A)
torsional loads
B)
transverse loads
C)
axial compressive loads
D)
axial tension loads

Correct Answer :   axial tension loads

A)
one
B)
two
C)
three
D)
four

Correct Answer :   one

A)
Thrust diagram
B)
Stress diagram
C)
Shear force diagram
D)
Bending moment diagram

Correct Answer :   Stress diagram


Explanation : The stress diagram shows the variation of the axial load for all sections of the pan. The bending moment diagram shows the variation of moment in a beam. The shear force diagram shows the variation in the shear force due to loading in the beam.

A)
Shear strain
B)
Bending stress
C)
Shear stress
D)
Compressive stress

Correct Answer :   Shear stress


Explanation : Shear stress makes the body to shear off across the section. It is tangential to the area over which it acts. The corresponding strain is the shear strain.

A)
Force/unit area
B)
Bending strain/area
C)
Shear resistance/shear area
D)
Shear stress/length

Correct Answer :   Shear resistance/shear area


Explanation : When force is applied, the twisting divides the body. The resistance is known as shear resistance and shear resistance per unit area is known as shear stress.

A)
a tie
B)
a column
C)
a strut
D)
a stanchion

Correct Answer :   a column

A)
ductility
B)
plasticity
C)
malleability
D)
elasticity

Correct Answer :   elasticity

A)
955.41 kg/cm²
B)
95.541 kg/cm²
C)
9.5541 kg/cm²
D)
9554.1 kg/cm²

Correct Answer :   955.41 kg/cm²

141 .
Which of the following stresses are associated with the tightening of a nut on a bolt?

P. Crushing and shear stress in threads
Q. Bending stress due to the bending of bolt
R. Torsional shear stress due to frictional resistance between the nut and the bolt

Select the correct answer using the codes given below :
A)
Only P
B)
Only R
C)
P and Q
D)
P and R

Correct Answer :   P and Q


Explaination : Bending stress comes when there is some kind of eccentric load. Torsional stress will come when the nut is rotating. Shear stress will come in tightening of a nut on bolt.

A)
parabola
B)
triangle
C)
rectangle
D)
cubic parabola

Correct Answer :   triangle

A)
one-half of the base
B)
one-fifth of the base
C)
one-third of the base
D)
one-fourth of the base

Correct Answer :   one-third of the base

A)
may be its centre
B)
does not change during deformation
C)
passes through the C.G. of the area of cross-section
D)
None of the above

Correct Answer :   does not change during deformation

A)
polar modulus
B)
moment of inertia
C)
modulus of rigidly
D)
polar moment of inertia

Correct Answer :   polar modulus

A)
least at the centre
B)
least at the supports
C)
maximum at the centre
D)
maximum at the supports

Correct Answer :   maximum at the supports

A)
equal to one
B)
equal to 3Ï€/16
C)
less than one
D)
more than one

Correct Answer :   equal to 3Ï€/16


Explanation : For circular plate, MI = π*d^4/64.

For square plate, MI = d^4/12.

So, Ratio = MI of circular plate/MI of square plate.

= 3*π/16.

A)
1
B)
2
C)
3
D)
4

Correct Answer :   2

A)
on top fibre along vertical plane
B)
on lower fibre along horizontal plane
C)
on middle fibre along horizontal plane
D)
equally on each fibre along horizontal plane

Correct Answer :   equally on each fibre along horizontal plane

A)
twice the number of joints minus one
B)
twice the number of joints minus two
C)
twice the number of joints minus three
D)
three times the number of joints minus three

Correct Answer :   twice the number of joints minus three

A)
top fibre
B)
bottom fibre
C)
neutral axis
D)
every cross-section

Correct Answer :   top fibre

A)
short spans
B)
large spans
C)
heavy weights
D)
light weights

Correct Answer :   large spans

A)
triangle
B)
rectangle
C)
parabola
D)
cubic parabola

Correct Answer :   rectangle

A)
vertical forces to zero
B)
horizontal forces to zero
C)
moment about any point to zero
D)
All of the above

Correct Answer :   All of the above

A)
500
B)
416
C)
360
D)
240

Correct Answer :   416

A)
average resistance x displacement
B)
1 / 2 stress x strain x area of its cross-section
C)
1 / 2 stress x strain x volume of the member
D)
1 / 2 (stress)² x volume of the member + Young's modulus E.

Correct Answer :   1 / 2 (stress)² x volume of the member + Young's modulus E.

A)
0.01
B)
0.05
C)
0.001
D)
0.005

Correct Answer :   0.001


Explanation : Strain = dL/L = 0.1/100 = 0.001.

A)
lap joint
B)
butt join
C)
single riveted single cover butt joint
D)
double riveted double cover butt joint

Correct Answer :   double riveted double cover butt joint

A)
triangle
B)
parabola
C)
rectangle
D)
cubic parabola

Correct Answer :   parabola

A)
circular beam is more economical
B)
square beam is more economical
C)
both the beams are equally strong
D)
both the beams are equally economical

Correct Answer :   square beam is more economical

A)
for triangular section is more than rectangular section
B)
for rectangular section is more than triangular section
C)
for triangular section is same as that of a rectangular section
D)
None of the above

Correct Answer :   for triangular section is same as that of a rectangular section

A)
determinate
B)
statically determinate
C)
Both (A) and (B)
D)
statically indeterminate

Correct Answer :   statically indeterminate

A)
triangle
B)
parabola
C)
cubic parabola
D)
rectangle

Correct Answer :   cubic parabola

A)
(σ₁² – σ₂² – 2σ₁σ₂ ) / 2E
B)
(σ₁² + σ₂² – 2σ₁σ₂ ) / 2E
C)
(σ₁² + σ₂² + 2σ₁σ₂ ) / 2E
D)
None of the above

Correct Answer :   (σ₁² + σ₂² – 2σ₁σ₂ ) / 2E


Explanation : Strain energy = (σ₁ε₁+ σ₁ε₁ ) / 2E

= (σ₁² + σâ‚‚² – 2σ₁σâ‚‚ ) / 2E.

A)
Be in equilibrium
B)
Reduce to a couple
C)
Reduce to a resultant force
D)
Not be in equilibrium

Correct Answer :   Not be in equilibrium


Explanation : The forces are not concurrent so the resultant force and couple both may be present. Thus the best choice is that forces are not in equilibrium.

A)
Product of stress and the strain
B)
Total strain multiplied by the volume of the member
C)
Product of strain and Young’s modulus of the material
D)
The maximum strain multiplied by the length of the member

Correct Answer :   Product of strain and Young’s modulus of the material


Explanation : Strain energy per unit volume for solid = q² / 4G.

A)
15.9 N-m
B)
14 N-m
C)
14 N-mm
D)
15.9 N-mm

Correct Answer :   15.9 N-m


Explanation : Stress = 50,000 / 625π = 25.46

Strain energy = σ²V/2E = 25.46×25.46×9817477 / (2×200000) = 15909.5 N-mm = 15.9 N-m.

A)
most distant
B)
least distant
C)
at either end
D)
centrally located.

Correct Answer :   most distant

A)
three-moment equation
B)
moment-area-theorem
C)
Maxwell's reciprocal theorem
D)
None of the above

Correct Answer :   moment-area-theorem

A)
free supports
B)
roller supports
C)
hinged supports
D)
All of the above

Correct Answer :   All of the above

A)
1/20
B)
1/15
C)
1/10
D)
1/25

Correct Answer :   1/10

A)
sum of the forces
B)
sum of the transverse forces
C)
displacement of the neutral axis
D)
algebraic sum of the transverse forces of the section

Correct Answer :   algebraic sum of the transverse forces of the section

A)
statically determinate
B)
geometrically unstable
C)
statically indeterminate
D)
structurally sound but indeterminate

Correct Answer :   statically determinate

A)
WL
B)
1/2 WL
C)
1/3 WL
D)
None of the above

Correct Answer :   1/2 WL

A)
middle half rule of columns
B)
middle third rule of columns
C)
middle fourth rule of columns
D)
None of the above

Correct Answer :   middle fourth rule of columns

A)
pass through the centroid of the section
B)
be an axis of symmetry of the section
C)
be equidistant from the top of bottom films
D)
None of the above

Correct Answer :   pass through the centroid of the section

A)
vertically upwards
B)
tangentially to the arch
C)
along the axis of the arch
D)
perpendicular to the axis of arch

Correct Answer :   perpendicular to the axis of arch

A)
The material of the beam is homogeneous and isotropic
B)
The resultant pull or thrust on transverse section of a beam is zero
C)
The value of the Young's modulus is the same in tension as well as in compression
D)
All of the above

Correct Answer :   All of the above


Explanation : * The material of the beam is homogeneous and isotropic
* The resultant pull or thrust on transverse section of a beam is zero
* The value of the Young's modulus is the same in tension as well as in compression
* Transverse section of a beam remains plane before and after bending

A)
Mr / ∑r²
B)
∑r² / Mr
C)
Mr² / ∑r²
D)
√Mr / ∑r²

Correct Answer :   Mr / ∑r²

A)
cubical
B)
parabolic
C)
linear
D)
circular

Correct Answer :   parabolic

A)
Uniform
B)
Variable with maximum at the top of the beam
C)
variable with maximum at the bottom of the beam
D)
Variable with maximum on the neutral axis

Correct Answer :   Variable with maximum on the neutral axis


Explanation : Maximum value of shear stress at neutral axis is τ = 3/2 τmean

So, transverse shear stress is variable with a maximum in the neutral axis.

A)
1Pa
B)
1MPa
C)
10MPa
D)
100Pa

Correct Answer :   1MPa


Explanation : Shear stress = 10kN / 100mmx100mm = 1 N/mm² = 1MPa.

A)
cubical
B)
linear
C)
circular
D)
parabolic

Correct Answer :   cubical

A)
top fibre
B)
bottom fibre
C)
every-horizontal plane
D)
middle fibre

Correct Answer :   every-horizontal plane

A)
tension per unit area
B)
tension in the member
C)
force divided by the length
D)
tension divided by the length

Correct Answer :   tension divided by the length

A)
2.275 mm
B)
0.2275 mm
C)
0.02275 mm
D)
2.02275 mm.

Correct Answer :   0.2275 mm

A)
triangle
B)
parabola
C)
rectangle
D)
cubic parabola

Correct Answer :   triangle

A)
is equal
B)
changes sign
C)
is minimum
D)
is maximum

Correct Answer :   changes sign

A)
25.22 cm
B)
20.00 cm
C)
14.14 cm
D)
17.32 cm

Correct Answer :   14.14 cm

A)
50 N at each end
B)
50 N at the centre
C)
100 N at the centre
D)
None of the above

Correct Answer :   100 N at the centre

A)
The twist along the shaft is uniform
B)
The shaft is of uniform circular section throughout
C)
Cross-section of the shaft, which is plane before twist remains plane after twist
D)
All radii get twisted due to torsion

Correct Answer :   All radii get twisted due to torsion

A)
statically determinate structure
B)
a bent beam
C)
statically indeterminate structure
D)
None of the above

Correct Answer :   statically determinate structure

A)
cubical
B)
linear
C)
circular
D)
parabolic

Correct Answer :   linear

A)
Degrees
B)
Minutes
C)
Radians
D)
Metric tonnes

Correct Answer :   Radians


Explanation : The slope is defined as at any point on the bent beam is the angle measured in terms of radians to which the tangent at that point makes with the x axis.

A)
Deflection curve
B)
Random curve
C)
Refraction curve
D)
Reflection curve

Correct Answer :   Deflection curve


Explanation : An elastic curve is defined as the line to which the longitudinal axis of a beam deviates under given load. It is also called a deflection curve.

A)
Macaulay's method
B)
Moment area method
C)
Double integration method
D)
Isoheytal method

Correct Answer :   Isoheytal method


Explanation : The method “Isoheytal” can be used for calculating run-off over an area. The remaining methods are effectively adopted to calculate the slope and deflection at a point in any type of beam.

A)
m
B)
kN
C)
kNm
D)
kN/m

Correct Answer :   m


Explanation : The term “deflection” is defined as the transverse displacement of a point on any straight axis to the curved axis. It is expressed in metres (m).

A)
Macaulay's method
B)
Lacey’s method
C)
Arithmetic increase method
D)
Mathematical curve setting

Correct Answer :   Macaulay's method


Explanation : Macaulay's method was devised by Mr WH Macaulay.

Advantages :

* Gives one continuous expression for bending moment
* Constants of integration can be found by using end conditions
* By using this method, slope and deflection at any section can be determined throughout the length of the beam.

A)
i
B)
y
C)
h
D)
e

Correct Answer :   y


Explanation : The deflection of a point on the axis of the deflected beam is defined as the angle developed in radians with tangent at the section makes with the original axis of the beam.

A)
1/4
B)
1/16
C)
15/16
D)
None of the above

Correct Answer :   15/16

A)
first row
B)
second row
C)
central raw
D)
one rivet hole of end row.

Correct Answer :   first row

A)
bending moment is maximum
B)
shearing force is maximum
C)
shearing force is minimum
D)
bending moment is zero or changes sign

Correct Answer :   bending moment is zero or changes sign

A)
Centroid
B)
Central point
C)
Inertial point
D)
Center of gravity

Correct Answer :   Center of gravity


Explanation : The centre of gravity of a body is the point through which the whole weight of the body acts. A body’s center of gravity is the point around which the resultant torque due to gravity forces vanishes. Where a gravity field can be considered to be uniform and the centre of gravity will be the same.

A)
Inertial point
B)
Centroid
C)
Central point
D)
Centre of gravity

Correct Answer :   Centroid


Explanation : The centroid is the point at which the total area of a plane figure is assumed to be concentrated. The centroid and centre of gravity are at the same point.

A)
At its end
B)
Depends upon its material
C)
At its middle point
D)
At its centre of its cross sectional area

Correct Answer :   At its middle point


Explanation : The centre of gravity of a uniform rod lies at its middle point. The whole weight of the rod acts through its middle point.

A)
from zero at the centre to a maximum at the circumference
B)
equally throughout the section
C)
from maximum at the centre to zero at the circumference
D)
from minimum at the centre of maximum at the circumference

Correct Answer :   from zero at the centre to a maximum at the circumference

A)
1.2
B)
1.4
C)
1.5
D)
1.8

Correct Answer :   1.2


Explanation : Bond stress is the shear stress acting parallel to the bar on the interface between the reinforcing bar and the surrounding concrete. Hence it is the stress developed between the contact surface of Steel and concrete to keep them together. The value of M20 designs Bond stress is 1.2 in tension.

A)
Bond stress
B)
Lateral stress
C)
Temperature stress
D)
Shear stress

Correct Answer :   Shear stress


Explanation : Bending is usually accompanied by shear. The combination of shear and bending stresses produces the principle stresses which causes diagonal tension in the beam section. This should be resisted by providing shear reinforcement in the form of vertical stirrups (or) bent up bars along with stirrups.

A)
0.68
B)
0.96
C)
1.76
D)
1.98

Correct Answer :   0.96


Explanation : The limiting percentage of steel for singly reinforced sections of M20 grade & Fe415 is 0.96.

A)
Top width
B)
Toe of the wall
C)
Base width
D)
Spillway length

Correct Answer :   Base width


Explanation : In dams, the economy prevails if the cross section of a dam is provided with minimum base width. Base width “b” can be determined from the equation: b2 +ab+ a2 = H2/ S.

A)
1658.15 kN/m²
B)
1775.12 kN/m²
C)
1897.45 kN/m²
D)
2336.67 kN/m²

Correct Answer :   1775.12 kN/m²


Explanation : The maximum stress at the base section = W/b (1+6e/b)

P= 4400/8 (1+6×2.97/8)

= 1775.12 kN/m²

A)
Tensile
B)
Bending
C)
Shearing
D)
Compressive

Correct Answer :   Compressive


Explanation : If the stress developed in the dam section at the base is positive there it indicates the nature of stress to be compressive.

A)
shear stress
B)
tensile stress
C)
transverse stress
D)
compressive stress

Correct Answer :   tensile stress

A)
directly proportional
B)
curvilinearly related
C)
inversely proportional
D)
None of the above

Correct Answer :   directly proportional

A)
square of length b/2
B)
rhombus of length h/2
C)
rhombus of diagonals b/3 and h/3
D)
rectangle of lengths b/2 and h/2

Correct Answer :   rhombus of diagonals b/3 and h/3

A)
d = √5 t
B)
d = √t + 1.5
C)
d = 6.05 √t
D)
d = 1.5 t + 4

Correct Answer :   d = 6.05 √t

A)
at every point of the bar
B)
at the lower cross-section
C)
at the central cross-section
D)
at the built-in upper cross-section

Correct Answer :   at the built-in upper cross-section

A)
torsional loads
B)
axial compressive loads
C)
transverse loads
D)
axial tension loads

Correct Answer :   axial compressive loads

A)
Thin cylinder
B)
Thick cylinder
C)
Hoop cylinder
D)
Circumferential cylinder

Correct Answer :   Thin cylinder


Explanation : The thickness of plate is negligible when compared to the diameter of the cylindrical shell, and then it can be termed as a thin cylinder. The radius stress in the cylinder walls is negligible.

A)
1/40
B)
1/30
C)
1/20
D)
1/15

Correct Answer :   1/20


Explanation : In thin shells, the stress distribution over the thickness of the material is assumed to be uniform and the wall thickness is equal to or less than 1/ 20 of the internal diameter.

A)
Thin cylinders
B)
Thick shells
C)
Hoop cylinders
D)
Longitudinal cylinders

Correct Answer :   Thin cylinders


Explanation : In thin cylindrical shells, the stresses are uniformly distributed throughout the wall. The type of stresses developed in thin cylinders is hoop stress and longitudinal stress. Ex: water supply mains, oil tanks, steam boilers and gas pipes.

A)
Resilience
B)
Proof resilience
C)
Impact resilience
D)
Modulus of resilience

Correct Answer :   Proof resilience


Explanation : Proof resilience is defined as the maximum that can be absorbed with in the proportionality limit without creating a permanent distortion.

A)
Equal to
B)
Less than
C)
As same as
D)
Greater than

Correct Answer :   Greater than


Explanation : The compressive strength of brittle materials is greater than its tensile strength. The tensile strength of ductile material is greater than its compressive strength.

A)
Equal to
B)
Less than
C)
As same as
D)
Greater than

Correct Answer :   Less than


Explanation : The stress developed in a material without any permanent stress is called elastic limit and the breaking stress is always less than the ultimate stress.

A)
Beam
B)
Post
C)
Column
D)
Strut

Correct Answer :   Column


Explanation : A vertical member subjected to direct compressive forces is called a column or pillar. The column transfers the load from the beams or slab to the footings and foundations.

A)
Strut
B)
Post
C)
Column
D)
Stanchion

Correct Answer :   Strut


Explanation : The inclined member carrying compressive load in case of frames and trusses is called as a strut. A strut is a member of a structure in any position carrying an axial load. Strut may be horizontal, inclined or even vertical.

A)
Post
B)
Strut
C)
Stanchion
D)
Pillar

Correct Answer :   Stanchion


Explanation : A built up rolled Steel section carrying compressive force is known as “stanchion”. A wood member carrying compressive force is called a “post”.

A)
Modulus
B)
Tenacity
C)
Stress energy
D)
Strain energy

Correct Answer :   Strain energy


Explanation : The capability of a material to absorb energy when it is deformed elastically and release that energy upon unloading is known resilience. This resilience is also termed as Strain energy.

A)
Power
B)
Work done
C)
Energy
D)
Young’s Modulus

Correct Answer :   Work done


Explanation : By the principle of work, the amount of strain energy in a body is found. When a load acts on a body there will be deformation, which causes movement of the applied load. This work is done by the applied load.

A)
Alignment method
B)
Voluminous method
C)
Centre line method
D)
Long wall and short wall method

Correct Answer :   Long wall and short wall method


Explanation : Long wall short wall method is tedious and long lasting. In this method, the length of wall running in one direction are measured first out to out and that of running in the perpendicular direction are measured in to in.

A)
Specifications
B)
Tenders
C)
Survey
D)
Estimate

Correct Answer :   Specifications


Explanation : Drawings cannot give every information about materials and quality. The specifications give the nature and class of work, quantity of materials and workmanship. They are very useful during the execution of work.

A)
Strut
B)
Caisson
C)
Frame
D)
Form work

Correct Answer :   Frame


Explanation : Frame is a structure made up of several members riveted and welded together. The members of the frame are made in such a way that the form angle iron or channel sections.

A)
Redundant frame
B)
Imperfect frame
C)
Perfect frame
D)
Deficient frame

Correct Answer :   Perfect frame


Explanation : A perfect frame is 1 for which the following equation is satisfied m = 2j-3.

A perfect frame is that which is composed of members just sufficient to keep it in equilibrium when loaded without any change.

A)
Axial load
B)
Bending moment
C)
Shear force
D)
Shear stress

Correct Answer :   Bending moment


Explanation : If conditions of equilibrium are sufficient to analyse the structure fully, then it is statically determinate structure. In this bending moment at a section is independent of the material of the components of the structure.

A)
120°
B)
90°
C)
60°
D)
45°

Correct Answer :   45°


Explanation : Splayed wing walls permit smooth entry and exit of water under the bridge. The splay is usually provided at 45°. The weep holes are also provided.

A)
Stresses
B)
Moment
C)
Strains
D)
Deflections

Correct Answer :   Stresses


Explanation : Statically indeterminate structures need some extra conditions for the further simplification. Normally stresses are produced due to variation in indeterminate beams.

A)
Gradient
B)
Camber
C)
Carriage way
D)
Super elevation

Correct Answer :   Gradient


Explanation : The gradient is defined as the longitudinal rise or fall off road surface love its length is expressed as ratio 1 vertical: n horizontal or as a percentage.

A)
600 mm
B)
350 mm
C)
200 mm
D)
100 mm

Correct Answer :   100 mm


Explanation : Sight distance is an important requirement for the safety of travel on highways the height of the object is taken to be at a depth of 100 mm above road.

A)
1 m
B)
0.5 m
C)
1.25 m
D)
1.4 m

Correct Answer :   0.5 m


Explanation : The minimum shoulder width provided for village roads is 0.5m.

A)
Summit
B)
Gradient
C)
Earth quantities
D)
Super elevation

Correct Answer :   Earth quantities


Explanation : The line of sight of a driver above the road is taken as 1.2m. The height of the object is taken to be height of 100 mm. Sight distance is an important resource requirement for the safety of travel. The designing layout plays a very vital role.

A)
Joint curves
B)
Summit curves
C)
Transition curves
D)
Adjoining curves

Correct Answer :   Transition curves


Explanation : The transition curves are necessary for a vehicle to have smooth entry of straight section into circular curve. They provide aesthetic experience of the road. They provide a graduate introduction of super elevation.

A)
0.0036 radians
B)
0.0072 radians
C)
0.0054 radians
D)
0.108 radians

Correct Answer :   0.0036 radians


Explanation : Maximum slope at supports be i = A/EI
= 180/50000
i = 0.0036 radians.

A)
Zero
B)
Minimum
C)
Maximum
D)
Uniform

Correct Answer :   Zero


Explanation : The slope in cantilever beam is zero at the fixed end of the cantilever and the slope is maximum at it’s free end. The slope is determined in the moment area method through Mohr’s theorems.

A)
Supports
B)
Mid span
C)
Through out
D)
At point of loading

Correct Answer :   Mid span


Explanation : In case simply supported beams, the slope is maximum at the end supports of the beam and relatively zero at midspan of a symmetrically loaded beam.

A)
0.066 radians
B)
0.0455 radians
C)
0.0367 radians
D)
0.0225 radians

Correct Answer :   0.0225 radians


Explanation : The maximum slope at free support (in cantilever beam) = i = A/EI
= 90/4000
= 0.0225 radians.

A)
Link canal
B)
Inundation canal
C)
Protective canal
D)
Productive canal

Correct Answer :   Protective canal


Explanation : The construction of protective canals and their development may be started during summer in hence they provide employment to the farmers at the time of drought and famine. Protective canals are not remunerative as productive canals.

A)
Bauxite
B)
Fly ash
C)
Dolomite
D)
Magnesia

Correct Answer :   Dolomite


Explanation : Dolomite bricks are made especially from dolomite it contains nearly 30% lime and 22% of magnesium these bricks are inferior to magnesite bricks. They are generally used in the lining of blast furnaces.

A)
bauxite bricks
B)
fire bricks
C)
silica bricks
D)
magnesia bricks

Correct Answer :   bauxite bricks


Explanation : Bauxite bricks contain nearly 75% of aluminium and it is mixed with fire clay 15 to 30% and added some water to mould. High alumina bricks are resistant to corrosion.

A)
49mm
B)
45mm
C)
35mm
D)
28mm

Correct Answer :   45mm


Explanation : The deflection at any point on the elastic curve equal to Ax/EI

But, we know that A/EI is already slope equation.

So, slope × (the distance of centre of gravity of bending moment to free end = 2m).

0.0225 × 2

0.045m ~ 45 mm.

A)
Aqueduct
B)
Super passage
C)
Level crossing
D)
Head regulator

Correct Answer :   Head regulator


Explanation : The head regulator is one of the canal regulation works. It can control the entry of silt into the canal. It can be used as a metre for measuring the discharge. It can shut out river floods.

A)
Outlet
B)
Weir type escape
C)
Surplus escape
D)
Cross regulator

Correct Answer :   Weir type escape


Explanation : The crest of the weir is fixed at canal FSL. When the water level rises above FSL, it is disposed of into the natural drain. Hence, the tale escape is also known as weir type escape.

A)
By mulches
B)
Crop rotation
C)
Recharge to ground water
D)
Spreading manure

Correct Answer :   Recharge to ground water


Explanation : The methods which are adopted for preserving the water in the soil from being lost are called as soil moisture conservation methods. The major part of the water is lost through evapotranspiration. The recharge to groundwater is one of the techniques in rainwater harvesting.

A)
125 years
B)
130 years
C)
140 years
D)
145 years

Correct Answer :   125 years


Explanation : Warabandi is a rotational method for allocation of the available water equally in an irrigation system. It provides continuous rotation of water generally lasts 7 days. It has been effectively practiced in India for more than 125 years.

A)
Plasticity
B)
Creep
C)
Ductility
D)
Malleability

Correct Answer :   Plasticity


Explanation : Plasticity in the property of Material by which the material can undergo permanent deformation and fails to regain its original shape on removal of load. Examples are gold, lead, etc.

A)
Basic
B)
Chrome
C)
Frosterite
D)
Spinel

Correct Answer :   Spinel


Explanation : The spinal bricks belong to neutral bricks. The spinel bricks mainly consist of alumina and magnesia. These bricks are widely used in the lining of electric furnace.

A)
212mm
B)
318mm
C)
435mm
D)
556mm

Correct Answer :   212mm


Explanation : The limiting depth of neutral axis Fe 250 steel is
Xu (max) = 0.53 × d ( for Fe250)
= 0.53 × 400
= 212mm.

A)
Lugs
B)
Anglets
C)
Bends
D)
Fillets

Correct Answer :   Bends


Explanation : In situations, where straight anchorage length cannot be provided due to lack of space. To improve the anchorage of bars, standard bends are provided in deformed bars.

A)
Continuous slab
B)
Cantilever slab
C)
One way slab
D)
Two way slab

Correct Answer :   One way slab


Explanation : If the ratio of the longest span the shorter span is greater than 2 or A slab supporting only in two edges (opposite to each other) is called one way slab. This slab spans across shorter span practically.

A)
4m
B)
3m
C)
2m
D)
1m

Correct Answer :   1m


Explanation : The stair consists of series of steps with landings at appropriate intervals. The width of stair depends upon the type of building in which it is provided. Generally, in residential buildings, the width of stair is 1 m.

A)
1.5 m
B)
2.5 m
C)
3.5 m
D)
4.5 m

Correct Answer :   2.5 m


Explanation : e = Z – b/2. [The value of Z = 5.5m] = 5.5 – 6/2
= 5.5 – 3
= 2.5 m.

A)
Character of material
B)
Toe width
C)
Height of foundation
D)
Free board allowance

Correct Answer :   Character of material


Explanation : The upstream and downstream slopes of the Dam should be stable in all situations the side slopes depend upon

1.Height of the dam
2.Character of material
3.Nature of foundation.

277 .
n and j are numbers of members and joints in a frame. It contains redundant members if
A)
n = 2j - 3
B)
n < 2j - 3
C)
n > 2j - 3
D)
n = 3j - 2

Correct Answer :   n > 2j - 3

A)
midpoint of the crown and left support hinge
B)
midpoint of the crown and right support hinge
C)
crown of the arch
D)
None of the above

Correct Answer :   crown of the arch

A)
Algebraic sum of the moments of all the forces on either side of the section
B)
Arithmetic sum of the forces on either side of the section
C)
Arithmetic sum of the moments of all the forces on either side of the section
D)
None of the above

Correct Answer :   Algebraic sum of the moments of all the forces on either side of the section

A)
ductility
B)
plasticity
C)
elasticity
D)
malleability

Correct Answer :   malleability

A)
elastic structures
B)
plastic structures
C)
symmetrical structures
D)
All of the above

Correct Answer :   elastic structures

282 .
A simply supported beam (l + 2a) with equal overhangs (a) carries a uniformly distributed load over the whole length, the B.M. changes sign if
A)
l = 2a
B)
l = 4a
C)
l > 2a
D)
l < 2a

Correct Answer :   l > 2a

A)
double V-butt joint
B)
double U-butt joint
C)
single V-butt joint
D)
single inverted V-butt joint

Correct Answer :   single inverted V-butt joint

A)
Bottom width
B)
Top width
C)
Radius
D)
Diameter

Correct Answer :   Top width


Explanation : Hydraulic depth is the ratio of wetted area to the top with (T). It is denoted by D
D = A/T.

A)
Check gates
B)
Scour gates
C)
Lock gates
D)
Sluice gates

Correct Answer :   Lock gates


Explanation : Gates which are used to change the water level in a canal or a river are known as lock gates. If a canal or a river has a vertical fall at any section, it is necessary to raise or lower the water level in order to transfer the boat from upper water level to lower one.

A)
Sluice gates
B)
Lock gates
C)
Drain gates
D)
Check gates

Correct Answer :   Sluice gates


Explanation : In hydraulic structures, the openings are provided to carry water from its storage place to place of utilisation. The flow of water through such openings is controlled by means of sluice gates.

A)
equal
B)
uniform
C)
directly proportional
D)
inversely proportional

Correct Answer :   inversely proportional


Explanation : The ductility of material increases with the increase in percentage reduction in area of a specimen under tensile stress.

A)
Osmoscope
B)
Sonoscope
C)
Thermometer
D)
Jackson turbidometer

Correct Answer :   Osmoscope


Explanation : The main causes of odour in water are algae, sewage and dissolved gases. Taste and odour can also be expressed in terms of odour density. Odour can be estimated by osmoscope.

A)
Ppm
B)
pH value
C)
Silica scale
D)
Platinum cobalt scale

Correct Answer :   Platinum cobalt scale


Explanation : Colour is caused by the presence of colloidal substance is aquatic growth etc. in water should be distinguished from turbidity which is termed as apparent colour. The colour is expressed in Platinum Cobalt scale. Colour may be removed by coagulation and adsorption method.

A)
Re chlorination
B)
De chlorination
C)
Pre chlorination
D)
Post chlorination

Correct Answer :   De chlorination


Explanation : De chlorination means removing the chlorine from the water this is generally required when super chlorination has been practiced.

A)
20 %
B)
15 %
C)
10 %
D)
5 %

Correct Answer :   5 %


Explanation : According to the board of Indian Standards [BIS], the sand which is used for filtration process should not lose weight more than 5% when placed in hydrochloric acid for one day (24 hours).

A)
1 to 2 hours
B)
1 to 3 days
C)
1 to 3 weeks
D)
1 to 3 months

Correct Answer :   1 to 3 months


Explanation : For the purpose of cleaning the top layer of sand is removed to a depth of 15 mm to 25 mm. The water is admitted to the filter the cleaning interval varies from 1 to 3 months.

A)
20 mm
B)
30 mm
C)
40 mm
D)
50 mm

Correct Answer :   40 mm


Explanation : Generally foundation concrete is laid about thickness of 30 cm with proportion 1:4:8 (or) 1:5:10 and are measured in m³.

Before laying the concrete bed level, sand filling and sinking must be done and checked properly.

A)
Seal coat
B)
Tack coat
C)
Open coat
D)
Prime coat

Correct Answer :   Seal coat


Explanation : Seal code is final coat lay over bituminous pavements which are not impervious. Seal coat develops skid resistant texture and they provide better riding surface.

A)
Lugs
B)
Rail joint
C)
Plates
D)
Spikes

Correct Answer :   Rail joint


Explanation : The joint which is made between two rails together with two fish plates and four fish bolts to form an expansion gap of 1.5 to 3 mm. Rail joint is the weakest part in the railway track.

A)
Dog spike
B)
Screw spike
C)
Polar spike
D)
Round spike

Correct Answer :   Screw spike


Explanation : Holding capacity of rails to sleepers is more and costly. Hence screw spike is used in driving and extraction. Though it is costly and time consuming, the sabotage problem is eliminated due to screw spike.

A)
1 in 10
B)
1 in 15
C)
1 in 20
D)
1 in 30

Correct Answer :   1 in 20


Explanation : The wheels of rolling stock are made in the shape of a frustum of a cone having a slope of 1 in 20 is known as coning of wheels. The objective of coning of wheels is to prevent lateral movement of trains in straight track.

A)
Clips
B)
Lugs
C)
Spikes
D)
Sleepers

Correct Answer :   Sleepers


Explanation : Sleepers are transverse ties on which the rails are laid and transfer the load from rails to ballast. The main function of a sleeper is to provide a firm and even support to rails.

A)
Wave height
B)
Base drop
C)
Freeboard
D)
Toe width

Correct Answer :   Wave height


Explanation : The minimum height of the free board for wave action is generally taken to be equal to 1.5 hw. Where hw = height of wave action.

It can be calculated using 0.032(VF)½.

A)
Mulching
B)
Breaching
C)
Balanced
D)
Over reinforced

Correct Answer :   Breaching


Explanation : Sometimes during construction, the surplus works are avoided in many tanks. In such circumstances, breaching sections are provided in the dams to allow the surplus flood discharge. With this the scouring of section can be avoided.

A)
Turbidity rod
B)
Hellipe turbidometer
C)
Baylis turbidometer
D)
Jackson’s turbidometer

Correct Answer :   Baylis turbidometer


Explanation : The turbidity of potable water should be within 10 PPM or with in 10 units on the silica scale. High turbidity of water can be determined by Jackson turbidity metre and low turbidity of water can be determined by baylis turbidity metre.

A)
500 ppm
B)
600 ppm
C)
850 ppm
D)
1000 ppm

Correct Answer :   500 ppm


Explanation : Analytically, the total solids content of water is defined as all the matter that remains as residue upon evaporation. The standards for drinking water is acceptable limit is 500 ppm.

A)
G. Coli
B)
F. Coli
C)
R. Coli
D)
B. Coli

Correct Answer :   B. Coli


Explanation : The pathogenic bacteria are generally inherent in the qualifying group of Bacteria of which the bacillus coli (B. Coli) now called as Escherichia coli (E.Coli ) is prominent.

A)
180 ng/L
B)
150 mg/L
C)
230 mg/L
D)
340 mg/L

Correct Answer :   150 mg/L


Explanation : Sulphates ion is one of the major ions occurring in natural waters. In drinking water, sulphate causes a laxative effect and leads to scale formation in boilers. The desirable limit in drinking water is 150 mg /L.

A)
Zero
B)
1 to 5 ppm
C)
2 to 3 ppm
D)
2 to 4 ppm

Correct Answer :   2 to 3 ppm


Explanation : Ozone easily breaks down with oxygen and releases nascent oxygen which is powerful in killing bacteria. It also reduces organic matter present in the water the dosage of ozone is about 2 to 3 ppm.

A)
85 %
B)
90 %
C)
95 %
D)
99 %

Correct Answer :   99 %


Explanation : The slow sand filters remove suspended and bacterial impurities to an extent of 98 to 99%. It requires a large area and unsuitable for treating high turbid water.

A)
0.25 to 5 cumecs
B)
2 to 4 cumecs
C)
1.5 to 5 cumecs
D)
1.2 to 5 cumecs

Correct Answer :   0.25 to 5 cumecs


Explanation : The major distributary takes off from a branch canal to distribute the water to various parts of the field. The supply of the water varies from 0.25 to 5 cumecs.

A)
2.5:1
B)
1:2
C)
3:1
D)
1.5:1

Correct Answer :   2.5:1


Explanation : According to Terazghi, the following upstream slopes should be recommended.

1. Homogeneous well graded – 2.5 : 1
2. Homogeneous coarse silt – 3 : 1
3. Sand and gravel with RCC core wall – 2.5 : 1.

A)
Inlets
B)
Outlets
C)
Channels
D)
Distributaries

Correct Answer :   Outlets


Explanation : An outlet is a simple and small irrigation structure which is constructed along the distributaries. The amount of water that is withdrawn through the outlet is in proportion to the area that is irrigated below respective point.