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Aerodynamics - Boundary Layers, Laminar & Turbulent Boundary Layers, Navier Stokes Solutions Quiz(MCQ)
A)
No – slip condition at the surface
B)
Flow velocity increases along y – direction
C)
Thermal boundary layer is equal to velocity boundary layer
D)
Temperature of fluid at the surface is equal to wall temperature

Correct Answer :   Thermal boundary layer is equal to velocity boundary layer


Explanation : When there’s a viscous flow over a flat plate, there’s a boundary layer formation which has certain properties. On the surface, there’s a no slip condition. Apart from this the temperature of the fluid which is immediately at the surface has the same temperature as the surface which is known as the wall temperature. The velocity profile inside a boundary layer increases along the y – direction until it becomes equal to the freestream velocity. The only property that is incorrect is that the thermal boundary layer is equal to the velocity boundary layer.

The boundary of thermal layer is defined as the layer where the outer edge temperature becomes equal to the freestream temperature. Similarly, at the velocity boundary layer, the outer edge velocity is equal to the freestream velocity.

2 .
How is the boundary layer thickness defined? (ue is the outer edge velocity)
A)
u = 0.99ue
B)
u = 0.89ue
C)
u = 0.90ue
D)
u = 0.50ue

Correct Answer :   u = 0.99ue


Explaination : Inside the boundary layer, the velocity increases along the y – direction until it becomes equal to the freestream velocity. The thickness of boundary layer δ is defined as the point from the surface where the velocity is 0.99 times the free stream velocity.

3 .
What is the thermal boundary layer?
A)
T = 0.90Te
B)
T = 0.99Te
C)
T = 0.89Te
D)
T = 0.97Te

Correct Answer :   T = 0.99Te


Explaination : The flow temperature just like velocity varies within the boundary layer. It is a function of y – direction. The temperature ranges from Tw which is the temperature at the wall (y = 0) to T = 0.99Te at y = δt, where δt is the thermal boundary layer thickness. This variation of temperature is known as temperature profile.

4 .
In which case are the velocity and thermal boundary layer equal?
A)
Pr = 0
B)
Pr = 1
C)
Pr > 1
D)
Pr < 1

Correct Answer :   Pr = 1


Explaination : In most of the cases the two thermal and velocity boundary layers are not same except in one exceptional case when the Prandtl number = 1, in which case δt = δ. When Prandtl number is greater than 1, δt < δ and when Prandtl number is less than 1, δt > δ. In real life scenario, the Prandtl number is equal to 0.71 thus the thermal boundary layer thickness is greater than the velocity boundary layer thickness.

5 .
Which of these relations is applicable for turbulent and laminar boundary layer?
A)
δturbulent < δlaminar
B)
δTturbulent = δTlaminar
C)
δturbulent > δlaminar
D)
δTturbulent < δTlaminar

Correct Answer :   δturbulent > δlaminar


Explaination : In case of turbulent flow, there is a high energy and momentum exchange compared to the laminar flow due to the presence of eddies. This leads to the thermal and velocity boundary layer thickness of the turbulent flow to be higher than that of the laminar flow. Thus, δturbulent > δlaminar and δTturbulent > δTlaminar.

A)
Viscosity
B)
Wave drag
C)
Pressure drag
D)
Aerodynamics drag

Correct Answer :   Viscosity


Explanation : There is shear stress between the adjacent layers of fluid in both laminar and turbulent flow inside the boundary layer. This is due to the viscosity and it is given by the relation:

A)
Remains same
B)
Approaches zero
C)
Approaches once
D)
Approaches infinity

Correct Answer :   Approaches zero


Explanation : As the Reynolds number increases, the boundary layer thickness decreases when compared to the length of the body. Usually for very large aircrafts, the value of δ/L is around 0.01 which is a very small value. So hypothetically, as Re ? ∞, δ ? 0.

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   True


Explanation : When a flat plate is kept in the freestream flow, there’s a formation of a laminar boundary layer at the leading edge. This boundary layer thickness grows to a point where a transition point is reached. Beyond that point, there’s turbulence due to the presence of eddies and there’s turbulent boundary layer formation whose thickness keeps on increasing.

9 .
According to the y – momentum equation, how does the pressure vary inside the boundary layer normal in the direction normal to the surface?
A)
Increases
B)
Decreases
C)
Remains constant
D)
First increases then decreases

Correct Answer :   Remains constant


Explaination : The y – momentum equation for a boundary layer is given by :

According to the formula, at any x point in the boundary layer, pressure remains constant in the direction normal to the surface.

A)
True
B)
False
C)
Can Not Say
D)
None of the above

Correct Answer :   True


Explanation : Turbulent boundary layer consists of inner and outer layers. There is a viscous – dependent part of the profile very close to the surface and different length scaling parameters are needed for the remaining Reynolds – stress – dependent part of the profile.

A)
WALE model
B)
DNS model
C)
RNG – LES model
D)
DES model

Correct Answer :   DES model


Explanation : DES model is a hybrid of LES and RANS model and makes use of advantages of both. For treating near – wall regions, DES works like the RANS model and for rest of the region, it works as the LES model.

A)
RANS model
B)
RNG – LES model
C)
K – omega model
D)
K – epsilon model

Correct Answer :   K – omega model


Explanation : K – omega is one of the popular turbulence model. It is a two-equation model which solves two transport equations – turbulent kinetic energy and specific dissipation. Turbulent kinetic energy determines the energy whereas the specific dissipation determines the turbulence scale.

A)
K – Epsilon model
B)
Baldwin – Lomax model
C)
Spalart – Allmaras model
D)
Prandtl’s equation model

Correct Answer :   K – Epsilon model


Explanation : K – epsilon model is a two – equation model which includes two transport equations representing the turbulent flow properties. The first transport equation is solved is the turbulent kinetic energy, and the second one is the turbulent dissipation rate.

A)
DNS
B)
LES
C)
FANS
D)
RANS

Correct Answer :   LES


Explanation : In Large Eddy simulation, large eddies are computed by resolving large time and length scales. In LES, the smaller length scales are ignored making it an economical and less time consuming than DNS.

A)
Time consuming
B)
Low scale resolution
C)
Possible for high Reynolds number
D)
Possible for low Reynolds number

Correct Answer :   Possible for low Reynolds number


Explanation : The DNS solves the time – dependent Navier’s Stokes equation by resolving eddies of all scales for a sufficient time before reaching statistical equilibrium. The only shortcoming is that DNS is only applicable for low Reynolds number flow which has simple geometry.

A)
Model hypersonic flows
B)
Define reynolds stress for closure problems
C)
Closure of continuity equation
D)
Lack of system to accurately find turbulent flow characteristic

Correct Answer :   Define reynolds stress for closure problems


Explanation : While solving Navier’s Stokes equation for turbulent flow which governs the velocity, pressure of the fluid, the quantity is decomposed into mean and fluctuating components. While solving these using RANS equation, we get a reynolds stress term that needs to be closed in order to solve it. Hence we make use of turbulence modeling which defines these reynolds stresses in terms of the known averaged quantities.