Correct Answer : β = μ, 90°
Explaination : When the deflection is zero, the θ-β-M equation reduces to (M1sin?β)2? = 1. Two solutions obtained for shock angles from the above relation are, β = -90°, 90°. When the shock angle is 90°, a normal shock is observed. But -90° is not possible and hence it takes some limiting value, μ.