Correct Answer : Peak Inverse Voltage
Explanation : PIV stands for Peak Inverse Voltage. It is the maximum reverse bias voltage which a diode can bear without breakdown.
Correct Answer : Maximum reverse bias potential which can be applied across a diode without breakdown
Explanation : PIV rating indicates the maximum allowable reverse bias voltage which can be safely applied to a diode. If a reverse potential is greater than PIV rating then the diode will enter reverse breakdown region.
Correct Answer : Hartley
Explanation : Only LC oscillators are suitable for MHz range.
Correct Answer : capacitor between source and load
Correct Answer : Voltage controlled current source
Correct Answer : 25%
Correct Answer : The p+n junction
Correct Answer : It is applicable in all bias states
Explanation : Diode equation is I=IO(eqV/kT – 1). It is applicable in all bias condition that is forward, reverse and unbiased states.
Correct Answer : 26mV
Explanation : Voltage equivalent of temperature VT is equal to the product of Boltzman constant (J.K-1) and temperature in Kelvin. At a temperature of 27°C, it’s value is VT=KT/q=26mV.
Correct Answer : Cut-in voltage decreases
Explanation : As temperature increases the conductivity of a semiconductor increases. The diode conducts smaller voltage at larger temperature. Therefore, cut-in voltage decreases.
Correct Answer : Increases
Explanation : As temperature increases the conductivity of a semiconductor increases. Reverse saturation current increases as temperature increases.
Correct Answer : 1 mA
Explaination :
IC = 10 x 100 μA = 1 mA.
Correct Answer : about 2.38 Hz
Explaination : New lower cutoff frequency 50 / 1+200x0.1
Correct Answer : more than 180° but less than 270°
Explaination : It is 180° for purely resistive load and between 180° and 270° for R-L load.
Correct Answer : 2 v
Correct Answer : Channel length modulation
Correct Answer : CE-CB
Correct Answer : fT = 1.47 x 1010 Hz & fβ = 1.64 x 108 Hz
Correct Answer : Reduces gain
Correct Answer : 5.5x 10-7 A
Explaination : I=I0×(e(V/ηVT) – 1) where I0 = reverse saturation currentη = ideality factorVT = thermal voltageV = applied voltageHere, I = 0.1mA, η = 1.5, V = 0.2V, VT = TK/11600Therefore, VT at T = 25+273=298 is 298/11600 = 0.0256V.Therefore, reverse saturation currentIO=0.00055mA = 5.5×10-7A.
Correct Answer : 0.618V
Explaination : I=I0×(e(V/ηVT)-1) where I0 = reverse saturation currentη = ideality factorVT = thermal voltageV = applied voltageVT at T = 25+273=298 is 298/11600 = 0.0256V, η = 1.5, I = 1mA, I0 = 10-10A
Correct Answer : 0.0718V
Explaination : η = 1.2, I2 = 10mA, I1 = 1mA and take VT = 0.026V
Correct Answer : Operating point of device
Explanation : Quiescent point of a device represents operating point of a device. For a diode quiescent point is determined by constant DC current through the diode. The Q-point is the DC voltage or current at a specified terminal of an active device with no input applied. A bias circuit is used to supply this steady voltage/current.
Correct Answer : AC resistance
Explanation : Reciprocal of slope of I-V graph at q-point gives AC or dynamic resistance. The inverse of slope will be change in voltage by change in current which is known as dynamic resistance.
Correct Answer : Decrease
Explanation : Slope of I-V graph at q-point is reciprocal of dynamic or AC resistance. Therefore, as slope increases resistance decreases.
Correct Answer : Calculated from V-I graph
Explanation : Average AC resistance and dynamic or AC resistance are not exactly the same. They both measure the resistance in different ways. AC resistance is slope of the tangent of the curve of characteristic graph at Q-point. But average AC resistance is measured by measuring the slope of straight line between the limits of operation.
Correct Answer : Decreases exponentially
Explanation : After cut-in voltage current exponentially increases with small increase in voltage. This will considerably reduce resistance.
Correct Answer : Q-point
Explanation : Static or DC resistance of a diode is the resistance offered by a diode at its q-point. DC resistance represents steady state. That is, it is calculated by treating current and voltage as constants.
Correct Answer : 0.7V
Explanation : Static or DC resistance is the resistance of a diode at its operating point.Resistance = voltage/currentTherefore, voltage = current x resistance = 10mA x 70 = 0.7V
Correct Answer : replace all calculated voltages and currents by reverse values
Explanation : All voltages and currents have reverse polarity.
Correct Answer : surge resistor
Correct Answer : 0.6
Correct Answer : ac signal is zero
Explaination : Quiescent-operation means operation when ac signal is not applied.
Correct Answer : 2 V and 4 k ohm
Correct Answer : 4.878
Explanation : Closed loop gain = 200 / 1+0.2x200
Correct Answer : at least three RC combinations
Explanation : One RC combination can give a phase shift of less them 90°. Therefore 3 RC combinations are required for 180° phase shift.
Correct Answer : low power consumption
Explanation : Low power consumption is a big advantage in digital circuits.
Correct Answer : when the phase difference between the inputs is 180°
Explanation : For non-inverting terminal input, output is in phase with input. For inverting terminal input, output is 180° out of phase with input. If inputs have 180° phase difference, outputs will be in phase and additive.
Correct Answer : 14.14 V
Explanation :
PIV is √2 x 10 = 14.14 V.
Correct Answer : 990 mA
IEQ = ICQ + IBQ = 910 μA + 90 μA => 990 μA.
Correct Answer : 20000
Correct Answer : does not affect dc biasing
Correct Answer : A unity gain inverting amplifier
Correct Answer : 0.5
Correct Answer : negative voltage feedback
Correct Answer : Transistor capacitances
Correct Answer : Perfect conductor
Explanation : In ideal diode model the diode is considered as a perfect conductor in forward bias and perfect insulator in reverse bias. That is voltage drop at forward bias is zero and current through the diode at reverse bias is zero.
Correct Answer : 79.5 mV
Correct Answer : 100 Hz each
Explaination : Output wave in each case has two cycles for one cycle of input wave.
Correct Answer : distorted
Explanation : A high signal causes distortion because v-i characteristics of BJT is non-linear.
Correct Answer : gm
Explaination : Gain is proportional to gm .
Correct Answer : 80°C
Correct Answer : Increase in input impedance & decreases in output impedance
Correct Answer : Voltage controlled capacitor
Correct Answer : 100 kHz
B.W. = fH' - fL' .
Correct Answer : 1%
Explanation : A good power supply does not allow output voltage to vary by more than 1% .
Correct Answer : voltage divider bias
Explanation : Voltage divider bias stabilizes Ic.
Correct Answer : 200
Correct Answer : 4%
Correct Answer : 6.3 mA
Correct Answer : input impedance of second stage
Explanation : Since the first amplifier is feeding the second stage, the input impedance of second stage is the ac collector resistance of first stage.
Correct Answer : 4.5 mA
Explanation : AC saturation current is cutoff voltage x slope of ac load line.
Correct Answer : decreases
Explanation : Since the output is taken across collector resistance, short-circuiting collector resistance will decrease output voltage.
Correct Answer : 5 mA
Explanation : Since both diodes contribute equal load current, each diode current is 5 mA.
Correct Answer : with positive feedback
Explanation : Positive feedback is necessary for sustained oscillations.
Correct Answer : drift
Explanation : The drift is amplified by different stages.
Correct Answer : 7.1 W
Power rating = 8 - (55 - 25)(30 x 10-3) = 7.1 W.
Correct Answer : zero internal resistance
Explanation : An ideal power supply should have zero voltage drop.
Correct Answer : 0.13 V
Correct Answer : become one-third
Explanation : The emitter current becomes one-third since collector current in BJT is almost the same as emitter current, collector current also becomes one-third.
Correct Answer : voltage regulation in quadrupler circuit will be poorer than in tripler circuit
Explanation : Since voltage quadrupler circuit uses more components, voltage drop will be more and voltage regulation poorer.
Correct Answer : class AB
Explanation : In class A operation IC exists for 360°. In class B operation IC exists for 180°. In between there is the class AB.
Correct Answer : 40 kΩ and 8 kΩ respectively
Correct Answer : 4
Explaination : Feed back factor (βA) = 4.
Correct Answer : load resistance is large
Explaination : If load resistance is large, current would be low and voltage drop would be low.
Correct Answer : to block dc collector voltage
Explanation : Capacitor acts for ac or dc.
Correct Answer : Affects the common mode gain Ac
Correct Answer : Q-factor of the tuned output circuit
Correct Answer : Capacitor
Correct Answer : Both Temperature & β
Correct Answer : Dc
Explanation : XL is zero for dc.
Correct Answer : saturation point
Explanation : Current is maximum at saturation point.
Correct Answer : 198 V
Correct Answer : Temperature
Correct Answer : Large collector-base reverse bias
Correct Answer : High CMRR
Correct Answer : 25.5 V
Correct Answer : decrease in emitter current
Explanation : Emitter voltage is the same. Increase of emitter resistance decreases with emitter current.
Correct Answer : 1.2 mA
IE = IC + IB .
Correct Answer : more than 1
Explanation : The initial loop gain must be more than 1.
Correct Answer : Cut off point
Correct Answer : CMRR
Correct Answer : reduce base emitter voltage
Correct Answer : diode bias
Correct Answer : active region
Correct Answer : 1 : 10
Correct Answer : -15 V
Correct Answer : 16.7%
Correct Answer : 0 Hz to 100 kHz
Correct Answer : 16 W
Correct Answer : zero dB
Correct Answer : above 30 MHz
Correct Answer : mobility of electrons is greater than that of holes
Correct Answer : audio frequencies only
Correct Answer : Greater than +100
Correct Answer : 98dB
Correct Answer : 25 Ω & 20 %
Correct Answer : The amplitude of output is proportional to rate of change of input
Correct Answer : Differentiating amplifier
Correct Answer : 78.5%
Correct Answer : 120, 1 and 120 respectively
Correct Answer : Reduce all dc sources to zero and short all capacitors
Correct Answer : Doubles for every 10°C rise in temperature
Correct Answer : 99
Correct Answer : inductor L
Correct Answer : two quasi-stable states
Correct Answer : N-P-N, silicon, in a plastic package
Correct Answer : lower off-set voltage
Correct Answer : negligibly smaller value
Correct Answer : 10000 μμ
Correct Answer : Overcome a crossover distortion
Correct Answer : Common emitter
Correct Answer : Medium input resistance and high output resistance
Correct Answer : Class AB operation cannot be used for a push pull audio power output phase
Correct Answer : A sine wave of constant amplitude at the frequency of the original sine wave
Correct Answer : CC
Correct Answer : thermionic valve
Correct Answer : Base
Correct Answer : avoid any stray voltage at the gate that may destroy SiO2 layer
Correct Answer : negative
Correct Answer : 44.5
Correct Answer : 2.98 kHz
Correct Answer : The FET is unipolar, while junction transistor are bipolar
Correct Answer : Wave traps in each stage
Correct Answer : Drain voltage
Correct Answer : ac collector voltage is 180° out of phase with ac base voltage
Correct Answer : Mechanical ruggedness
Correct Answer : All capacitors
Correct Answer : The mobility decreases
Correct Answer : audio frequencies
Correct Answer : 2 kΩ
Correct Answer : 3 diodes and 3 capacitors
Correct Answer : square wave
Correct Answer : dual gate MOSFET
Correct Answer : 50.5 Ω
Correct Answer : the flow across the base region is mainly because of holes
Correct Answer : onset of non-linearity
Correct Answer : It has fast switching time
Correct Answer : 0.99
Correct Answer : SCR
Correct Answer : It is not particularly suited to A.C. or mains power control
Correct Answer : 50 Hz and 100 Hz
Correct Answer : 0.7 V and 0.3 V
Correct Answer : Transit time noise
Correct Answer : 100 Hz
Correct Answer : increase
Correct Answer : C
Correct Answer : Logarithmic amplifier
Correct Answer : close to unity
Correct Answer : square law device
Correct Answer : E MOSFETs
Correct Answer : emitter resistance
Correct Answer : Weinbridge oscillator
Correct Answer : will decrease
Correct Answer : 66.6
Correct Answer : current is low
Correct Answer : 0.985 mA
Correct Answer : infinite, zero
Correct Answer : higher gain
Correct Answer : natural convection
Correct Answer : almost sine wave
Correct Answer : Schmitt trigger
Correct Answer : 1000 MΩ
Correct Answer : Common collector
Correct Answer : current source bias is used
Correct Answer : low gain-bandwidth product
Correct Answer : bypass capacitor
Correct Answer : less sensitive to changes in input voltage
Correct Answer : increase the speed of response
Correct Answer : Ac emitter voltage
Correct Answer : two CB stages in cascade
Correct Answer : positive half cycle will be elongated and negative half cycle will be compressed
Correct Answer : current to voltage converter
Correct Answer : cut off clipping
Correct Answer : less than that of single stage amplifier
Correct Answer : 180° out of phase with the input signal
Correct Answer : high pass amplifiers
Correct Answer : 3N
Correct Answer : β
Correct Answer : at zero frequency
Correct Answer : high
Correct Answer : base, emitter and collector respectively are -8 V, 7.3 V and -5 V
Correct Answer : offers a low resistance
Correct Answer : its frequency of oscillation remains almost constant
Correct Answer : how successfully the active device converts D.C. power to A.C. signal power
Correct Answer : almost constant
Correct Answer : high input and output impedance
Correct Answer : source terminal is earthed during transit
Correct Answer : Regulation : Efficiency
Correct Answer : Cascade amplifier
Correct Answer : MOSFET and IGEFT
Correct Answer : gives constant frequency of oscillations
Correct Answer : class B output stage
Correct Answer : emitter junction is reverse biased and collector junction is forward biased
Correct Answer : intermodulation distortion
Correct Answer : switching
Correct Answer : a tapped inductor for inductive feedback
Correct Answer : delay between the instance at which hold command is initiated and the instance at which O/P starts tracking I/P
Correct Answer : positive clamper
Correct Answer : ferrite core
Correct Answer : poor phase response
Correct Answer : Q point must lie on both dc and ac load lines
Correct Answer : a diode with two electrodes
Correct Answer : resistance
Correct Answer : Both (A) and (B)
Correct Answer : both terminals
Correct Answer : Source follower
Correct Answer : has the lowest value
Correct Answer : Emitter follower
Correct Answer : no signal is applied to the input
Correct Answer : loop gain of the circuit must be equal to unity
Correct Answer : 0.0065 pF
Correct Answer : 0°
Correct Answer : independent of the quiescent point
Correct Answer : almost horizontal
Correct Answer : positive clipping of collector current
Correct Answer : reverse biased
Correct Answer : both voltage gain and bandwidth
Correct Answer : +1%
Correct Answer : maximum power transfer
Correct Answer : its reactance is small for the lowest frequency in the input and output
Correct Answer : at the centre of ac load line
Correct Answer : ac collector voltage to ac base voltage
Correct Answer : depletion mode only