Correct Answer : Equivalent voltage or current source
Correct Answer : Linear responses only
Correct Answer : Both (B) and (C)
Correct Answer : the degree of numerator and denominator are equal
Explanation : If degrees of numerator and denominator were unequal, a pole or zero can be removed. Such a function cannot be a minimum function. Therefore degrees of numerator and denominator must be equal.
Correct Answer : Weber/Ampere
Correct Answer : has to be increased
Explanation : For overdamping R is more.
Correct Answer : 975 Hz
Explanation : Maximum voltage across capacitance occurs at a frequency slightly less than resonant frequency.
Correct Answer : 529 Ω
Explanation :
Correct Answer : 7 volts source in series with 2.4 Ω resistor
Explaination :
Correct Answer : the polarity of voltage across R during discharging is opposite to that during charging
Explanation : Direction of current during discharging is opposite to that during charging.
Correct Answer : 20 mH
Correct Answer : 10 Ω
Explaination : At half power frequency the circuit impedance is 2 times resistance.
Correct Answer : 0.5 mH
Correct Answer : 30 μC and 60 μC respectively
Q1 = 1 x 10-6 x 30 = 30 μC, Q2 = 2 x 10-6 x 30 = 60 μC.
Correct Answer : temperature alarm circuit
Explanation : The resistance of a thermistor decreases with increases in temperature. It is used to monitor hot spot temperature of electric machines.
Correct Answer : increases
Explanation : Specific gravity of electrolyte is highest when battery is fully charged and is lowest when discharged.
Correct Answer : mmf for iron and air gap are equal
Correct Answer : 0.3 V
Correct Answer : 20 V and 10 V
Explaination : Charge will be the same. Since Q = C V voltage will be inversely proportional to Q. Hence 20 V and 10 V.
Correct Answer : W1 < W2 < W3
Explaination : Energy dissipated by the plate with lowest resistance is maximum.
Correct Answer : 109 ∠ - 36.6° V
Explaination : 50Ð0 = 50 + j 0.75∠-60° = 37.5 - j 64.95Sum = (50 + 37.5) - j 64.95 = 87.5 - j 64.95 = 109∠-36.6°
Correct Answer : 0.18 J
Correct Answer : R and C in series
Explaination : As f increases impedance increases and current decreases in RL circuit.
Correct Answer : cannot be higher than source voltage
Explanation : A practical voltage source has some source resistance.Because of voltage drop across source resistance, terminal voltage cannot be higher than source voltage.If current is zero, terminal voltage and source voltage are equal.
Correct Answer : t = ∞
i = 10 (1 - e-t). It reaches steadily state value at t = ∞
Correct Answer : a voltage source of 16 V in series with 4 ohm resistance
Explaination : The parallel combination of 20 Ω and 5 Ω is 4 Ω. Therefore, strength of current source is 4 x 4 = 16 A and source resistance is 4 ohms.
Correct Answer : lags, 90°
Explanation : In inductive circuit current lags the voltage by 90°.
Correct Answer : is more than 50% of total energy
Explaination : The parallel combination of 30 Ω and 20 Ω is 12 Ω. Since 12 Ω and 10 Ω are in parallel, the 10 ohm plate draws more than 50% current and dissipates more than 50% energy.
Correct Answer : 333.3 W
Correct Answer : 4∠32°
Correct Answer : 10 Ω
Correct Answer : very small as compared to speed of light
Explanation : Drift velocity of electrons is very small.
Correct Answer : rms values of the two waves are equal
Explanation : Since peak values are equal, their rms values are equal irrespective of phase difference.
Correct Answer : 0
Explanation : Voltage across a capacitor cannot change instantaneously.
Correct Answer : 0.03 F
Explanation : Q = CV or 0.15 = C(5) or C = 0.03 F.
Correct Answer : 0 A and 10 V
Explanation : When the capacitor is fully charged, i = 0 and voltage across capacitor is equal to battery voltage.
Correct Answer : is 6 Ω
Explaination : Current supplied by battery = 10/10 = 1A. Therefore current through 2Ω resistance is 11 A. Voltage across R = 48 - 10 - 11 x 2 = 16 V.
Correct Answer : 1000 rad/sec
Correct Answer : will always be equal to or less than 0.5 A
Correct Answer : the line current and increases p.f.
Explanation : Capacitor is used to improve (increase) p.f. Therefore, line current is decreased for the same active power.
Correct Answer : Active power cannot be more than apparent power
Explanation : Active and apparent power are equal for resistive circuit. Otherwise active power is less than apparent power.
Correct Answer : 10 mH
Correct Answer : will decrease
Explanation : μr for air is 1 while μr for iron is more than 1.
Correct Answer : 4 A
Correct Answer : capacitance
Explaination : Charge across capacitance increases linearly. Since capacitance is constant, voltage increases linearly.
Correct Answer : 11 W
Correct Answer : 16∠14°
Correct Answer : 160 mH
Explaination : Since diameter is halved, area of cross-section is one-fourth. The number of turns becomes four times. Inductance = μ N2.
Correct Answer : 7.07 A
Correct Answer : s = -1 and s = -3
Explanation : In RC functions poles and zeros are interlaced.
Correct Answer : 750 V
Explanation : Voltage across inductance at resonance = QV = 7.5 X 100 V.
Correct Answer : decreases
Explanation : It at is temperature coefficient at t°C and a0 is temperature coefficient at 0°C.
Correct Answer : R/16
Explaination : Since diameter is double, area of cross-section is four times and length is one-fourth.
Correct Answer : joule/coulomb
Explanation : Dynamic resistance = L/RC and increases as C is decreased.
Correct Answer : 3 Ω
Correct Answer : more than 20 Ω but less than 40 Ω
Correct Answer : 40 Ω
Correct Answer : 5 Ω
Explaination : The parallel combination of 3, 5 and 4 ohm is short-circuited. Therefore their net resistance is zero.
Correct Answer : 4.5 H
Correct Answer : a necessary condition
Explaination : H(s) must possess two more properties if it is positive real.
Correct Answer : 0.6 T or less than 0.6 T
Explanation : Since μr for silicon steel is more than that of cast iron, flux density will be more than 0.6 T.
Correct Answer : v2 is leading v1 by 75°
Explaination : v1 = 100 sin (ωt + 15°) and v2 = 60 cos ωt = 60 sin (ωt + 90°). Hence, v2 is leading v1 by (90 - 15) = 75°.
Correct Answer : RC impedance function
Explanation : RL admittance function and RC impedance function have similar forms.
Correct Answer : are bulky and unsuitable for miniaturization
Explanation : Active filters consist of electronic components and have very small size.
Correct Answer : 5 Ω
Correct Answer : O'Brune
Explanation : The procedure is called Brune's synthesis.
Correct Answer : 1 and 3
Explaination : A minimum of 2 wattmeters is required to measure 3 phase power. Of course power can be measured by putting one wattmeter in each phase.
Correct Answer : The real parts of all poles and zeros must be negative or zero
Explanation : It is a necessary condition for response to be stable.
Correct Answer : the current leads the voltage by about 6°
Explaination : In RC circuit the current leads the voltage.
Correct Answer : current will be the same but current density will be different at different cross-sections.
Explanation : Current density = current/area of cross-section. Same current throughout the conductor.Since, area of cross-section is non-uniform, current density will be different at different cross-sections.
Correct Answer : 2.67 kWh
Explanation : Since 25% of input is lost, 0.75 Input = 2 or input = 2/0.75 = 2.67 kWh
Correct Answer : diameter of cable
Explanation : Current rating depends only on area of cross-section and hence diameter.
Correct Answer : 1 and 0
Explanation : Power factor is maximum and equal to 1 for purely resistive load. Power factor is minimum and equal to zero for purely reactive load.
Correct Answer : 500 Ω
Explaination : At parallel resonance circuit impedance = L/RC
Correct Answer : more
Explanation : To avoid mutually coupled inductors, more elements are needed.
Correct Answer : 35.35 V
Explanation : Peak value = 50 V, rms value = 50 / √2 = 35.35 V.
Correct Answer : √2 x 230V
Explanation : Peak voltage rating = √2 (rms voltage rating).
Correct Answer : Both A and R are true and R is correct explanation of A
Explaination : A high value of time constant results in slow rise of current.
Explaination : Dynamic resistance = L/RC
Correct Answer : 2000 Hz
Explanation : Resonant frequency of arms in constant k band pass filter =
Correct Answer : 0.225 J
Explaination : Energy = 0.5 LI2
Correct Answer : Either R and L or R and C in series
Explanation : Thevenin's impedance may be inductive or capacitive.
Correct Answer : 0 V
Correct Answer : 0.2 rad/sec
Correct Answer : 0.67
Correct Answer : L and C
Explanation : In network having only L and C, poles and zeros of driving point function are simple and alternate on jω axis.
Correct Answer : 0.56 mA
Correct Answer : an inductance of value K
Explanation : Admittance of a capacitance K is Ks.
Correct Answer : four times
Explanation : Since diameter is doubled, area of cross-section becomes four times. Current carrying capacity is proportional to area of cross-section.
Correct Answer : 92.4 V
Explanation : RMS value =
Correct Answer : 10800 W
Correct Answer : 900 C
Explanation : When axis are perpendicular then there is no mutual coupling.
Correct Answer : zero
Explaination : Z0T = R0(1 - f2 / fc2)0.5. At f = f0. Z0T = 0.
Correct Answer : A(ω) = Cω2, Φ (ω) = kω
Correct Answer : the current at the instant of switching may be less than or equal to operating current
Explanation : Resistance at the time of switching on is minimum and increases due to increase of temperature.
Correct Answer : 300 mH
Explanation : M = k√L1L2, L1 = L2 = L, M = kL. Total inductance = L1 + L2 + 2M = 2L + 2kL = 900 mH or L(2 + 2 x 0.5) = 900 or L = 300 mH.
Correct Answer : both at the time of starting and during working
Explanation : At the time of starting the choke provides a high voltage. During working there is voltage drop across choke so that lamp gets proper voltage.
Correct Answer : VL = VC
Explaination : At resonance XL = XC. Therefore IXL = IXC or VL = VC.
Correct Answer : the numerator of Z(s) is one degree higher than denominator
Explanation : If numerator is one degree higher than denominator z(s) tends to infinity as s tends to infinity.
Correct Answer : about 3500 kcal/kg
Correct Answer : 28.28 Ω
Correct Answer : A is true but R is false
Explaination : Maximum power transfer theorem is applicable to ac circuits.
Correct Answer : RC circuit
Explanation : In RL circuits phase angle of Z is positive.
Correct Answer : 1 A
Correct Answer : 90°
Correct Answer : a parabola
Explanation : Integral of unit step function is ramp and integral of ramp is doublet.
Correct Answer : more than 100 Ω
Correct Answer : 1 kilowatt-hour
Explanation : Consumers are charged on the basis of kWh of energy used.
Correct Answer : 36 mH
Correct Answer : 27.386 mA
Explanation : 0.75 = I2 x 1 x 1000 or I = 27.386 mA.
Correct Answer : 250 vars
Correct Answer : 100 Hz
Correct Answer : 0.0035
Correct Answer : direction of current through the resistor
Explanation : Polarity of voltage depends only on direction of current and nothing else.
Correct Answer : the waveshape of voltage across resistance will be sawtooth
Explanation : V = IR and P = I2R. Therefore, waveshape of V is the same as that of I but waveshape of P is different.
Correct Answer : (R, Y, Z) or (R, X, Z)
Explanation : Admittance triangle depicts admittance Y and its components G and B.
Explanation : Inductance does not allow the current to increase instantaneously.
Correct Answer : is less than 4 A
Correct Answer : 5 mH
Correct Answer : 1 + e -at
Correct Answer : 125 W
Explaination : P = I2R = 52(5) = 125 W.
Correct Answer : 10A
Explanation : The average of sinusoid over 1 cycle is zero.
Correct Answer : A is false but R is true
Explaination : The current may lead or lag the voltage depending on values of L and C.
Correct Answer : RC admittance function
Explanation : RL impedance function and RC admittance have similar forms.
Correct Answer : critically damped
Correct Answer : 30 ∠0°.
Explaination : Z = 30 + j (30 - 30) = 30∠0 Ω.
Correct Answer : if line to line voltages are balanced or unbalanced
Explanation : Zero sequence component of line to line voltage is always zero irrespective of degree of unbalance.
Correct Answer : v-i plot is not a straight line
Explanation : In a non-linear resistance v-i graph is a curve.
Correct Answer : less than 3 A
Explanation : The current will be less than 3 A. It may not be 1.5 A because other resistance in the circuit also affect the value of current.
Correct Answer : 2
Explanation : In dual, node pairs and meshes are interchanged b = (n - 1) + l => l = 2.
Correct Answer : 0.4
Correct Answer : must have either negative or zero real part
Explanation : Only then it is possible to synthesize by R, L and C elements.
Correct Answer : voltage and current
Correct Answer : more than battery voltage
Explanation : The charger has to supply current to battery for charging. This is possible only if voltage of charger is more than that of battery.
Correct Answer : communication circuits
Explanation : In power and distribution circuits efficiency has to be very high.
Correct Answer : 50 V
Explanation : |V| = IXL - IXC.
Correct Answer : all poles and zeros are simple and lie on jω axis only
Explanation : Only then the network has only L and C. If poles and zeros are not on jω axis, resistance will be there.
Correct Answer : sine terms only
Explanation : Since f(-t) = -f(t) only sine terms exist.
Correct Answer : 2.236 ∠243.43°
Explaination : A - B = - 1 - j2 = 2.236∠243.43°.
Correct Answer : 10 μF
Correct Answer : it is necessary to find new Thevenin's circuit
Explanation : Thevenin's equivalent circuit with respect to particular terminals only.
Correct Answer : 100 ∠90° V
Explaination : Voltage across inductance = QV and leads the applied voltage.
Correct Answer : 360°
Explaination : Sum of phasors is maximum if they are in phase and 360° = 0.
Correct Answer : 22 Ω
Correct Answer : all voltages and current
Explanation : KCL and KVL are valid for voltages and currents of all wave shapes during transient as well as steady state conductions.