Correct Answer : 873 RPM
Explanation :
Speed of Alternator, N = 1200 RPM
Number of Alternator poles, P = 6
Supply frequency, f = PN/120 = 60 Hz
Hence, for number of 8 poles in Induction motor, the synchronous speed or speed of rotating field is: Ns = 120f/P = 900 RPM
Let Nr is actual speed of motor.
Thus, Percentage Slip, S % = ((Ns – Nr)/Ns) x 100
Substituting the values, we get: Nr = Ns (1-S/100) = 873 RPM.