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Electronics and Communication Engineering (ECE) : Electromagnetic Field Theory - Quiz(MCQ)
Find the current density of a material with resistivity 20 units and electric field intensity 2000 units.
A)
100
B)
200
C)
300
D)
400

Correct Answer : Option (A) :   100


Explanation : The current density is given by J = σ E, where σ is the conductivity. Thus resistivity ρ = 1/σ. J = E/ρ = 2000/20 = 100 units.

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