Find the electric potential for an electric field 3units at a distance of 2m.

Electronics and Communication Engineering (ECE) : Electromagnetic Field Theory - Quiz(MCQ)

3/2

Correct Answer : Option (B) : 6

Explanation : The electric field intensity is the ratio of electric potential to the distance. E = V/d. To get V = E X d = 3 X 2 = 6units.

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