The conductivity of a material with current density 1 unit and electric field 200 Î¼V is

Electronics and Communication Engineering (ECE) : Electromagnetic Field Theory - Quiz(MCQ)

2000

3000

4000

5000

Correct Answer : Option (D) : 5000

Explanation : The current density is given by, J = σE. To find conductivity, σ = J/E = 1/200 X 10^-6 = 5000.

Recently Updated in Electromagnetic Field Theory Questions

Radiation intensity in a given direction is the

Energy radiated per square metre

Power radiated per square metre

Power radiated per unit solid angle in that direction

None of the above

Correct Answer : Power radiated per unit solid angle in that direction

Which of the following impedance inversion is obtained?

Balun transformer

A quarter wave line

Short-circuited stub

A half wave line

Correct Answer : A quarter wave line

The wave in wave guide has

Larger frequency than in the free space

Diminishing wavelength than in the free space

Group velocity inversely proportional to wavelength

Larger wavelength than in the free space

Correct Answer : Larger wavelength than in the free space