Correct Answer : Option (D) : 2
Explanation :
A B-tree of order m contains n records and each contains b records on average then the tree will have about n/b leaves. If we split k nodes along the path from leaves then
k<=1+logm/2 [n/b]
here n=10,b=3,m=4 so
k<=1+log4/2 [n/b]
k<=1+log2 4
k<= 1+2
k<=3