You have an IP address of 172.16.13.5 with a 255.255.255.128 subnet mask. What is your class of address, subnet address, and broadcast address?

Networking - Quiz(MCQ)

Class A, Subnet 172.16.13.0, Broadcast address 172.16.13.127

Class B, Subnet 172.16.13.0, Broadcast address 172.16.13.255

Class B, Subnet 172.16.0.0, Broadcast address 172.16.255.255

Class B, Subnet 172.16.13.0, Broadcast address 172.16.13.127

Correct Answer : Option (D) : Class B, Subnet 172.16.13.0, Broadcast address 172.16.13.127

Explanation : We know that the prefix 172 lies in class B (128 to 191) of IPv4 addresses. From the subnet mask, we get that the class is divided into 2 subnets: 172.16.13.0 to 172.16.13.127 and 172.16.13.128 to 172.16.13.255. The IP 172.16.13.5 lies in the first subnet. So the starting address 172.16.13.0 is the subnet address and last address 172.16.13.127 is the broadcast address.

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Q .

EIGRP uses the ____________ algorithm for finding shortest path.

DUAL

SPF

Linkstat

Djikstra’s

Correct Answer : Option (A) : DUAL

Explanation : EIGRP uses the DUAL algorithm for finding shortest path. DUAL stands for diffusing update algorithm and it is used to prevent routing loops by recalculating routes globally.

Q .

Administrative distance for external EIGRP route is _______

100

170

135

190

Correct Answer : Option (B) : 170

Explanation : Routers use the metric of administrative distance to select the best path when there are different routes to the same destination from two different routing protocols as it is a measure of reliability of routing protocols. Administrative distance for external EIGRP is 170.