Let’s consider the population of men who have normally distributed weights, with a mean of 60 kg and a standard deviation of 10 kg, and the probability needs to be found out.
If one single man is selected, the weight is greater than 65 kg, but if 40 men are selected, then the mean weight is far more than 65 kg.
The solution to this can be as shown below :
Z = (x − µ) / ? = (65 − 60) / 10 = 0.5
For a normal distribution P(Z > 0.5) = 0.409
Z = (65 − 60) / 5 = 1
P(Z > 1) = 0.090?
