General Knowledge(GK) (or) General Awareness

Welcome to the General Knowledge Section of Free Time Learning. As we are aware General Knowledge (GK) is a very important area in all the competitive exams held in the country. Nowadays, a good knowledge of general awareness is very important in clearing any competitive and government recruitment examinations.

These General Knowledge Question are very important and usefull to UPSC, IAS/PCS, UPPSC, IBPS, SBI, RBI, SSC, CGL, Railway, APPSC, TSPSC, KPSC, TNPSC, TPSC, UPPSC, MPSC, RPSC, BPSC, MPPSC, UKPSC, MPSC, and other competitive exams.

1 .

MODULA is a

Machine language

Assembly language

Programming language

Low-level language

Correct Answer : Programming language

The Modula programming language is a descendant of the Pascal language. It was developed in Switzerland, at ETH Zurich, in the mid-1970s by Niklaus Wirth, the same person who designed Pascal.

The main innovation of Modula over Pascal is a module system, used for grouping sets of related declarations into program units; hence the name Modula. The language is defined in a report by Wirth called Modula. A language for modular multiprogramming published 1976.

Published On : June 18, 2021

2 .

The term MIPS refers to

millions of instructions per second

multiple instructions per second

millions input processor set

megabytes of instructions per seconds

Correct Answer : millions of instructions per second

The term MIPS refers to millions of instructions per second. MIPS. Stands for "Million Instructions Per Second." It is a method of measuring the raw speed of a computer's processor.

Published On : June 18, 2021

3 .

A database management system based on the concept of ownership is

Network database system

Network license system

Network topology

Network layer

Correct Answer : Network database system

Published On : June 18, 2021

4 .

A device that stores one item of information is

Block Compaction

Memory element

Memory guard

None of the above

Correct Answer : Memory element

Published On : June 18, 2021

5 .

How many operations per second can perform by a modern fast mainframe digital computer.

1000

100,000

10,00,000

1,00,00,00,000

Correct Answer : 1,00,00,00,000

Published On : June 18, 2021

6 .

What is the number of bits needed for an address in a 4 K memory?

Correct Answer : 12

12 bits needed for an address in a 4K memory

Likewise, you need 20 bits to address every byte in a megabyte, and 30 bits to address every byte in a gigabyte. 232 = 4294967296, which is the number of bytes in 4 gigabytes, so you need a 32 bit address for 4 GB of memory.

As I mentioned before, it's the size of a machine word. Machine word is the amount of memory CPU uses to hold numbers (in RAM, cache or internal registers). 32-bit CPU uses 32 bits (4 bytes) to hold numbers. Memory addresses are numbers too, so on a 32-bit CPU the memory address consists of 32 bits.

Published On : June 18, 2021

7 .

A storage area used to store data to compensate for the difference in speed at which the different units can handle data is

Memory

Buffer

Address

Accumulator

Correct Answer : Buffer

A buffer, also called buffer memory, is a portion of a computer's memory that is set aside as a temporary holding place for data that is being sent to or received from an external device, such as a hard disk drive (HDD), keyboard or printer.

Published On : June 18, 2021

8 .

A notation for defining the form and structure of data is known as

Data definition language

Data description language

Binary language

Data channel

Correct Answer : Data definition language

A data definition language or data description language (DDL) is a syntax similar to a computer programming language for defining data structures, especially database schemas.

Published On : June 18, 2021

9 .

Control of computer system or subsystem operation by an operator who may intervene at arbitrary times is

Shift register

Manual control

Mapping

None of the above

Correct Answer : Manual control

Published On : June 18, 2021

10 .

The data bus in 8080A/8085 microprocessor is a group of

eight unidirectional lines that are used for I/O devices

eight lines used to transfer data among the registers

sixteen bidirectional lines that are used for data transfer between the microprocessor and memory

eight bidirectional lines that are used to transfer 8 bits between the microprocessor and its I/O and memory

Correct Answer : eight bidirectional lines that are used to transfer 8 bits between the microprocessor and its I/O and memory

The data bus in 8080A/8085 microprocessor is a group of eight bidirectional lines that are used to transfer 8 bits between the microprocessor and its I/O and memory.

Diagram to represent bus organization system of 8085 Microprocessor. It is a group of conducting wires which carries address only.Address bus is unidirectional because data flow in one direction, from microprocessor to memory or from microprocessor to Input/output devices

It is unidirectional.In Intel 8085 microprocessor, Address bus was of 16 bits. This means that Microprocessor 8085 can transfer maximum 16 bit address which means it can address 65,536 different memory locations. This bus is multiplexed with 8 bit data bus.

An address bus is a computer bus architecture used to transfer data between devices that are identified by the hardware address of the physical memory (the physical address), which is stored in the form of binary numbers to enable the data bus to access memory storage.

Published On : June 18, 2021